Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.What is the difference between the compound interest and the simple interest on ₹3200 at 15% per year for 2 years (in ₹)?
- 2.A scooter is worth ₹16200. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
- 3.What amount will ₹40100 grow to in 2 years at 10% per year compound interest (in ₹)?
- 4.A town has 12500 people. The population grows by 8% every year. What will the population be after 2 years?
- 5.Find the compound interest on ₹11600 at 8% per year for 1 year, compounded every year (in ₹).
- 6.Find the compound interest on ₹30200 at 20% per year for 2 years, compounded every year (in ₹).
- 7.Find the compound interest on ₹26200 at 10% per year for 1 year, compounded every year (in ₹).
- 8.Find the compound interest on ₹53600 at 25% per year for 2 years, compounded every year (in ₹).
- 9.What amount will ₹33600 grow to in 1 year at 12% per year compound interest (in ₹)?
- 10.What is the difference between the compound interest and the simple interest on ₹20000 at 12% per year for 2 years (in ₹)?
- 11.Find the compound interest on ₹40000 at 15% per year for 3 years, compounded every year (in ₹).
- 12.A scooter is worth ₹45000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
- 13.Find the compound interest on ₹20500 at 20% per year for 1 year, compounded every year (in ₹).
- 14.A town has 26400 people. The population grows by 15% every year. What will the population be after 1 year?
- 15.Find the compound interest on ₹10000 at 4% per year for 2 years, compounded every year (in ₹).
- 16.What amount will ₹24000 grow to in 3 years at 15% per year compound interest (in ₹)?
- 17.What amount will ₹17100 grow to in 1 year at 10% per year compound interest (in ₹)?
- 18.Find the compound interest on ₹32800 at 20% per year for 2 years, compounded every year (in ₹).
- 19.What is the difference between the compound interest and the simple interest on ₹12000 at 5% per year for 2 years (in ₹)?
- 20.What amount will ₹8000 grow to in 1 year at 15% per year compound interest (in ₹)?
- 21.What amount will ₹16000 grow to in 3 years at 20% per year compound interest (in ₹)?
- 22.A town has 4000 people. The population grows by 10% every year. What will the population be after 3 years?
- 23.What amount will ₹18300 grow to in 2 years at 10% per year compound interest (in ₹)?
- 24.What is the difference between the compound interest and the simple interest on ₹52500 at 12% per year for 2 years (in ₹)?
- 25.Find the compound interest on ₹3000 at 20% per year for 3 years, compounded every year (in ₹).
- 26.Find the compound interest on ₹38400 at 25% per year for 2 years, compounded every year (in ₹).
- 27.What is the difference between the compound interest and the simple interest on ₹27600 at 25% per year for 2 years (in ₹)?
- 28.What is the difference between the compound interest and the simple interest on ₹57500 at 4% per year for 2 years (in ₹)?
- 29.Find the compound interest on ₹58000 at 20% per year for 3 years, compounded every year (in ₹).
- 30.What amount will ₹15200 grow to in 2 years at 5% per year compound interest (in ₹)?
- 31.What amount will ₹2000 grow to in 1 year at 12% per year compound interest (in ₹)?
- 32.What amount will ₹31000 grow to in 3 years at 10% per year compound interest (in ₹)?
- 33.What amount will ₹4600 grow to in 1 year at 15% per year compound interest (in ₹)?
- 34.Find the compound interest on ₹57500 at 5% per year for 1 year, compounded every year (in ₹).
- 35.What amount will ₹40200 grow to in 2 years at 10% per year compound interest (in ₹)?
- 36.What amount will ₹8000 grow to in 2 years at 15% per year compound interest (in ₹)?
- 37.A town has 44400 people. The population grows by 15% every year. What will the population be after 2 years?
- 38.Find the compound interest on ₹14900 at 12% per year for 1 year, compounded every year (in ₹).
- 39.Find the compound interest on ₹22000 at 25% per year for 2 years, compounded every year (in ₹).
- 40.Find the compound interest on ₹24000 at 15% per year for 3 years, compounded every year (in ₹).
Answer key
- 72
- 13122
- 48521
- 14580
- 928
- 13288
- 2620
- 30150
- 37632
- 288
- 20835
- 38088
- 4100
- 30360
- 816
- 36501
- 18810
- 14432
- 30
- 9200
- 27648
- 5324
- 22143
- 756
- 2184
- 21600
- 1725
- 92
- 42224
- 16758
- 2240
- 41261
- 5290
- 2875
- 48642
- 10580
- 58719
- 1788
- 12375
- 12501
Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets