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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 105 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

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  1. 1.A town has 33900 people. The population grows by 4% every year. What will the population be after 1 year?
  2. 2.What amount will ₹46700 grow to in 1 year at 10% per year compound interest (in ₹)?
  3. 3.What amount will ₹10000 grow to in 2 years at 12% per year compound interest (in ₹)?
  4. 4.Find the compound interest on ₹5000 at 12% per year for 2 years, compounded every year (in ₹).
  5. 5.Find the compound interest on ₹11200 at 25% per year for 3 years, compounded every year (in ₹).
  6. 6.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).
  7. 7.Find the compound interest on ₹8000 at 15% per year for 3 years, compounded every year (in ₹).
  8. 8.What amount will ₹7000 grow to in 1 year at 25% per year compound interest (in ₹)?
  9. 9.Find the compound interest on ₹5000 at 8% per year for 1 year, compounded every year (in ₹).
  10. 10.Find the compound interest on ₹5000 at 8% per year for 2 years, compounded every year (in ₹).
  11. 11.What is the difference between the compound interest and the simple interest on ₹17500 at 4% per year for 2 years (in ₹)?
  12. 12.Find the compound interest on ₹27500 at 4% per year for 2 years, compounded every year (in ₹).
  13. 13.Find the compound interest on ₹54900 at 20% per year for 1 year, compounded every year (in ₹).
  14. 14.What amount will ₹17500 grow to in 3 years at 20% per year compound interest (in ₹)?
  15. 15.Find the compound interest on ₹10400 at 15% per year for 2 years, compounded every year (in ₹).
  16. 16.A town has 56000 people. The population grows by 5% every year. What will the population be after 3 years?
  17. 17.A town has 26000 people. The population grows by 10% every year. What will the population be after 3 years?
  18. 18.A town has 56000 people. The population grows by 10% every year. What will the population be after 3 years?
  19. 19.What amount will ₹19300 grow to in 1 year at 25% per year compound interest (in ₹)?
  20. 20.What is the difference between the compound interest and the simple interest on ₹57100 at 10% per year for 2 years (in ₹)?
  21. 21.Find the compound interest on ₹27000 at 20% per year for 3 years, compounded every year (in ₹).
  22. 22.What amount will ₹33700 grow to in 1 year at 12% per year compound interest (in ₹)?
  23. 23.A town has 46400 people. The population grows by 15% every year. What will the population be after 1 year?
  24. 24.What amount will ₹28400 grow to in 2 years at 15% per year compound interest (in ₹)?
  25. 25.A scooter is worth ₹33600. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
  26. 26.What is the difference between the compound interest and the simple interest on ₹2500 at 8% per year for 2 years (in ₹)?
  27. 27.A scooter is worth ₹26000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
  28. 28.A scooter is worth ₹14500. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
  29. 29.Find the compound interest on ₹32000 at 10% per year for 3 years, compounded every year (in ₹).
  30. 30.A scooter is worth ₹15600. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
  31. 31.Find the compound interest on ₹47700 at 15% per year for 1 year, compounded every year (in ₹).
  32. 32.A scooter is worth ₹21700. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
  33. 33.What is the difference between the compound interest and the simple interest on ₹57500 at 12% per year for 2 years (in ₹)?
  34. 34.What amount will ₹20000 grow to in 2 years at 4% per year compound interest (in ₹)?
  35. 35.A town has 14100 people. The population grows by 20% every year. What will the population be after 1 year?
  36. 36.Find the compound interest on ₹46900 at 10% per year for 2 years, compounded every year (in ₹).
  37. 37.What is the difference between the compound interest and the simple interest on ₹55200 at 15% per year for 2 years (in ₹)?
  38. 38.What is the difference between the compound interest and the simple interest on ₹20000 at 12% per year for 2 years (in ₹)?
  39. 39.What amount will ₹56000 grow to in 3 years at 5% per year compound interest (in ₹)?
  40. 40.Find the compound interest on ₹3800 at 10% per year for 2 years, compounded every year (in ₹).

Answer key

  1. 35256
  2. 51370
  3. 12544
  4. 1272
  5. 10675
  6. 6305
  7. 4167
  8. 8750
  9. 400
  10. 832
  11. 28
  12. 2244
  13. 10980
  14. 30240
  15. 3354
  16. 64827
  17. 34606
  18. 74536
  19. 24125
  20. 571
  21. 19656
  22. 37744
  23. 53360
  24. 37559
  25. 27216
  26. 16
  27. 18954
  28. 7424
  29. 10592
  30. 11271
  31. 7155
  32. 17577
  33. 828
  34. 21632
  35. 16920
  36. 9849
  37. 1242
  38. 288
  39. 64827
  40. 798

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