Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.Find the compound interest on ₹2500 at 4% per year for 2 years, compounded every year (in ₹).
- 2.What amount will ₹13000 grow to in 3 years at 20% per year compound interest (in ₹)?
- 3.A town has 56500 people. The population grows by 20% every year. What will the population be after 2 years?
- 4.What amount will ₹34000 grow to in 3 years at 10% per year compound interest (in ₹)?
- 5.A scooter is worth ₹17400. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
- 6.What amount will ₹14700 grow to in 1 year at 8% per year compound interest (in ₹)?
- 7.What is the difference between the compound interest and the simple interest on ₹46500 at 20% per year for 2 years (in ₹)?
- 8.What is the difference between the compound interest and the simple interest on ₹45000 at 8% per year for 2 years (in ₹)?
- 9.What amount will ₹42800 grow to in 2 years at 5% per year compound interest (in ₹)?
- 10.What amount will ₹33600 grow to in 2 years at 20% per year compound interest (in ₹)?
- 11.What amount will ₹60000 grow to in 2 years at 8% per year compound interest (in ₹)?
- 12.A town has 15600 people. The population grows by 15% every year. What will the population be after 2 years?
- 13.Find the compound interest on ₹43400 at 5% per year for 1 year, compounded every year (in ₹).
- 14.What amount will ₹11000 grow to in 2 years at 20% per year compound interest (in ₹)?
- 15.A scooter is worth ₹11900. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
- 16.What amount will ₹31200 grow to in 1 year at 20% per year compound interest (in ₹)?
- 17.What is the difference between the compound interest and the simple interest on ₹48300 at 10% per year for 2 years (in ₹)?
- 18.What amount will ₹8000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 19.What is the difference between the compound interest and the simple interest on ₹17500 at 8% per year for 2 years (in ₹)?
- 20.What amount will ₹40000 grow to in 3 years at 15% per year compound interest (in ₹)?
- 21.A scooter is worth ₹49000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
- 22.What amount will ₹28800 grow to in 2 years at 15% per year compound interest (in ₹)?
- 23.A scooter is worth ₹24800. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
- 24.What amount will ₹4300 grow to in 1 year at 12% per year compound interest (in ₹)?
- 25.A scooter is worth ₹14800. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
- 26.What is the difference between the compound interest and the simple interest on ₹23300 at 10% per year for 2 years (in ₹)?
- 27.Find the compound interest on ₹46700 at 10% per year for 2 years, compounded every year (in ₹).
- 28.What amount will ₹17700 grow to in 1 year at 10% per year compound interest (in ₹)?
- 29.A scooter is worth ₹8900. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
- 30.What amount will ₹32200 grow to in 2 years at 10% per year compound interest (in ₹)?
- 31.What is the difference between the compound interest and the simple interest on ₹10200 at 10% per year for 2 years (in ₹)?
- 32.Find the compound interest on ₹25600 at 25% per year for 3 years, compounded every year (in ₹).
- 33.Find the compound interest on ₹9400 at 15% per year for 1 year, compounded every year (in ₹).
- 34.Find the compound interest on ₹7500 at 12% per year for 2 years, compounded every year (in ₹).
- 35.What amount will ₹32500 grow to in 1 year at 10% per year compound interest (in ₹)?
- 36.What is the difference between the compound interest and the simple interest on ₹45300 at 10% per year for 2 years (in ₹)?
- 37.Find the compound interest on ₹15000 at 12% per year for 2 years, compounded every year (in ₹).
- 38.Find the compound interest on ₹36600 at 5% per year for 1 year, compounded every year (in ₹).
- 39.A town has 37500 people. The population grows by 4% every year. What will the population be after 2 years?
- 40.Find the compound interest on ₹32000 at 20% per year for 3 years, compounded every year (in ₹).
Answer key
- 204
- 22464
- 81360
- 45254
- 14790
- 15876
- 1860
- 288
- 47187
- 48384
- 69984
- 20631
- 2170
- 15840
- 11424
- 37440
- 483
- 9261
- 112
- 60835
- 35721
- 38088
- 22382
- 4816
- 10693
- 233
- 9807
- 19470
- 8455
- 38962
- 102
- 24400
- 1410
- 1908
- 35750
- 453
- 3816
- 1830
- 40560
- 23296
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