Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 113 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A scooter is worth ₹40000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
2. 2.What is the difference between the compound interest and the simple interest on ₹49200 at 10% per year for 2 years (in ₹)?
3. 3.What amount will ₹48400 grow to in 1 year at 10% per year compound interest (in ₹)?
4. 4.What is the difference between the compound interest and the simple interest on ₹25000 at 12% per year for 2 years (in ₹)?
5. 5.A town has 50900 people. The population grows by 15% every year. What will the population be after 1 year?
6. 6.Find the compound interest on ₹53500 at 20% per year for 3 years, compounded every year (in ₹).
7. 7.What is the difference between the compound interest and the simple interest on ₹20000 at 4% per year for 2 years (in ₹)?
8. 8.Find the compound interest on ₹15600 at 25% per year for 2 years, compounded every year (in ₹).
9. 9.What amount will ₹44800 grow to in 2 years at 15% per year compound interest (in ₹)?
10. 10.What is the difference between the compound interest and the simple interest on ₹10000 at 12% per year for 2 years (in ₹)?
11. 11.What amount will ₹53000 grow to in 3 years at 20% per year compound interest (in ₹)?
12. 12.A scooter is worth ₹30000. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
13. 13.What amount will ₹16000 grow to in 3 years at 25% per year compound interest (in ₹)?
14. 14.What is the difference between the compound interest and the simple interest on ₹33600 at 15% per year for 2 years (in ₹)?
15. 15.What is the difference between the compound interest and the simple interest on ₹3200 at 10% per year for 2 years (in ₹)?
16. 16.A scooter is worth ₹59200. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
17. 17.What is the difference between the compound interest and the simple interest on ₹35000 at 4% per year for 2 years (in ₹)?
18. 18.What is the difference between the compound interest and the simple interest on ₹56800 at 15% per year for 2 years (in ₹)?
19. 19.What is the difference between the compound interest and the simple interest on ₹15000 at 4% per year for 2 years (in ₹)?
20. 20.What is the difference between the compound interest and the simple interest on ₹34400 at 5% per year for 2 years (in ₹)?
21. 21.Find the compound interest on ₹26400 at 8% per year for 1 year, compounded every year (in ₹).
22. 22.What amount will ₹4800 grow to in 3 years at 25% per year compound interest (in ₹)?
23. 23.What amount will ₹20000 grow to in 2 years at 4% per year compound interest (in ₹)?
24. 24.A town has 49200 people. The population grows by 4% every year. What will the population be after 1 year?
25. 25.A scooter is worth ₹29600. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
26. 26.Find the compound interest on ₹49200 at 20% per year for 2 years, compounded every year (in ₹).
27. 27.Find the compound interest on ₹5300 at 10% per year for 1 year, compounded every year (in ₹).
28. 28.Find the compound interest on ₹12800 at 15% per year for 1 year, compounded every year (in ₹).
29. 29.Find the compound interest on ₹55600 at 5% per year for 1 year, compounded every year (in ₹).
30. 30.Find the compound interest on ₹21300 at 20% per year for 1 year, compounded every year (in ₹).
31. 31.A scooter is worth ₹12500. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
32. 32.What amount will ₹2500 grow to in 2 years at 8% per year compound interest (in ₹)?
33. 33.What is the difference between the compound interest and the simple interest on ₹37500 at 4% per year for 2 years (in ₹)?
34. 34.Find the compound interest on ₹55900 at 10% per year for 2 years, compounded every year (in ₹).
35. 35.A town has 32000 people. The population grows by 15% every year. What will the population be after 3 years?
36. 36.Find the compound interest on ₹37100 at 12% per year for 1 year, compounded every year (in ₹).
37. 37.What is the difference between the compound interest and the simple interest on ₹2500 at 12% per year for 2 years (in ₹)?
38. 38.What amount will ₹21000 grow to in 1 year at 10% per year compound interest (in ₹)?
39. 39.What is the difference between the compound interest and the simple interest on ₹41600 at 15% per year for 2 years (in ₹)?
40. 40.A town has 56000 people. The population grows by 5% every year. What will the population be after 1 year?

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