Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 116 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What amount will ₹7800 grow to in 1 year at 4% per year compound interest (in ₹)?
2. 2.Find the compound interest on ₹44700 at 10% per year for 2 years, compounded every year (in ₹).
3. 3.Find the compound interest on ₹2000 at 10% per year for 3 years, compounded every year (in ₹).
4. 4.What amount will ₹32500 grow to in 2 years at 12% per year compound interest (in ₹)?
5. 5.A town has 48000 people. The population grows by 5% every year. What will the population be after 3 years?
6. 6.Find the compound interest on ₹23300 at 12% per year for 1 year, compounded every year (in ₹).
7. 7.What is the difference between the compound interest and the simple interest on ₹30000 at 8% per year for 2 years (in ₹)?
8. 8.A scooter is worth ₹32800. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
9. 9.What is the difference between the compound interest and the simple interest on ₹52500 at 12% per year for 2 years (in ₹)?
10. 10.A scooter is worth ₹3900. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
11. 11.A town has 52500 people. The population grows by 12% every year. What will the population be after 2 years?
12. 12.What is the difference between the compound interest and the simple interest on ₹30400 at 15% per year for 2 years (in ₹)?
13. 13.What is the difference between the compound interest and the simple interest on ₹39900 at 20% per year for 2 years (in ₹)?
14. 14.Find the compound interest on ₹44500 at 5% per year for 1 year, compounded every year (in ₹).
15. 15.Find the compound interest on ₹15000 at 10% per year for 3 years, compounded every year (in ₹).
16. 16.A town has 54600 people. The population grows by 20% every year. What will the population be after 1 year?
17. 17.A town has 6700 people. The population grows by 10% every year. What will the population be after 2 years?
18. 18.Find the compound interest on ₹19200 at 5% per year for 2 years, compounded every year (in ₹).
19. 19.A town has 16000 people. The population grows by 15% every year. What will the population be after 3 years?
20. 20.What amount will ₹8000 grow to in 3 years at 5% per year compound interest (in ₹)?
21. 21.What is the difference between the compound interest and the simple interest on ₹53600 at 5% per year for 2 years (in ₹)?
22. 22.What is the difference between the compound interest and the simple interest on ₹27500 at 4% per year for 2 years (in ₹)?
23. 23.What amount will ₹59500 grow to in 1 year at 8% per year compound interest (in ₹)?
24. 24.What amount will ₹44400 grow to in 2 years at 15% per year compound interest (in ₹)?
25. 25.What is the difference between the compound interest and the simple interest on ₹60000 at 8% per year for 2 years (in ₹)?
26. 26.What amount will ₹45100 grow to in 1 year at 8% per year compound interest (in ₹)?
27. 27.What amount will ₹55000 grow to in 2 years at 12% per year compound interest (in ₹)?
28. 28.Find the compound interest on ₹22500 at 4% per year for 2 years, compounded every year (in ₹).
29. 29.Find the compound interest on ₹56000 at 5% per year for 3 years, compounded every year (in ₹).
30. 30.Find the compound interest on ₹19300 at 4% per year for 1 year, compounded every year (in ₹).
31. 31.A town has 40000 people. The population grows by 5% every year. What will the population be after 3 years?
32. 32.A town has 2500 people. The population grows by 12% every year. What will the population be after 2 years?
33. 33.Find the compound interest on ₹27500 at 8% per year for 2 years, compounded every year (in ₹).
34. 34.Find the compound interest on ₹25000 at 25% per year for 1 year, compounded every year (in ₹).
35. 35.A town has 7600 people. The population grows by 15% every year. What will the population be after 2 years?
36. 36.Find the compound interest on ₹41900 at 10% per year for 2 years, compounded every year (in ₹).
37. 37.A town has 12500 people. The population grows by 4% every year. What will the population be after 2 years?
38. 38.A town has 40000 people. The population grows by 8% every year. What will the population be after 2 years?
39. 39.What amount will ₹41000 grow to in 3 years at 10% per year compound interest (in ₹)?
40. 40.What is the difference between the compound interest and the simple interest on ₹17200 at 5% per year for 2 years (in ₹)?

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets