Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.A scooter is worth ₹16000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
- 2.A town has 38000 people. The population grows by 20% every year. What will the population be after 3 years?
- 3.What amount will ₹36800 grow to in 3 years at 25% per year compound interest (in ₹)?
- 4.A scooter is worth ₹40000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
- 5.A scooter is worth ₹57500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
- 6.Find the compound interest on ₹60000 at 15% per year for 2 years, compounded every year (in ₹).
- 7.What amount will ₹38800 grow to in 2 years at 25% per year compound interest (in ₹)?
- 8.What amount will ₹3700 grow to in 1 year at 25% per year compound interest (in ₹)?
- 9.What amount will ₹54900 grow to in 1 year at 5% per year compound interest (in ₹)?
- 10.Find the compound interest on ₹40000 at 8% per year for 2 years, compounded every year (in ₹).
- 11.What is the difference between the compound interest and the simple interest on ₹48200 at 20% per year for 2 years (in ₹)?
- 12.A scooter is worth ₹59400. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
- 13.A scooter is worth ₹56000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
- 14.What is the difference between the compound interest and the simple interest on ₹45200 at 20% per year for 2 years (in ₹)?
- 15.A town has 50000 people. The population grows by 4% every year. What will the population be after 1 year?
- 16.Find the compound interest on ₹24000 at 15% per year for 3 years, compounded every year (in ₹).
- 17.What is the difference between the compound interest and the simple interest on ₹11100 at 20% per year for 2 years (in ₹)?
- 18.A scooter is worth ₹4500. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
- 19.What amount will ₹5000 grow to in 2 years at 12% per year compound interest (in ₹)?
- 20.What is the difference between the compound interest and the simple interest on ₹52400 at 15% per year for 2 years (in ₹)?
- 21.What amount will ₹47000 grow to in 1 year at 15% per year compound interest (in ₹)?
- 22.A scooter is worth ₹13000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
- 23.What amount will ₹15000 grow to in 2 years at 12% per year compound interest (in ₹)?
- 24.What is the difference between the compound interest and the simple interest on ₹13600 at 15% per year for 2 years (in ₹)?
- 25.What amount will ₹53600 grow to in 2 years at 25% per year compound interest (in ₹)?
- 26.What amount will ₹11600 grow to in 2 years at 25% per year compound interest (in ₹)?
- 27.Find the compound interest on ₹18400 at 25% per year for 2 years, compounded every year (in ₹).
- 28.What amount will ₹5200 grow to in 1 year at 12% per year compound interest (in ₹)?
- 29.What is the difference between the compound interest and the simple interest on ₹29400 at 10% per year for 2 years (in ₹)?
- 30.A town has 58400 people. The population grows by 25% every year. What will the population be after 2 years?
- 31.A town has 22800 people. The population grows by 20% every year. What will the population be after 1 year?
- 32.What amount will ₹4200 grow to in 1 year at 5% per year compound interest (in ₹)?
- 33.A scooter is worth ₹24000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
- 34.A scooter is worth ₹8000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
- 35.What amount will ₹34300 grow to in 1 year at 8% per year compound interest (in ₹)?
- 36.What amount will ₹16000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 37.What amount will ₹9000 grow to in 3 years at 10% per year compound interest (in ₹)?
- 38.A town has 56000 people. The population grows by 15% every year. What will the population be after 3 years?
- 39.What amount will ₹4000 grow to in 2 years at 25% per year compound interest (in ₹)?
- 40.Find the compound interest on ₹41800 at 8% per year for 1 year, compounded every year (in ₹).
Answer key
- 13718
- 65664
- 71875
- 34295
- 48668
- 19350
- 60625
- 4625
- 57645
- 6656
- 1928
- 48114
- 48013
- 1808
- 52000
- 12501
- 444
- 2304
- 6272
- 1179
- 54050
- 9477
- 18816
- 306
- 83750
- 18125
- 10350
- 5824
- 294
- 91250
- 27360
- 4410
- 20577
- 6859
- 37044
- 18522
- 11979
- 85169
- 6250
- 3344
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