← Compound interest lesson New set →

Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 12 · 40 sums
TalentJR

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What is the difference between the compound interest and the simple interest on ₹44400 at 15% per year for 2 years (in ₹)?
  2. 2.Find the compound interest on ₹49700 at 20% per year for 2 years, compounded every year (in ₹).
  3. 3.A town has 4200 people. The population grows by 25% every year. What will the population be after 1 year?
  4. 4.What is the difference between the compound interest and the simple interest on ₹35000 at 12% per year for 2 years (in ₹)?
  5. 5.Find the compound interest on ₹27200 at 25% per year for 2 years, compounded every year (in ₹).
  6. 6.What is the difference between the compound interest and the simple interest on ₹15000 at 12% per year for 2 years (in ₹)?
  7. 7.A scooter is worth ₹32000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
  8. 8.Find the compound interest on ₹55100 at 20% per year for 1 year, compounded every year (in ₹).
  9. 9.What amount will ₹37600 grow to in 2 years at 25% per year compound interest (in ₹)?
  10. 10.What is the difference between the compound interest and the simple interest on ₹6400 at 20% per year for 2 years (in ₹)?
  11. 11.What amount will ₹53200 grow to in 1 year at 10% per year compound interest (in ₹)?
  12. 12.Find the compound interest on ₹41900 at 10% per year for 2 years, compounded every year (in ₹).
  13. 13.What is the difference between the compound interest and the simple interest on ₹18800 at 10% per year for 2 years (in ₹)?
  14. 14.Find the compound interest on ₹6800 at 5% per year for 2 years, compounded every year (in ₹).
  15. 15.Find the compound interest on ₹47500 at 8% per year for 2 years, compounded every year (in ₹).
  16. 16.A scooter is worth ₹11000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
  17. 17.What amount will ₹42500 grow to in 2 years at 8% per year compound interest (in ₹)?
  18. 18.Find the compound interest on ₹16000 at 20% per year for 3 years, compounded every year (in ₹).
  19. 19.Find the compound interest on ₹2500 at 8% per year for 2 years, compounded every year (in ₹).
  20. 20.What is the difference between the compound interest and the simple interest on ₹5200 at 20% per year for 2 years (in ₹)?
  21. 21.What amount will ₹6400 grow to in 2 years at 15% per year compound interest (in ₹)?
  22. 22.What is the difference between the compound interest and the simple interest on ₹13600 at 10% per year for 2 years (in ₹)?
  23. 23.What is the difference between the compound interest and the simple interest on ₹2800 at 15% per year for 2 years (in ₹)?
  24. 24.What amount will ₹47600 grow to in 1 year at 20% per year compound interest (in ₹)?
  25. 25.What is the difference between the compound interest and the simple interest on ₹16000 at 15% per year for 2 years (in ₹)?
  26. 26.What is the difference between the compound interest and the simple interest on ₹5900 at 10% per year for 2 years (in ₹)?
  27. 27.What amount will ₹26000 grow to in 2 years at 5% per year compound interest (in ₹)?
  28. 28.What is the difference between the compound interest and the simple interest on ₹30000 at 4% per year for 2 years (in ₹)?
  29. 29.Find the compound interest on ₹40800 at 5% per year for 2 years, compounded every year (in ₹).
  30. 30.A scooter is worth ₹43700. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
  31. 31.What is the difference between the compound interest and the simple interest on ₹52800 at 5% per year for 2 years (in ₹)?
  32. 32.What amount will ₹30400 grow to in 1 year at 4% per year compound interest (in ₹)?
  33. 33.What amount will ₹32300 grow to in 1 year at 4% per year compound interest (in ₹)?
  34. 34.A town has 48000 people. The population grows by 15% every year. What will the population be after 3 years?
  35. 35.A town has 29600 people. The population grows by 15% every year. What will the population be after 2 years?
  36. 36.What is the difference between the compound interest and the simple interest on ₹13200 at 25% per year for 2 years (in ₹)?
  37. 37.What amount will ₹30300 grow to in 1 year at 10% per year compound interest (in ₹)?
  38. 38.What amount will ₹9600 grow to in 1 year at 5% per year compound interest (in ₹)?
  39. 39.A town has 7400 people. The population grows by 25% every year. What will the population be after 1 year?
  40. 40.What amount will ₹37000 grow to in 3 years at 10% per year compound interest (in ₹)?

Answer key

  1. 999
  2. 21868
  3. 5250
  4. 504
  5. 15300
  6. 216
  7. 27436
  8. 11020
  9. 58750
  10. 256
  11. 58520
  12. 8799
  13. 188
  14. 697
  15. 7904
  16. 8019
  17. 49572
  18. 11648
  19. 416
  20. 208
  21. 8464
  22. 136
  23. 63
  24. 57120
  25. 360
  26. 59
  27. 28665
  28. 48
  29. 4182
  30. 35397
  31. 132
  32. 31616
  33. 33592
  34. 73002
  35. 39146
  36. 825
  37. 33330
  38. 10080
  39. 9250
  40. 49247

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets