Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.Find the compound interest on ₹25000 at 12% per year for 2 years, compounded every year (in ₹).
- 2.Find the compound interest on ₹32500 at 25% per year for 1 year, compounded every year (in ₹).
- 3.What amount will ₹49900 grow to in 1 year at 25% per year compound interest (in ₹)?
- 4.What amount will ₹8000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 5.What is the difference between the compound interest and the simple interest on ₹27500 at 4% per year for 2 years (in ₹)?
- 6.Find the compound interest on ₹13300 at 10% per year for 1 year, compounded every year (in ₹).
- 7.A town has 16000 people. The population grows by 5% every year. What will the population be after 3 years?
- 8.What amount will ₹44800 grow to in 3 years at 25% per year compound interest (in ₹)?
- 9.Find the compound interest on ₹39100 at 20% per year for 2 years, compounded every year (in ₹).
- 10.A scooter is worth ₹51200. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
- 11.What is the difference between the compound interest and the simple interest on ₹50400 at 15% per year for 2 years (in ₹)?
- 12.What amount will ₹25000 grow to in 2 years at 4% per year compound interest (in ₹)?
- 13.Find the compound interest on ₹15000 at 20% per year for 2 years, compounded every year (in ₹).
- 14.A scooter is worth ₹39200. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
- 15.What amount will ₹24000 grow to in 3 years at 25% per year compound interest (in ₹)?
- 16.Find the compound interest on ₹59500 at 20% per year for 3 years, compounded every year (in ₹).
- 17.What is the difference between the compound interest and the simple interest on ₹44800 at 25% per year for 2 years (in ₹)?
- 18.What is the difference between the compound interest and the simple interest on ₹35000 at 12% per year for 2 years (in ₹)?
- 19.What is the difference between the compound interest and the simple interest on ₹14000 at 15% per year for 2 years (in ₹)?
- 20.Find the compound interest on ₹37500 at 4% per year for 1 year, compounded every year (in ₹).
- 21.What amount will ₹6000 grow to in 2 years at 25% per year compound interest (in ₹)?
- 22.A scooter is worth ₹9000. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
- 23.A town has 32000 people. The population grows by 15% every year. What will the population be after 3 years?
- 24.What is the difference between the compound interest and the simple interest on ₹34400 at 15% per year for 2 years (in ₹)?
- 25.A town has 50000 people. The population grows by 12% every year. What will the population be after 2 years?
- 26.What amount will ₹4800 grow to in 2 years at 5% per year compound interest (in ₹)?
- 27.Find the compound interest on ₹32000 at 5% per year for 3 years, compounded every year (in ₹).
- 28.What amount will ₹33600 grow to in 1 year at 20% per year compound interest (in ₹)?
- 29.Find the compound interest on ₹59000 at 8% per year for 1 year, compounded every year (in ₹).
- 30.What amount will ₹9700 grow to in 2 years at 20% per year compound interest (in ₹)?
- 31.Find the compound interest on ₹23200 at 25% per year for 1 year, compounded every year (in ₹).
- 32.A scooter is worth ₹19900. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
- 33.A scooter is worth ₹16700. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
- 34.What is the difference between the compound interest and the simple interest on ₹53500 at 10% per year for 2 years (in ₹)?
- 35.What is the difference between the compound interest and the simple interest on ₹36800 at 15% per year for 2 years (in ₹)?
- 36.What is the difference between the compound interest and the simple interest on ₹40000 at 8% per year for 2 years (in ₹)?
- 37.A town has 33500 people. The population grows by 20% every year. What will the population be after 3 years?
- 38.A scooter is worth ₹15400. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
- 39.Find the compound interest on ₹4000 at 5% per year for 2 years, compounded every year (in ₹).
- 40.What is the difference between the compound interest and the simple interest on ₹50000 at 12% per year for 2 years (in ₹)?
Answer key
- 6360
- 8125
- 62375
- 9261
- 44
- 1330
- 18522
- 87500
- 17204
- 28800
- 1134
- 27040
- 6600
- 35378
- 46875
- 43316
- 2800
- 504
- 315
- 1500
- 9375
- 6750
- 48668
- 774
- 62720
- 5292
- 5044
- 40320
- 4720
- 13968
- 5800
- 15920
- 15030
- 535
- 828
- 256
- 57888
- 14168
- 410
- 720
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