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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 129 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

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  1. 1.A town has 19500 people. The population grows by 5% every year. What will the population be after 1 year?
  2. 2.What is the difference between the compound interest and the simple interest on ₹24400 at 5% per year for 2 years (in ₹)?
  3. 3.A town has 6400 people. The population grows by 15% every year. What will the population be after 2 years?
  4. 4.Find the compound interest on ₹27500 at 8% per year for 2 years, compounded every year (in ₹).
  5. 5.Find the compound interest on ₹33000 at 20% per year for 3 years, compounded every year (in ₹).
  6. 6.A scooter is worth ₹34000. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
  7. 7.What amount will ₹15000 grow to in 3 years at 10% per year compound interest (in ₹)?
  8. 8.What is the difference between the compound interest and the simple interest on ₹5000 at 12% per year for 2 years (in ₹)?
  9. 9.What amount will ₹6000 grow to in 2 years at 15% per year compound interest (in ₹)?
  10. 10.What amount will ₹16000 grow to in 2 years at 5% per year compound interest (in ₹)?
  11. 11.A scooter is worth ₹40000. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
  12. 12.A scooter is worth ₹2500. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
  13. 13.Find the compound interest on ₹37500 at 20% per year for 3 years, compounded every year (in ₹).
  14. 14.Find the compound interest on ₹38500 at 15% per year for 1 year, compounded every year (in ₹).
  15. 15.A scooter is worth ₹52700. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
  16. 16.What is the difference between the compound interest and the simple interest on ₹48400 at 15% per year for 2 years (in ₹)?
  17. 17.A town has 6400 people. The population grows by 5% every year. What will the population be after 2 years?
  18. 18.A town has 33300 people. The population grows by 20% every year. What will the population be after 1 year?
  19. 19.Find the compound interest on ₹48000 at 15% per year for 3 years, compounded every year (in ₹).
  20. 20.What amount will ₹16000 grow to in 3 years at 15% per year compound interest (in ₹)?
  21. 21.A town has 41800 people. The population grows by 5% every year. What will the population be after 1 year?
  22. 22.Find the compound interest on ₹19000 at 10% per year for 3 years, compounded every year (in ₹).
  23. 23.Find the compound interest on ₹15900 at 10% per year for 1 year, compounded every year (in ₹).
  24. 24.What is the difference between the compound interest and the simple interest on ₹59700 at 10% per year for 2 years (in ₹)?
  25. 25.A town has 8000 people. The population grows by 5% every year. What will the population be after 3 years?
  26. 26.What is the difference between the compound interest and the simple interest on ₹49600 at 25% per year for 2 years (in ₹)?
  27. 27.Find the compound interest on ₹14400 at 25% per year for 2 years, compounded every year (in ₹).
  28. 28.What is the difference between the compound interest and the simple interest on ₹32500 at 4% per year for 2 years (in ₹)?
  29. 29.What amount will ₹4000 grow to in 3 years at 10% per year compound interest (in ₹)?
  30. 30.What is the difference between the compound interest and the simple interest on ₹18500 at 10% per year for 2 years (in ₹)?
  31. 31.Find the compound interest on ₹5000 at 8% per year for 2 years, compounded every year (in ₹).
  32. 32.What amount will ₹18300 grow to in 1 year at 25% per year compound interest (in ₹)?
  33. 33.What is the difference between the compound interest and the simple interest on ₹53600 at 25% per year for 2 years (in ₹)?
  34. 34.Find the compound interest on ₹19100 at 12% per year for 1 year, compounded every year (in ₹).
  35. 35.What is the difference between the compound interest and the simple interest on ₹25200 at 15% per year for 2 years (in ₹)?
  36. 36.Find the compound interest on ₹22500 at 20% per year for 3 years, compounded every year (in ₹).
  37. 37.Find the compound interest on ₹38400 at 10% per year for 1 year, compounded every year (in ₹).
  38. 38.Find the compound interest on ₹58200 at 10% per year for 2 years, compounded every year (in ₹).
  39. 39.What amount will ₹14400 grow to in 3 years at 25% per year compound interest (in ₹)?
  40. 40.A scooter is worth ₹20000. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?

Answer key

  1. 20475
  2. 61
  3. 8464
  4. 4576
  5. 24024
  6. 27200
  7. 19965
  8. 72
  9. 7935
  10. 17640
  11. 16875
  12. 2300
  13. 27300
  14. 5775
  15. 47430
  16. 1089
  17. 7056
  18. 39960
  19. 25002
  20. 24334
  21. 43890
  22. 6289
  23. 1590
  24. 597
  25. 9261
  26. 3100
  27. 8100
  28. 52
  29. 5324
  30. 185
  31. 832
  32. 22875
  33. 3350
  34. 2292
  35. 567
  36. 16380
  37. 3840
  38. 12222
  39. 28125
  40. 18432

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