Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.A town has 19500 people. The population grows by 5% every year. What will the population be after 1 year?
- 2.What is the difference between the compound interest and the simple interest on ₹24400 at 5% per year for 2 years (in ₹)?
- 3.A town has 6400 people. The population grows by 15% every year. What will the population be after 2 years?
- 4.Find the compound interest on ₹27500 at 8% per year for 2 years, compounded every year (in ₹).
- 5.Find the compound interest on ₹33000 at 20% per year for 3 years, compounded every year (in ₹).
- 6.A scooter is worth ₹34000. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
- 7.What amount will ₹15000 grow to in 3 years at 10% per year compound interest (in ₹)?
- 8.What is the difference between the compound interest and the simple interest on ₹5000 at 12% per year for 2 years (in ₹)?
- 9.What amount will ₹6000 grow to in 2 years at 15% per year compound interest (in ₹)?
- 10.What amount will ₹16000 grow to in 2 years at 5% per year compound interest (in ₹)?
- 11.A scooter is worth ₹40000. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
- 12.A scooter is worth ₹2500. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
- 13.Find the compound interest on ₹37500 at 20% per year for 3 years, compounded every year (in ₹).
- 14.Find the compound interest on ₹38500 at 15% per year for 1 year, compounded every year (in ₹).
- 15.A scooter is worth ₹52700. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
- 16.What is the difference between the compound interest and the simple interest on ₹48400 at 15% per year for 2 years (in ₹)?
- 17.A town has 6400 people. The population grows by 5% every year. What will the population be after 2 years?
- 18.A town has 33300 people. The population grows by 20% every year. What will the population be after 1 year?
- 19.Find the compound interest on ₹48000 at 15% per year for 3 years, compounded every year (in ₹).
- 20.What amount will ₹16000 grow to in 3 years at 15% per year compound interest (in ₹)?
- 21.A town has 41800 people. The population grows by 5% every year. What will the population be after 1 year?
- 22.Find the compound interest on ₹19000 at 10% per year for 3 years, compounded every year (in ₹).
- 23.Find the compound interest on ₹15900 at 10% per year for 1 year, compounded every year (in ₹).
- 24.What is the difference between the compound interest and the simple interest on ₹59700 at 10% per year for 2 years (in ₹)?
- 25.A town has 8000 people. The population grows by 5% every year. What will the population be after 3 years?
- 26.What is the difference between the compound interest and the simple interest on ₹49600 at 25% per year for 2 years (in ₹)?
- 27.Find the compound interest on ₹14400 at 25% per year for 2 years, compounded every year (in ₹).
- 28.What is the difference between the compound interest and the simple interest on ₹32500 at 4% per year for 2 years (in ₹)?
- 29.What amount will ₹4000 grow to in 3 years at 10% per year compound interest (in ₹)?
- 30.What is the difference between the compound interest and the simple interest on ₹18500 at 10% per year for 2 years (in ₹)?
- 31.Find the compound interest on ₹5000 at 8% per year for 2 years, compounded every year (in ₹).
- 32.What amount will ₹18300 grow to in 1 year at 25% per year compound interest (in ₹)?
- 33.What is the difference between the compound interest and the simple interest on ₹53600 at 25% per year for 2 years (in ₹)?
- 34.Find the compound interest on ₹19100 at 12% per year for 1 year, compounded every year (in ₹).
- 35.What is the difference between the compound interest and the simple interest on ₹25200 at 15% per year for 2 years (in ₹)?
- 36.Find the compound interest on ₹22500 at 20% per year for 3 years, compounded every year (in ₹).
- 37.Find the compound interest on ₹38400 at 10% per year for 1 year, compounded every year (in ₹).
- 38.Find the compound interest on ₹58200 at 10% per year for 2 years, compounded every year (in ₹).
- 39.What amount will ₹14400 grow to in 3 years at 25% per year compound interest (in ₹)?
- 40.A scooter is worth ₹20000. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
Answer key
- 20475
- 61
- 8464
- 4576
- 24024
- 27200
- 19965
- 72
- 7935
- 17640
- 16875
- 2300
- 27300
- 5775
- 47430
- 1089
- 7056
- 39960
- 25002
- 24334
- 43890
- 6289
- 1590
- 597
- 9261
- 3100
- 8100
- 52
- 5324
- 185
- 832
- 22875
- 3350
- 2292
- 567
- 16380
- 3840
- 12222
- 28125
- 18432
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