Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 132 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹41500 at 4% per year for 1 year, compounded every year (in ₹).
2. 2.What is the difference between the compound interest and the simple interest on ₹50000 at 12% per year for 2 years (in ₹)?
3. 3.What is the difference between the compound interest and the simple interest on ₹20000 at 8% per year for 2 years (in ₹)?
4. 4.Find the compound interest on ₹21900 at 25% per year for 1 year, compounded every year (in ₹).
5. 5.What is the difference between the compound interest and the simple interest on ₹23800 at 20% per year for 2 years (in ₹)?
6. 6.What amount will ₹11000 grow to in 3 years at 10% per year compound interest (in ₹)?
7. 7.Find the compound interest on ₹4600 at 12% per year for 1 year, compounded every year (in ₹).
8. 8.Find the compound interest on ₹24200 at 20% per year for 1 year, compounded every year (in ₹).
9. 9.What is the difference between the compound interest and the simple interest on ₹24500 at 20% per year for 2 years (in ₹)?
10. 10.What amount will ₹42400 grow to in 2 years at 5% per year compound interest (in ₹)?
11. 11.What is the difference between the compound interest and the simple interest on ₹27500 at 12% per year for 2 years (in ₹)?
12. 12.A town has 35200 people. The population grows by 25% every year. What will the population be after 3 years?
13. 13.Find the compound interest on ₹49600 at 15% per year for 2 years, compounded every year (in ₹).
14. 14.What amount will ₹54000 grow to in 1 year at 4% per year compound interest (in ₹)?
15. 15.Find the compound interest on ₹22100 at 5% per year for 1 year, compounded every year (in ₹).
16. 16.What is the difference between the compound interest and the simple interest on ₹22500 at 12% per year for 2 years (in ₹)?
17. 17.What amount will ₹55000 grow to in 2 years at 12% per year compound interest (in ₹)?
18. 18.Find the compound interest on ₹3500 at 8% per year for 1 year, compounded every year (in ₹).
19. 19.Find the compound interest on ₹2200 at 12% per year for 1 year, compounded every year (in ₹).
20. 20.Find the compound interest on ₹59600 at 10% per year for 2 years, compounded every year (in ₹).
21. 21.What is the difference between the compound interest and the simple interest on ₹26400 at 25% per year for 2 years (in ₹)?
22. 22.Find the compound interest on ₹25100 at 4% per year for 1 year, compounded every year (in ₹).
23. 23.What is the difference between the compound interest and the simple interest on ₹52500 at 4% per year for 2 years (in ₹)?
24. 24.What amount will ₹4500 grow to in 3 years at 20% per year compound interest (in ₹)?
25. 25.Find the compound interest on ₹49600 at 25% per year for 3 years, compounded every year (in ₹).
26. 26.What amount will ₹10200 grow to in 1 year at 15% per year compound interest (in ₹)?
27. 27.Find the compound interest on ₹12400 at 20% per year for 1 year, compounded every year (in ₹).
28. 28.What amount will ₹8800 grow to in 2 years at 15% per year compound interest (in ₹)?
29. 29.What amount will ₹22500 grow to in 2 years at 4% per year compound interest (in ₹)?
30. 30.A town has 24500 people. The population grows by 8% every year. What will the population be after 1 year?
31. 31.What amount will ₹60000 grow to in 2 years at 20% per year compound interest (in ₹)?
32. 32.Find the compound interest on ₹52400 at 4% per year for 1 year, compounded every year (in ₹).
33. 33.What is the difference between the compound interest and the simple interest on ₹58400 at 15% per year for 2 years (in ₹)?
34. 34.A town has 30000 people. The population grows by 8% every year. What will the population be after 2 years?
35. 35.Find the compound interest on ₹25600 at 5% per year for 1 year, compounded every year (in ₹).
36. 36.A town has 14000 people. The population grows by 10% every year. What will the population be after 3 years?
37. 37.What amount will ₹25200 grow to in 2 years at 15% per year compound interest (in ₹)?
38. 38.What amount will ₹13800 grow to in 1 year at 20% per year compound interest (in ₹)?
39. 39.Find the compound interest on ₹56400 at 5% per year for 2 years, compounded every year (in ₹).
40. 40.What amount will ₹52100 grow to in 1 year at 12% per year compound interest (in ₹)?

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