Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 136 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A town has 16000 people. The population grows by 5% every year. What will the population be after 3 years?
2. 2.What is the difference between the compound interest and the simple interest on ₹2500 at 4% per year for 2 years (in ₹)?
3. 3.What is the difference between the compound interest and the simple interest on ₹37500 at 4% per year for 2 years (in ₹)?
4. 4.What is the difference between the compound interest and the simple interest on ₹20000 at 12% per year for 2 years (in ₹)?
5. 5.What is the difference between the compound interest and the simple interest on ₹25000 at 8% per year for 2 years (in ₹)?
6. 6.A town has 22800 people. The population grows by 25% every year. What will the population be after 2 years?
7. 7.What amount will ₹48000 grow to in 3 years at 5% per year compound interest (in ₹)?
8. 8.A town has 25000 people. The population grows by 4% every year. What will the population be after 2 years?
9. 9.What amount will ₹8000 grow to in 3 years at 5% per year compound interest (in ₹)?
10. 10.A town has 15300 people. The population grows by 15% every year. What will the population be after 1 year?
11. 11.What amount will ₹47800 grow to in 1 year at 5% per year compound interest (in ₹)?
12. 12.Find the compound interest on ₹8000 at 15% per year for 3 years, compounded every year (in ₹).
13. 13.Find the compound interest on ₹2900 at 10% per year for 1 year, compounded every year (in ₹).
14. 14.Find the compound interest on ₹39000 at 10% per year for 3 years, compounded every year (in ₹).
15. 15.A scooter is worth ₹5000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
16. 16.Find the compound interest on ₹44800 at 5% per year for 1 year, compounded every year (in ₹).
17. 17.What amount will ₹22500 grow to in 2 years at 8% per year compound interest (in ₹)?
18. 18.What amount will ₹54400 grow to in 3 years at 25% per year compound interest (in ₹)?
19. 19.Find the compound interest on ₹2400 at 20% per year for 2 years, compounded every year (in ₹).
20. 20.What is the difference between the compound interest and the simple interest on ₹5000 at 8% per year for 2 years (in ₹)?
21. 21.Find the compound interest on ₹28700 at 8% per year for 1 year, compounded every year (in ₹).
22. 22.Find the compound interest on ₹48000 at 5% per year for 3 years, compounded every year (in ₹).
23. 23.What amount will ₹47500 grow to in 3 years at 20% per year compound interest (in ₹)?
24. 24.Find the compound interest on ₹10200 at 5% per year for 1 year, compounded every year (in ₹).
25. 25.What amount will ₹31700 grow to in 1 year at 12% per year compound interest (in ₹)?
26. 26.Find the compound interest on ₹53100 at 20% per year for 2 years, compounded every year (in ₹).
27. 27.Find the compound interest on ₹3200 at 25% per year for 3 years, compounded every year (in ₹).
28. 28.Find the compound interest on ₹34500 at 8% per year for 1 year, compounded every year (in ₹).
29. 29.A town has 15000 people. The population grows by 12% every year. What will the population be after 2 years?
30. 30.What is the difference between the compound interest and the simple interest on ₹50100 at 10% per year for 2 years (in ₹)?
31. 31.What amount will ₹54600 grow to in 1 year at 20% per year compound interest (in ₹)?
32. 32.Find the compound interest on ₹3100 at 15% per year for 1 year, compounded every year (in ₹).
33. 33.Find the compound interest on ₹29000 at 4% per year for 1 year, compounded every year (in ₹).
34. 34.What amount will ₹56000 grow to in 3 years at 15% per year compound interest (in ₹)?
35. 35.What amount will ₹56000 grow to in 3 years at 5% per year compound interest (in ₹)?
36. 36.Find the compound interest on ₹49300 at 10% per year for 1 year, compounded every year (in ₹).
37. 37.What is the difference between the compound interest and the simple interest on ₹32800 at 15% per year for 2 years (in ₹)?
38. 38.A town has 54400 people. The population grows by 25% every year. What will the population be after 3 years?
39. 39.What amount will ₹32000 grow to in 3 years at 25% per year compound interest (in ₹)?
40. 40.Find the compound interest on ₹47500 at 8% per year for 2 years, compounded every year (in ₹).

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets