Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 138 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What amount will ₹24400 grow to in 2 years at 15% per year compound interest (in ₹)?
2. 2.What amount will ₹28500 grow to in 1 year at 4% per year compound interest (in ₹)?
3. 3.A town has 36000 people. The population grows by 20% every year. What will the population be after 3 years?
4. 4.A town has 48400 people. The population grows by 10% every year. What will the population be after 2 years?
5. 5.What is the difference between the compound interest and the simple interest on ₹6800 at 10% per year for 2 years (in ₹)?
6. 6.A scooter is worth ₹6600. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
7. 7.What is the difference between the compound interest and the simple interest on ₹55600 at 20% per year for 2 years (in ₹)?
8. 8.Find the compound interest on ₹25000 at 4% per year for 2 years, compounded every year (in ₹).
9. 9.What is the difference between the compound interest and the simple interest on ₹60000 at 8% per year for 2 years (in ₹)?
10. 10.What amount will ₹20000 grow to in 2 years at 8% per year compound interest (in ₹)?
11. 11.A town has 52800 people. The population grows by 10% every year. What will the population be after 1 year?
12. 12.What amount will ₹7200 grow to in 2 years at 5% per year compound interest (in ₹)?
13. 13.What amount will ₹50200 grow to in 1 year at 12% per year compound interest (in ₹)?
14. 14.What amount will ₹29500 grow to in 1 year at 20% per year compound interest (in ₹)?
15. 15.Find the compound interest on ₹13600 at 5% per year for 1 year, compounded every year (in ₹).
16. 16.What is the difference between the compound interest and the simple interest on ₹46400 at 5% per year for 2 years (in ₹)?
17. 17.A town has 43600 people. The population grows by 25% every year. What will the population be after 2 years?
18. 18.Find the compound interest on ₹15600 at 25% per year for 1 year, compounded every year (in ₹).
19. 19.A town has 16000 people. The population grows by 15% every year. What will the population be after 3 years?
20. 20.Find the compound interest on ₹46000 at 10% per year for 2 years, compounded every year (in ₹).
21. 21.Find the compound interest on ₹11200 at 15% per year for 2 years, compounded every year (in ₹).
22. 22.Find the compound interest on ₹10000 at 8% per year for 2 years, compounded every year (in ₹).
23. 23.Find the compound interest on ₹57100 at 25% per year for 1 year, compounded every year (in ₹).
24. 24.What is the difference between the compound interest and the simple interest on ₹16400 at 10% per year for 2 years (in ₹)?
25. 25.A town has 28200 people. The population grows by 20% every year. What will the population be after 1 year?
26. 26.Find the compound interest on ₹42900 at 10% per year for 2 years, compounded every year (in ₹).
27. 27.Find the compound interest on ₹19600 at 5% per year for 1 year, compounded every year (in ₹).
28. 28.A town has 17600 people. The population grows by 15% every year. What will the population be after 2 years?
29. 29.What amount will ₹34900 grow to in 1 year at 12% per year compound interest (in ₹)?
30. 30.What amount will ₹17500 grow to in 2 years at 12% per year compound interest (in ₹)?
31. 31.What is the difference between the compound interest and the simple interest on ₹27500 at 8% per year for 2 years (in ₹)?
32. 32.A town has 7600 people. The population grows by 5% every year. What will the population be after 2 years?
33. 33.What amount will ₹26400 grow to in 1 year at 25% per year compound interest (in ₹)?
34. 34.What is the difference between the compound interest and the simple interest on ₹4400 at 5% per year for 2 years (in ₹)?
35. 35.A scooter is worth ₹16900. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
36. 36.A scooter is worth ₹8000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
37. 37.What is the difference between the compound interest and the simple interest on ₹3600 at 5% per year for 2 years (in ₹)?
38. 38.What is the difference between the compound interest and the simple interest on ₹47500 at 4% per year for 2 years (in ₹)?
39. 39.A town has 10000 people. The population grows by 20% every year. What will the population be after 1 year?
40. 40.A town has 30000 people. The population grows by 4% every year. What will the population be after 2 years?

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