Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.What is the difference between the compound interest and the simple interest on ₹38000 at 10% per year for 2 years (in ₹)?
- 2.A town has 5500 people. The population grows by 4% every year. What will the population be after 1 year?
- 3.What is the difference between the compound interest and the simple interest on ₹38800 at 5% per year for 2 years (in ₹)?
- 4.Find the compound interest on ₹4800 at 25% per year for 3 years, compounded every year (in ₹).
- 5.What amount will ₹42500 grow to in 3 years at 20% per year compound interest (in ₹)?
- 6.A town has 8800 people. The population grows by 25% every year. What will the population be after 1 year?
- 7.What amount will ₹7800 grow to in 1 year at 5% per year compound interest (in ₹)?
- 8.A scooter is worth ₹44800. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
- 9.What is the difference between the compound interest and the simple interest on ₹52500 at 8% per year for 2 years (in ₹)?
- 10.Find the compound interest on ₹27000 at 4% per year for 1 year, compounded every year (in ₹).
- 11.What is the difference between the compound interest and the simple interest on ₹28500 at 10% per year for 2 years (in ₹)?
- 12.What is the difference between the compound interest and the simple interest on ₹47200 at 15% per year for 2 years (in ₹)?
- 13.What is the difference between the compound interest and the simple interest on ₹30000 at 12% per year for 2 years (in ₹)?
- 14.What amount will ₹30000 grow to in 2 years at 4% per year compound interest (in ₹)?
- 15.What is the difference between the compound interest and the simple interest on ₹7200 at 5% per year for 2 years (in ₹)?
- 16.What amount will ₹15000 grow to in 2 years at 4% per year compound interest (in ₹)?
- 17.What amount will ₹37500 grow to in 2 years at 8% per year compound interest (in ₹)?
- 18.What amount will ₹12500 grow to in 2 years at 4% per year compound interest (in ₹)?
- 19.What is the difference between the compound interest and the simple interest on ₹40000 at 12% per year for 2 years (in ₹)?
- 20.What amount will ₹33500 grow to in 3 years at 20% per year compound interest (in ₹)?
- 21.A scooter is worth ₹30400. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
- 22.What is the difference between the compound interest and the simple interest on ₹44800 at 15% per year for 2 years (in ₹)?
- 23.What amount will ₹9600 grow to in 2 years at 15% per year compound interest (in ₹)?
- 24.What is the difference between the compound interest and the simple interest on ₹17500 at 4% per year for 2 years (in ₹)?
- 25.A scooter is worth ₹44800. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
- 26.Find the compound interest on ₹5000 at 12% per year for 2 years, compounded every year (in ₹).
- 27.Find the compound interest on ₹57500 at 8% per year for 2 years, compounded every year (in ₹).
- 28.Find the compound interest on ₹49000 at 25% per year for 1 year, compounded every year (in ₹).
- 29.A scooter is worth ₹6700. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
- 30.A scooter is worth ₹32700. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
- 31.Find the compound interest on ₹37000 at 10% per year for 2 years, compounded every year (in ₹).
- 32.A town has 42500 people. The population grows by 8% every year. What will the population be after 2 years?
- 33.What amount will ₹22500 grow to in 2 years at 4% per year compound interest (in ₹)?
- 34.A town has 21300 people. The population grows by 10% every year. What will the population be after 2 years?
- 35.Find the compound interest on ₹58000 at 25% per year for 2 years, compounded every year (in ₹).
- 36.A town has 15100 people. The population grows by 10% every year. What will the population be after 1 year?
- 37.What amount will ₹16100 grow to in 1 year at 12% per year compound interest (in ₹)?
- 38.What is the difference between the compound interest and the simple interest on ₹50300 at 10% per year for 2 years (in ₹)?
- 39.What is the difference between the compound interest and the simple interest on ₹30000 at 8% per year for 2 years (in ₹)?
- 40.What amount will ₹43200 grow to in 2 years at 5% per year compound interest (in ₹)?
Answer key
- 380
- 5720
- 97
- 4575
- 73440
- 11000
- 8190
- 18900
- 336
- 1080
- 285
- 1062
- 432
- 32448
- 18
- 16224
- 43740
- 13520
- 576
- 57888
- 25840
- 1008
- 12696
- 28
- 40432
- 1272
- 9568
- 12250
- 6432
- 29430
- 7770
- 49572
- 24336
- 25773
- 32625
- 16610
- 18032
- 503
- 192
- 47628
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