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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 14 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What is the difference between the compound interest and the simple interest on ₹38000 at 10% per year for 2 years (in ₹)?
  2. 2.A town has 5500 people. The population grows by 4% every year. What will the population be after 1 year?
  3. 3.What is the difference between the compound interest and the simple interest on ₹38800 at 5% per year for 2 years (in ₹)?
  4. 4.Find the compound interest on ₹4800 at 25% per year for 3 years, compounded every year (in ₹).
  5. 5.What amount will ₹42500 grow to in 3 years at 20% per year compound interest (in ₹)?
  6. 6.A town has 8800 people. The population grows by 25% every year. What will the population be after 1 year?
  7. 7.What amount will ₹7800 grow to in 1 year at 5% per year compound interest (in ₹)?
  8. 8.A scooter is worth ₹44800. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
  9. 9.What is the difference between the compound interest and the simple interest on ₹52500 at 8% per year for 2 years (in ₹)?
  10. 10.Find the compound interest on ₹27000 at 4% per year for 1 year, compounded every year (in ₹).
  11. 11.What is the difference between the compound interest and the simple interest on ₹28500 at 10% per year for 2 years (in ₹)?
  12. 12.What is the difference between the compound interest and the simple interest on ₹47200 at 15% per year for 2 years (in ₹)?
  13. 13.What is the difference between the compound interest and the simple interest on ₹30000 at 12% per year for 2 years (in ₹)?
  14. 14.What amount will ₹30000 grow to in 2 years at 4% per year compound interest (in ₹)?
  15. 15.What is the difference between the compound interest and the simple interest on ₹7200 at 5% per year for 2 years (in ₹)?
  16. 16.What amount will ₹15000 grow to in 2 years at 4% per year compound interest (in ₹)?
  17. 17.What amount will ₹37500 grow to in 2 years at 8% per year compound interest (in ₹)?
  18. 18.What amount will ₹12500 grow to in 2 years at 4% per year compound interest (in ₹)?
  19. 19.What is the difference between the compound interest and the simple interest on ₹40000 at 12% per year for 2 years (in ₹)?
  20. 20.What amount will ₹33500 grow to in 3 years at 20% per year compound interest (in ₹)?
  21. 21.A scooter is worth ₹30400. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
  22. 22.What is the difference between the compound interest and the simple interest on ₹44800 at 15% per year for 2 years (in ₹)?
  23. 23.What amount will ₹9600 grow to in 2 years at 15% per year compound interest (in ₹)?
  24. 24.What is the difference between the compound interest and the simple interest on ₹17500 at 4% per year for 2 years (in ₹)?
  25. 25.A scooter is worth ₹44800. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
  26. 26.Find the compound interest on ₹5000 at 12% per year for 2 years, compounded every year (in ₹).
  27. 27.Find the compound interest on ₹57500 at 8% per year for 2 years, compounded every year (in ₹).
  28. 28.Find the compound interest on ₹49000 at 25% per year for 1 year, compounded every year (in ₹).
  29. 29.A scooter is worth ₹6700. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
  30. 30.A scooter is worth ₹32700. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
  31. 31.Find the compound interest on ₹37000 at 10% per year for 2 years, compounded every year (in ₹).
  32. 32.A town has 42500 people. The population grows by 8% every year. What will the population be after 2 years?
  33. 33.What amount will ₹22500 grow to in 2 years at 4% per year compound interest (in ₹)?
  34. 34.A town has 21300 people. The population grows by 10% every year. What will the population be after 2 years?
  35. 35.Find the compound interest on ₹58000 at 25% per year for 2 years, compounded every year (in ₹).
  36. 36.A town has 15100 people. The population grows by 10% every year. What will the population be after 1 year?
  37. 37.What amount will ₹16100 grow to in 1 year at 12% per year compound interest (in ₹)?
  38. 38.What is the difference between the compound interest and the simple interest on ₹50300 at 10% per year for 2 years (in ₹)?
  39. 39.What is the difference between the compound interest and the simple interest on ₹30000 at 8% per year for 2 years (in ₹)?
  40. 40.What amount will ₹43200 grow to in 2 years at 5% per year compound interest (in ₹)?

Answer key

  1. 380
  2. 5720
  3. 97
  4. 4575
  5. 73440
  6. 11000
  7. 8190
  8. 18900
  9. 336
  10. 1080
  11. 285
  12. 1062
  13. 432
  14. 32448
  15. 18
  16. 16224
  17. 43740
  18. 13520
  19. 576
  20. 57888
  21. 25840
  22. 1008
  23. 12696
  24. 28
  25. 40432
  26. 1272
  27. 9568
  28. 12250
  29. 6432
  30. 29430
  31. 7770
  32. 49572
  33. 24336
  34. 25773
  35. 32625
  36. 16610
  37. 18032
  38. 503
  39. 192
  40. 47628

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