← Compound interest lesson New set →

Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 140 · 40 sums
TalentJR

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What amount will ₹24000 grow to in 3 years at 15% per year compound interest (in ₹)?
  2. 2.A scooter is worth ₹24400. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
  3. 3.Find the compound interest on ₹22000 at 10% per year for 3 years, compounded every year (in ₹).
  4. 4.Find the compound interest on ₹51200 at 25% per year for 3 years, compounded every year (in ₹).
  5. 5.Find the compound interest on ₹34000 at 25% per year for 2 years, compounded every year (in ₹).
  6. 6.What is the difference between the compound interest and the simple interest on ₹38400 at 25% per year for 2 years (in ₹)?
  7. 7.What is the difference between the compound interest and the simple interest on ₹13600 at 5% per year for 2 years (in ₹)?
  8. 8.What amount will ₹8000 grow to in 1 year at 20% per year compound interest (in ₹)?
  9. 9.Find the compound interest on ₹6800 at 15% per year for 2 years, compounded every year (in ₹).
  10. 10.What amount will ₹42500 grow to in 2 years at 8% per year compound interest (in ₹)?
  11. 11.What is the difference between the compound interest and the simple interest on ₹27500 at 8% per year for 2 years (in ₹)?
  12. 12.What amount will ₹56000 grow to in 1 year at 15% per year compound interest (in ₹)?
  13. 13.Find the compound interest on ₹51000 at 10% per year for 2 years, compounded every year (in ₹).
  14. 14.What amount will ₹16800 grow to in 1 year at 15% per year compound interest (in ₹)?
  15. 15.A scooter is worth ₹25200. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
  16. 16.What amount will ₹45400 grow to in 1 year at 5% per year compound interest (in ₹)?
  17. 17.A town has 38600 people. The population grows by 10% every year. What will the population be after 2 years?
  18. 18.Find the compound interest on ₹60000 at 12% per year for 2 years, compounded every year (in ₹).
  19. 19.Find the compound interest on ₹52000 at 10% per year for 3 years, compounded every year (in ₹).
  20. 20.A town has 10000 people. The population grows by 4% every year. What will the population be after 2 years?
  21. 21.Find the compound interest on ₹40000 at 5% per year for 2 years, compounded every year (in ₹).
  22. 22.What amount will ₹40500 grow to in 2 years at 20% per year compound interest (in ₹)?
  23. 23.Find the compound interest on ₹16800 at 25% per year for 1 year, compounded every year (in ₹).
  24. 24.Find the compound interest on ₹24000 at 15% per year for 3 years, compounded every year (in ₹).
  25. 25.A town has 1600 people. The population grows by 25% every year. What will the population be after 3 years?
  26. 26.A town has 32500 people. The population grows by 4% every year. What will the population be after 2 years?
  27. 27.What amount will ₹47200 grow to in 1 year at 25% per year compound interest (in ₹)?
  28. 28.What is the difference between the compound interest and the simple interest on ₹29100 at 20% per year for 2 years (in ₹)?
  29. 29.Find the compound interest on ₹17500 at 4% per year for 2 years, compounded every year (in ₹).
  30. 30.Find the compound interest on ₹22700 at 10% per year for 2 years, compounded every year (in ₹).
  31. 31.What is the difference between the compound interest and the simple interest on ₹49600 at 25% per year for 2 years (in ₹)?
  32. 32.Find the compound interest on ₹32000 at 5% per year for 3 years, compounded every year (in ₹).
  33. 33.What is the difference between the compound interest and the simple interest on ₹45000 at 12% per year for 2 years (in ₹)?
  34. 34.What is the difference between the compound interest and the simple interest on ₹32500 at 20% per year for 2 years (in ₹)?
  35. 35.Find the compound interest on ₹4500 at 10% per year for 2 years, compounded every year (in ₹).
  36. 36.Find the compound interest on ₹57500 at 20% per year for 3 years, compounded every year (in ₹).
  37. 37.A scooter is worth ₹48000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
  38. 38.What amount will ₹40400 grow to in 2 years at 15% per year compound interest (in ₹)?
  39. 39.What is the difference between the compound interest and the simple interest on ₹47600 at 10% per year for 2 years (in ₹)?
  40. 40.What amount will ₹16900 grow to in 1 year at 12% per year compound interest (in ₹)?

Answer key

  1. 36501
  2. 13725
  3. 7282
  4. 48800
  5. 19125
  6. 2400
  7. 34
  8. 9600
  9. 2193
  10. 49572
  11. 176
  12. 64400
  13. 10710
  14. 19320
  15. 22680
  16. 47670
  17. 46706
  18. 15264
  19. 17212
  20. 10816
  21. 4100
  22. 58320
  23. 4200
  24. 12501
  25. 3125
  26. 35152
  27. 59000
  28. 1164
  29. 1428
  30. 4767
  31. 3100
  32. 5044
  33. 648
  34. 1300
  35. 945
  36. 41860
  37. 41154
  38. 53429
  39. 476
  40. 18928

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets