Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.What is the difference between the compound interest and the simple interest on ₹17500 at 4% per year for 2 years (in ₹)?
- 2.A scooter is worth ₹20000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
- 3.A town has 16000 people. The population grows by 15% every year. What will the population be after 3 years?
- 4.Find the compound interest on ₹51600 at 12% per year for 1 year, compounded every year (in ₹).
- 5.A scooter is worth ₹40500. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
- 6.What is the difference between the compound interest and the simple interest on ₹35000 at 4% per year for 2 years (in ₹)?
- 7.What is the difference between the compound interest and the simple interest on ₹37500 at 8% per year for 2 years (in ₹)?
- 8.Find the compound interest on ₹33000 at 10% per year for 3 years, compounded every year (in ₹).
- 9.A scooter is worth ₹52000. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
- 10.Find the compound interest on ₹40000 at 4% per year for 2 years, compounded every year (in ₹).
- 11.A scooter is worth ₹37000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
- 12.A scooter is worth ₹37200. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
- 13.Find the compound interest on ₹50000 at 5% per year for 2 years, compounded every year (in ₹).
- 14.What is the difference between the compound interest and the simple interest on ₹11900 at 10% per year for 2 years (in ₹)?
- 15.Find the compound interest on ₹14100 at 5% per year for 1 year, compounded every year (in ₹).
- 16.A town has 45500 people. The population grows by 20% every year. What will the population be after 3 years?
- 17.Find the compound interest on ₹11800 at 20% per year for 2 years, compounded every year (in ₹).
- 18.A scooter is worth ₹10000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
- 19.A town has 4400 people. The population grows by 4% every year. What will the population be after 1 year?
- 20.What amount will ₹20000 grow to in 1 year at 10% per year compound interest (in ₹)?
- 21.A scooter is worth ₹11900. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
- 22.What amount will ₹34500 grow to in 1 year at 12% per year compound interest (in ₹)?
- 23.A scooter is worth ₹41500. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
- 24.A scooter is worth ₹45000. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
- 25.A town has 46100 people. The population grows by 20% every year. What will the population be after 1 year?
- 26.What is the difference between the compound interest and the simple interest on ₹7200 at 15% per year for 2 years (in ₹)?
- 27.A scooter is worth ₹22800. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
- 28.What amount will ₹12700 grow to in 1 year at 4% per year compound interest (in ₹)?
- 29.What is the difference between the compound interest and the simple interest on ₹5000 at 4% per year for 2 years (in ₹)?
- 30.What amount will ₹32000 grow to in 3 years at 15% per year compound interest (in ₹)?
- 31.Find the compound interest on ₹24400 at 15% per year for 2 years, compounded every year (in ₹).
- 32.What is the difference between the compound interest and the simple interest on ₹15600 at 5% per year for 2 years (in ₹)?
- 33.Find the compound interest on ₹5600 at 15% per year for 2 years, compounded every year (in ₹).
- 34.What is the difference between the compound interest and the simple interest on ₹8900 at 10% per year for 2 years (in ₹)?
- 35.Find the compound interest on ₹25600 at 25% per year for 2 years, compounded every year (in ₹).
- 36.Find the compound interest on ₹22500 at 12% per year for 2 years, compounded every year (in ₹).
- 37.What amount will ₹28300 grow to in 1 year at 5% per year compound interest (in ₹)?
- 38.What is the difference between the compound interest and the simple interest on ₹48800 at 25% per year for 2 years (in ₹)?
- 39.What amount will ₹60000 grow to in 2 years at 8% per year compound interest (in ₹)?
- 40.What amount will ₹43100 grow to in 1 year at 25% per year compound interest (in ₹)?
Answer key
- 28
- 16928
- 24334
- 6192
- 34425
- 56
- 240
- 10923
- 49920
- 3264
- 26973
- 33480
- 5125
- 119
- 705
- 78624
- 5192
- 8464
- 4576
- 22000
- 10472
- 38640
- 21248
- 34848
- 55320
- 162
- 20577
- 13208
- 8
- 48668
- 7869
- 39
- 1806
- 89
- 14400
- 5724
- 29715
- 3050
- 69984
- 53875
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