Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.What is the difference between the compound interest and the simple interest on ₹41700 at 20% per year for 2 years (in ₹)?
- 2.What amount will ₹30400 grow to in 3 years at 25% per year compound interest (in ₹)?
- 3.A town has 8100 people. The population grows by 5% every year. What will the population be after 1 year?
- 4.Find the compound interest on ₹42800 at 5% per year for 2 years, compounded every year (in ₹).
- 5.What is the difference between the compound interest and the simple interest on ₹18400 at 20% per year for 2 years (in ₹)?
- 6.What is the difference between the compound interest and the simple interest on ₹47800 at 10% per year for 2 years (in ₹)?
- 7.A scooter is worth ₹13200. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
- 8.Find the compound interest on ₹50200 at 10% per year for 1 year, compounded every year (in ₹).
- 9.What amount will ₹8000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 10.What is the difference between the compound interest and the simple interest on ₹45600 at 25% per year for 2 years (in ₹)?
- 11.What is the difference between the compound interest and the simple interest on ₹46800 at 25% per year for 2 years (in ₹)?
- 12.A town has 35900 people. The population grows by 8% every year. What will the population be after 1 year?
- 13.A scooter is worth ₹29000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
- 14.A town has 41000 people. The population grows by 4% every year. What will the population be after 1 year?
- 15.What amount will ₹11300 grow to in 1 year at 4% per year compound interest (in ₹)?
- 16.A scooter is worth ₹6700. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
- 17.Find the compound interest on ₹59600 at 5% per year for 2 years, compounded every year (in ₹).
- 18.A town has 43300 people. The population grows by 15% every year. What will the population be after 1 year?
- 19.What is the difference between the compound interest and the simple interest on ₹8800 at 15% per year for 2 years (in ₹)?
- 20.A scooter is worth ₹55000. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
- 21.What is the difference between the compound interest and the simple interest on ₹33700 at 10% per year for 2 years (in ₹)?
- 22.Find the compound interest on ₹56600 at 10% per year for 1 year, compounded every year (in ₹).
- 23.A town has 57500 people. The population grows by 8% every year. What will the population be after 2 years?
- 24.What is the difference between the compound interest and the simple interest on ₹27400 at 20% per year for 2 years (in ₹)?
- 25.What amount will ₹21000 grow to in 3 years at 10% per year compound interest (in ₹)?
- 26.Find the compound interest on ₹54000 at 10% per year for 3 years, compounded every year (in ₹).
- 27.What amount will ₹51500 grow to in 2 years at 10% per year compound interest (in ₹)?
- 28.A town has 10100 people. The population grows by 4% every year. What will the population be after 1 year?
- 29.Find the compound interest on ₹18800 at 12% per year for 1 year, compounded every year (in ₹).
- 30.What is the difference between the compound interest and the simple interest on ₹35200 at 15% per year for 2 years (in ₹)?
- 31.Find the compound interest on ₹60000 at 12% per year for 1 year, compounded every year (in ₹).
- 32.What amount will ₹7900 grow to in 1 year at 8% per year compound interest (in ₹)?
- 33.Find the compound interest on ₹6400 at 15% per year for 2 years, compounded every year (in ₹).
- 34.What is the difference between the compound interest and the simple interest on ₹47500 at 12% per year for 2 years (in ₹)?
- 35.What is the difference between the compound interest and the simple interest on ₹12000 at 5% per year for 2 years (in ₹)?
- 36.What amount will ₹32500 grow to in 2 years at 8% per year compound interest (in ₹)?
- 37.What amount will ₹27200 grow to in 2 years at 10% per year compound interest (in ₹)?
- 38.Find the compound interest on ₹22000 at 5% per year for 2 years, compounded every year (in ₹).
- 39.A scooter is worth ₹36500. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
- 40.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).
Answer key
- 1668
- 59375
- 8505
- 4387
- 736
- 478
- 12540
- 5020
- 9261
- 2850
- 2925
- 38772
- 21141
- 42640
- 11752
- 5896
- 6109
- 49795
- 198
- 50688
- 337
- 5660
- 67068
- 1096
- 27951
- 17874
- 62315
- 10504
- 2256
- 792
- 7200
- 8532
- 2064
- 684
- 30
- 37908
- 32912
- 2255
- 33580
- 6305
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