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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 146 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What is the difference between the compound interest and the simple interest on ₹41700 at 20% per year for 2 years (in ₹)?
  2. 2.What amount will ₹30400 grow to in 3 years at 25% per year compound interest (in ₹)?
  3. 3.A town has 8100 people. The population grows by 5% every year. What will the population be after 1 year?
  4. 4.Find the compound interest on ₹42800 at 5% per year for 2 years, compounded every year (in ₹).
  5. 5.What is the difference between the compound interest and the simple interest on ₹18400 at 20% per year for 2 years (in ₹)?
  6. 6.What is the difference between the compound interest and the simple interest on ₹47800 at 10% per year for 2 years (in ₹)?
  7. 7.A scooter is worth ₹13200. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
  8. 8.Find the compound interest on ₹50200 at 10% per year for 1 year, compounded every year (in ₹).
  9. 9.What amount will ₹8000 grow to in 3 years at 5% per year compound interest (in ₹)?
  10. 10.What is the difference between the compound interest and the simple interest on ₹45600 at 25% per year for 2 years (in ₹)?
  11. 11.What is the difference between the compound interest and the simple interest on ₹46800 at 25% per year for 2 years (in ₹)?
  12. 12.A town has 35900 people. The population grows by 8% every year. What will the population be after 1 year?
  13. 13.A scooter is worth ₹29000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
  14. 14.A town has 41000 people. The population grows by 4% every year. What will the population be after 1 year?
  15. 15.What amount will ₹11300 grow to in 1 year at 4% per year compound interest (in ₹)?
  16. 16.A scooter is worth ₹6700. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
  17. 17.Find the compound interest on ₹59600 at 5% per year for 2 years, compounded every year (in ₹).
  18. 18.A town has 43300 people. The population grows by 15% every year. What will the population be after 1 year?
  19. 19.What is the difference between the compound interest and the simple interest on ₹8800 at 15% per year for 2 years (in ₹)?
  20. 20.A scooter is worth ₹55000. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
  21. 21.What is the difference between the compound interest and the simple interest on ₹33700 at 10% per year for 2 years (in ₹)?
  22. 22.Find the compound interest on ₹56600 at 10% per year for 1 year, compounded every year (in ₹).
  23. 23.A town has 57500 people. The population grows by 8% every year. What will the population be after 2 years?
  24. 24.What is the difference between the compound interest and the simple interest on ₹27400 at 20% per year for 2 years (in ₹)?
  25. 25.What amount will ₹21000 grow to in 3 years at 10% per year compound interest (in ₹)?
  26. 26.Find the compound interest on ₹54000 at 10% per year for 3 years, compounded every year (in ₹).
  27. 27.What amount will ₹51500 grow to in 2 years at 10% per year compound interest (in ₹)?
  28. 28.A town has 10100 people. The population grows by 4% every year. What will the population be after 1 year?
  29. 29.Find the compound interest on ₹18800 at 12% per year for 1 year, compounded every year (in ₹).
  30. 30.What is the difference between the compound interest and the simple interest on ₹35200 at 15% per year for 2 years (in ₹)?
  31. 31.Find the compound interest on ₹60000 at 12% per year for 1 year, compounded every year (in ₹).
  32. 32.What amount will ₹7900 grow to in 1 year at 8% per year compound interest (in ₹)?
  33. 33.Find the compound interest on ₹6400 at 15% per year for 2 years, compounded every year (in ₹).
  34. 34.What is the difference between the compound interest and the simple interest on ₹47500 at 12% per year for 2 years (in ₹)?
  35. 35.What is the difference between the compound interest and the simple interest on ₹12000 at 5% per year for 2 years (in ₹)?
  36. 36.What amount will ₹32500 grow to in 2 years at 8% per year compound interest (in ₹)?
  37. 37.What amount will ₹27200 grow to in 2 years at 10% per year compound interest (in ₹)?
  38. 38.Find the compound interest on ₹22000 at 5% per year for 2 years, compounded every year (in ₹).
  39. 39.A scooter is worth ₹36500. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
  40. 40.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).

Answer key

  1. 1668
  2. 59375
  3. 8505
  4. 4387
  5. 736
  6. 478
  7. 12540
  8. 5020
  9. 9261
  10. 2850
  11. 2925
  12. 38772
  13. 21141
  14. 42640
  15. 11752
  16. 5896
  17. 6109
  18. 49795
  19. 198
  20. 50688
  21. 337
  22. 5660
  23. 67068
  24. 1096
  25. 27951
  26. 17874
  27. 62315
  28. 10504
  29. 2256
  30. 792
  31. 7200
  32. 8532
  33. 2064
  34. 684
  35. 30
  36. 37908
  37. 32912
  38. 2255
  39. 33580
  40. 6305

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