Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 149 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What is the difference between the compound interest and the simple interest on ₹15000 at 8% per year for 2 years (in ₹)?
2. 2.A scooter is worth ₹34000. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
3. 3.What is the difference between the compound interest and the simple interest on ₹12500 at 4% per year for 2 years (in ₹)?
4. 4.Find the compound interest on ₹40500 at 20% per year for 1 year, compounded every year (in ₹).
5. 5.Find the compound interest on ₹8800 at 5% per year for 2 years, compounded every year (in ₹).
6. 6.Find the compound interest on ₹7800 at 8% per year for 1 year, compounded every year (in ₹).
7. 7.A town has 4900 people. The population grows by 5% every year. What will the population be after 1 year?
8. 8.A scooter is worth ₹21000. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
9. 9.A town has 37500 people. The population grows by 8% every year. What will the population be after 2 years?
10. 10.A scooter is worth ₹53300. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
11. 11.What is the difference between the compound interest and the simple interest on ₹24800 at 15% per year for 2 years (in ₹)?
12. 12.A town has 9600 people. The population grows by 25% every year. What will the population be after 3 years?
13. 13.Find the compound interest on ₹24000 at 5% per year for 2 years, compounded every year (in ₹).
14. 14.A scooter is worth ₹17500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
15. 15.What is the difference between the compound interest and the simple interest on ₹4600 at 20% per year for 2 years (in ₹)?
16. 16.What is the difference between the compound interest and the simple interest on ₹36900 at 10% per year for 2 years (in ₹)?
17. 17.Find the compound interest on ₹14900 at 8% per year for 1 year, compounded every year (in ₹).
18. 18.Find the compound interest on ₹16000 at 15% per year for 3 years, compounded every year (in ₹).
19. 19.What amount will ₹32000 grow to in 3 years at 15% per year compound interest (in ₹)?
20. 20.What is the difference between the compound interest and the simple interest on ₹34000 at 25% per year for 2 years (in ₹)?
21. 21.Find the compound interest on ₹10000 at 20% per year for 1 year, compounded every year (in ₹).
22. 22.A town has 49600 people. The population grows by 12% every year. What will the population be after 1 year?
23. 23.A town has 59700 people. The population grows by 8% every year. What will the population be after 1 year?
24. 24.What amount will ₹24000 grow to in 3 years at 5% per year compound interest (in ₹)?
25. 25.What is the difference between the compound interest and the simple interest on ₹41200 at 5% per year for 2 years (in ₹)?
26. 26.What amount will ₹12600 grow to in 1 year at 12% per year compound interest (in ₹)?
27. 27.A town has 31600 people. The population grows by 5% every year. What will the population be after 2 years?
28. 28.What is the difference between the compound interest and the simple interest on ₹10000 at 5% per year for 2 years (in ₹)?
29. 29.Find the compound interest on ₹16000 at 20% per year for 3 years, compounded every year (in ₹).
30. 30.What amount will ₹7200 grow to in 2 years at 25% per year compound interest (in ₹)?
31. 31.Find the compound interest on ₹8000 at 15% per year for 3 years, compounded every year (in ₹).
32. 32.What is the difference between the compound interest and the simple interest on ₹22500 at 8% per year for 2 years (in ₹)?
33. 33.What is the difference between the compound interest and the simple interest on ₹60000 at 8% per year for 2 years (in ₹)?
34. 34.What amount will ₹8000 grow to in 3 years at 10% per year compound interest (in ₹)?
35. 35.What is the difference between the compound interest and the simple interest on ₹4500 at 10% per year for 2 years (in ₹)?
36. 36.A town has 4500 people. The population grows by 10% every year. What will the population be after 1 year?
37. 37.Find the compound interest on ₹24000 at 15% per year for 3 years, compounded every year (in ₹).
38. 38.What amount will ₹20200 grow to in 1 year at 8% per year compound interest (in ₹)?
39. 39.What amount will ₹5300 grow to in 1 year at 5% per year compound interest (in ₹)?
40. 40.What amount will ₹22500 grow to in 2 years at 12% per year compound interest (in ₹)?

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