Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 151 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What is the difference between the compound interest and the simple interest on ₹27500 at 12% per year for 2 years (in ₹)?
2. 2.A scooter is worth ₹25400. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
3. 3.What amount will ₹9200 grow to in 2 years at 5% per year compound interest (in ₹)?
4. 4.A town has 10000 people. The population grows by 8% every year. What will the population be after 2 years?
5. 5.Find the compound interest on ₹56500 at 20% per year for 3 years, compounded every year (in ₹).
6. 6.What is the difference between the compound interest and the simple interest on ₹37500 at 4% per year for 2 years (in ₹)?
7. 7.What is the difference between the compound interest and the simple interest on ₹8400 at 15% per year for 2 years (in ₹)?
8. 8.What amount will ₹25100 grow to in 1 year at 20% per year compound interest (in ₹)?
9. 9.What amount will ₹54500 grow to in 2 years at 20% per year compound interest (in ₹)?
10. 10.A scooter is worth ₹31900. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
11. 11.What amount will ₹12500 grow to in 2 years at 12% per year compound interest (in ₹)?
12. 12.What amount will ₹10800 grow to in 2 years at 25% per year compound interest (in ₹)?
13. 13.A town has 35000 people. The population grows by 10% every year. What will the population be after 3 years?
14. 14.Find the compound interest on ₹39000 at 10% per year for 3 years, compounded every year (in ₹).
15. 15.What amount will ₹59800 grow to in 1 year at 25% per year compound interest (in ₹)?
16. 16.What amount will ₹55000 grow to in 3 years at 20% per year compound interest (in ₹)?
17. 17.Find the compound interest on ₹10000 at 4% per year for 1 year, compounded every year (in ₹).
18. 18.Find the compound interest on ₹49500 at 10% per year for 1 year, compounded every year (in ₹).
19. 19.A town has 20200 people. The population grows by 15% every year. What will the population be after 1 year?
20. 20.A scooter is worth ₹6100. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
21. 21.Find the compound interest on ₹3500 at 10% per year for 1 year, compounded every year (in ₹).
22. 22.What is the difference between the compound interest and the simple interest on ₹4400 at 25% per year for 2 years (in ₹)?
23. 23.A town has 52500 people. The population grows by 20% every year. What will the population be after 3 years?
24. 24.A town has 52500 people. The population grows by 4% every year. What will the population be after 1 year?
25. 25.What amount will ₹28000 grow to in 3 years at 20% per year compound interest (in ₹)?
26. 26.What amount will ₹56000 grow to in 3 years at 5% per year compound interest (in ₹)?
27. 27.What amount will ₹7000 grow to in 3 years at 10% per year compound interest (in ₹)?
28. 28.A town has 24400 people. The population grows by 5% every year. What will the population be after 2 years?
29. 29.What amount will ₹50700 grow to in 1 year at 4% per year compound interest (in ₹)?
30. 30.A scooter is worth ₹39900. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
31. 31.Find the compound interest on ₹25600 at 25% per year for 3 years, compounded every year (in ₹).
32. 32.What amount will ₹35000 grow to in 2 years at 4% per year compound interest (in ₹)?
33. 33.What is the difference between the compound interest and the simple interest on ₹22900 at 10% per year for 2 years (in ₹)?
34. 34.Find the compound interest on ₹43600 at 25% per year for 2 years, compounded every year (in ₹).
35. 35.What is the difference between the compound interest and the simple interest on ₹34300 at 10% per year for 2 years (in ₹)?
36. 36.What is the difference between the compound interest and the simple interest on ₹24000 at 25% per year for 2 years (in ₹)?
37. 37.What amount will ₹44000 grow to in 1 year at 10% per year compound interest (in ₹)?
38. 38.A town has 34400 people. The population grows by 25% every year. What will the population be after 2 years?
39. 39.What amount will ₹19800 grow to in 2 years at 10% per year compound interest (in ₹)?
40. 40.A scooter is worth ₹49600. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?

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