Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.What amount will ₹4800 grow to in 3 years at 25% per year compound interest (in ₹)?
- 2.What amount will ₹36900 grow to in 1 year at 10% per year compound interest (in ₹)?
- 3.What is the difference between the compound interest and the simple interest on ₹25000 at 4% per year for 2 years (in ₹)?
- 4.Find the compound interest on ₹16000 at 5% per year for 3 years, compounded every year (in ₹).
- 5.What amount will ₹28300 grow to in 1 year at 10% per year compound interest (in ₹)?
- 6.What is the difference between the compound interest and the simple interest on ₹27500 at 4% per year for 2 years (in ₹)?
- 7.What amount will ₹56000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 8.Find the compound interest on ₹50000 at 8% per year for 2 years, compounded every year (in ₹).
- 9.Find the compound interest on ₹2000 at 20% per year for 3 years, compounded every year (in ₹).
- 10.What is the difference between the compound interest and the simple interest on ₹2000 at 25% per year for 2 years (in ₹)?
- 11.Find the compound interest on ₹1600 at 25% per year for 3 years, compounded every year (in ₹).
- 12.A town has 42000 people. The population grows by 20% every year. What will the population be after 3 years?
- 13.Find the compound interest on ₹22100 at 5% per year for 1 year, compounded every year (in ₹).
- 14.What is the difference between the compound interest and the simple interest on ₹37500 at 8% per year for 2 years (in ₹)?
- 15.Find the compound interest on ₹5800 at 15% per year for 1 year, compounded every year (in ₹).
- 16.Find the compound interest on ₹14000 at 5% per year for 2 years, compounded every year (in ₹).
- 17.What is the difference between the compound interest and the simple interest on ₹59000 at 10% per year for 2 years (in ₹)?
- 18.What is the difference between the compound interest and the simple interest on ₹10800 at 5% per year for 2 years (in ₹)?
- 19.What amount will ₹21600 grow to in 2 years at 5% per year compound interest (in ₹)?
- 20.Find the compound interest on ₹13600 at 25% per year for 2 years, compounded every year (in ₹).
- 21.Find the compound interest on ₹59900 at 10% per year for 2 years, compounded every year (in ₹).
- 22.What amount will ₹10000 grow to in 2 years at 12% per year compound interest (in ₹)?
- 23.A town has 4800 people. The population grows by 5% every year. What will the population be after 2 years?
- 24.What amount will ₹2400 grow to in 2 years at 5% per year compound interest (in ₹)?
- 25.What amount will ₹58200 grow to in 1 year at 20% per year compound interest (in ₹)?
- 26.A scooter is worth ₹26000. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
- 27.What amount will ₹8000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 28.Find the compound interest on ₹27800 at 12% per year for 1 year, compounded every year (in ₹).
- 29.Find the compound interest on ₹22100 at 12% per year for 1 year, compounded every year (in ₹).
- 30.Find the compound interest on ₹56000 at 5% per year for 3 years, compounded every year (in ₹).
- 31.Find the compound interest on ₹2900 at 20% per year for 1 year, compounded every year (in ₹).
- 32.What amount will ₹17600 grow to in 2 years at 15% per year compound interest (in ₹)?
- 33.What amount will ₹51200 grow to in 2 years at 25% per year compound interest (in ₹)?
- 34.Find the compound interest on ₹27900 at 8% per year for 1 year, compounded every year (in ₹).
- 35.What amount will ₹2600 grow to in 2 years at 10% per year compound interest (in ₹)?
- 36.Find the compound interest on ₹8000 at 15% per year for 3 years, compounded every year (in ₹).
- 37.Find the compound interest on ₹10000 at 10% per year for 3 years, compounded every year (in ₹).
- 38.Find the compound interest on ₹18100 at 10% per year for 2 years, compounded every year (in ₹).
- 39.Find the compound interest on ₹22500 at 12% per year for 2 years, compounded every year (in ₹).
- 40.A town has 33600 people. The population grows by 10% every year. What will the population be after 1 year?
Answer key
- 9375
- 40590
- 40
- 2522
- 31130
- 44
- 64827
- 8320
- 1456
- 125
- 1525
- 72576
- 1105
- 240
- 870
- 1435
- 590
- 27
- 23814
- 7650
- 12579
- 12544
- 5292
- 2646
- 69840
- 21060
- 9261
- 3336
- 2652
- 8827
- 580
- 23276
- 80000
- 2232
- 3146
- 4167
- 3310
- 3801
- 5724
- 36960
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