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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 158 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What amount will ₹25000 grow to in 1 year at 20% per year compound interest (in ₹)?
  2. 2.Find the compound interest on ₹21000 at 20% per year for 1 year, compounded every year (in ₹).
  3. 3.Find the compound interest on ₹10000 at 15% per year for 1 year, compounded every year (in ₹).
  4. 4.A scooter is worth ₹50300. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
  5. 5.What is the difference between the compound interest and the simple interest on ₹16500 at 20% per year for 2 years (in ₹)?
  6. 6.What amount will ₹20600 grow to in 2 years at 10% per year compound interest (in ₹)?
  7. 7.What amount will ₹56000 grow to in 3 years at 15% per year compound interest (in ₹)?
  8. 8.A town has 32000 people. The population grows by 15% every year. What will the population be after 3 years?
  9. 9.What is the difference between the compound interest and the simple interest on ₹41300 at 10% per year for 2 years (in ₹)?
  10. 10.What is the difference between the compound interest and the simple interest on ₹17200 at 15% per year for 2 years (in ₹)?
  11. 11.What amount will ₹18000 grow to in 1 year at 15% per year compound interest (in ₹)?
  12. 12.What is the difference between the compound interest and the simple interest on ₹35000 at 12% per year for 2 years (in ₹)?
  13. 13.A scooter is worth ₹16000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
  14. 14.Find the compound interest on ₹3200 at 25% per year for 1 year, compounded every year (in ₹).
  15. 15.A town has 8000 people. The population grows by 5% every year. What will the population be after 3 years?
  16. 16.What is the difference between the compound interest and the simple interest on ₹52500 at 12% per year for 2 years (in ₹)?
  17. 17.Find the compound interest on ₹43600 at 4% per year for 1 year, compounded every year (in ₹).
  18. 18.Find the compound interest on ₹57500 at 12% per year for 2 years, compounded every year (in ₹).
  19. 19.What amount will ₹17400 grow to in 1 year at 15% per year compound interest (in ₹)?
  20. 20.What amount will ₹8000 grow to in 3 years at 5% per year compound interest (in ₹)?
  21. 21.Find the compound interest on ₹46400 at 15% per year for 2 years, compounded every year (in ₹).
  22. 22.Find the compound interest on ₹13000 at 10% per year for 3 years, compounded every year (in ₹).
  23. 23.What is the difference between the compound interest and the simple interest on ₹5000 at 4% per year for 2 years (in ₹)?
  24. 24.A town has 4200 people. The population grows by 12% every year. What will the population be after 1 year?
  25. 25.Find the compound interest on ₹21700 at 10% per year for 1 year, compounded every year (in ₹).
  26. 26.What is the difference between the compound interest and the simple interest on ₹24400 at 25% per year for 2 years (in ₹)?
  27. 27.What amount will ₹33600 grow to in 3 years at 25% per year compound interest (in ₹)?
  28. 28.What amount will ₹8000 grow to in 2 years at 10% per year compound interest (in ₹)?
  29. 29.Find the compound interest on ₹18000 at 10% per year for 1 year, compounded every year (in ₹).
  30. 30.What amount will ₹21600 grow to in 2 years at 5% per year compound interest (in ₹)?
  31. 31.What is the difference between the compound interest and the simple interest on ₹17500 at 12% per year for 2 years (in ₹)?
  32. 32.What is the difference between the compound interest and the simple interest on ₹55500 at 10% per year for 2 years (in ₹)?
  33. 33.A town has 20500 people. The population grows by 10% every year. What will the population be after 2 years?
  34. 34.Find the compound interest on ₹27600 at 10% per year for 1 year, compounded every year (in ₹).
  35. 35.What amount will ₹30600 grow to in 1 year at 20% per year compound interest (in ₹)?
  36. 36.What amount will ₹30900 grow to in 1 year at 5% per year compound interest (in ₹)?
  37. 37.What amount will ₹22500 grow to in 1 year at 4% per year compound interest (in ₹)?
  38. 38.Find the compound interest on ₹27700 at 8% per year for 1 year, compounded every year (in ₹).
  39. 39.A scooter is worth ₹11600. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
  40. 40.A town has 60000 people. The population grows by 4% every year. What will the population be after 2 years?

Answer key

  1. 30000
  2. 4200
  3. 1500
  4. 45270
  5. 660
  6. 24926
  7. 85169
  8. 48668
  9. 413
  10. 387
  11. 20700
  12. 504
  13. 13718
  14. 800
  15. 9261
  16. 756
  17. 1744
  18. 14628
  19. 20010
  20. 9261
  21. 14964
  22. 4303
  23. 8
  24. 4704
  25. 2170
  26. 1525
  27. 65625
  28. 9680
  29. 1800
  30. 23814
  31. 252
  32. 555
  33. 24805
  34. 2760
  35. 36720
  36. 32445
  37. 23400
  38. 2216
  39. 10469
  40. 64896

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