Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.What is the difference between the compound interest and the simple interest on ₹41800 at 10% per year for 2 years (in ₹)?
- 2.What is the difference between the compound interest and the simple interest on ₹51700 at 10% per year for 2 years (in ₹)?
- 3.Find the compound interest on ₹22200 at 20% per year for 2 years, compounded every year (in ₹).
- 4.What is the difference between the compound interest and the simple interest on ₹16100 at 10% per year for 2 years (in ₹)?
- 5.What amount will ₹7500 grow to in 2 years at 12% per year compound interest (in ₹)?
- 6.A scooter is worth ₹6000. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
- 7.What is the difference between the compound interest and the simple interest on ₹12100 at 20% per year for 2 years (in ₹)?
- 8.What amount will ₹26000 grow to in 3 years at 10% per year compound interest (in ₹)?
- 9.What amount will ₹8000 grow to in 3 years at 25% per year compound interest (in ₹)?
- 10.What amount will ₹48000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 11.What is the difference between the compound interest and the simple interest on ₹33600 at 15% per year for 2 years (in ₹)?
- 12.What amount will ₹56000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 13.What is the difference between the compound interest and the simple interest on ₹16000 at 15% per year for 2 years (in ₹)?
- 14.What amount will ₹50100 grow to in 1 year at 12% per year compound interest (in ₹)?
- 15.What amount will ₹28000 grow to in 3 years at 20% per year compound interest (in ₹)?
- 16.Find the compound interest on ₹32200 at 8% per year for 1 year, compounded every year (in ₹).
- 17.A town has 30800 people. The population grows by 20% every year. What will the population be after 2 years?
- 18.What amount will ₹49200 grow to in 1 year at 15% per year compound interest (in ₹)?
- 19.Find the compound interest on ₹17500 at 8% per year for 1 year, compounded every year (in ₹).
- 20.A scooter is worth ₹49000. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
- 21.A town has 14400 people. The population grows by 5% every year. What will the population be after 2 years?
- 22.What is the difference between the compound interest and the simple interest on ₹57200 at 15% per year for 2 years (in ₹)?
- 23.A scooter is worth ₹51100. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
- 24.What amount will ₹55800 grow to in 1 year at 10% per year compound interest (in ₹)?
- 25.A town has 58000 people. The population grows by 10% every year. What will the population be after 3 years?
- 26.A town has 16000 people. The population grows by 5% every year. What will the population be after 3 years?
- 27.Find the compound interest on ₹39400 at 8% per year for 1 year, compounded every year (in ₹).
- 28.What amount will ₹16000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 29.What is the difference between the compound interest and the simple interest on ₹6800 at 25% per year for 2 years (in ₹)?
- 30.What is the difference between the compound interest and the simple interest on ₹30000 at 4% per year for 2 years (in ₹)?
- 31.What is the difference between the compound interest and the simple interest on ₹24800 at 5% per year for 2 years (in ₹)?
- 32.What is the difference between the compound interest and the simple interest on ₹57500 at 8% per year for 2 years (in ₹)?
- 33.What amount will ₹35100 grow to in 1 year at 20% per year compound interest (in ₹)?
- 34.A town has 19200 people. The population grows by 25% every year. What will the population be after 2 years?
- 35.Find the compound interest on ₹41600 at 25% per year for 3 years, compounded every year (in ₹).
- 36.Find the compound interest on ₹56000 at 5% per year for 3 years, compounded every year (in ₹).
- 37.What is the difference between the compound interest and the simple interest on ₹37100 at 10% per year for 2 years (in ₹)?
- 38.What amount will ₹50000 grow to in 3 years at 10% per year compound interest (in ₹)?
- 39.Find the compound interest on ₹55000 at 10% per year for 3 years, compounded every year (in ₹).
- 40.What amount will ₹14000 grow to in 2 years at 10% per year compound interest (in ₹)?
Answer key
- 418
- 517
- 9768
- 161
- 9408
- 4335
- 484
- 34606
- 15625
- 55566
- 756
- 64827
- 360
- 56112
- 48384
- 2576
- 44352
- 56580
- 1400
- 41650
- 15876
- 1287
- 38325
- 61380
- 77198
- 18522
- 3152
- 18522
- 425
- 48
- 62
- 368
- 42120
- 30000
- 39650
- 8827
- 371
- 66550
- 18205
- 16940
Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets