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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 163 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What is the difference between the compound interest and the simple interest on ₹41800 at 10% per year for 2 years (in ₹)?
  2. 2.What is the difference between the compound interest and the simple interest on ₹51700 at 10% per year for 2 years (in ₹)?
  3. 3.Find the compound interest on ₹22200 at 20% per year for 2 years, compounded every year (in ₹).
  4. 4.What is the difference between the compound interest and the simple interest on ₹16100 at 10% per year for 2 years (in ₹)?
  5. 5.What amount will ₹7500 grow to in 2 years at 12% per year compound interest (in ₹)?
  6. 6.A scooter is worth ₹6000. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
  7. 7.What is the difference between the compound interest and the simple interest on ₹12100 at 20% per year for 2 years (in ₹)?
  8. 8.What amount will ₹26000 grow to in 3 years at 10% per year compound interest (in ₹)?
  9. 9.What amount will ₹8000 grow to in 3 years at 25% per year compound interest (in ₹)?
  10. 10.What amount will ₹48000 grow to in 3 years at 5% per year compound interest (in ₹)?
  11. 11.What is the difference between the compound interest and the simple interest on ₹33600 at 15% per year for 2 years (in ₹)?
  12. 12.What amount will ₹56000 grow to in 3 years at 5% per year compound interest (in ₹)?
  13. 13.What is the difference between the compound interest and the simple interest on ₹16000 at 15% per year for 2 years (in ₹)?
  14. 14.What amount will ₹50100 grow to in 1 year at 12% per year compound interest (in ₹)?
  15. 15.What amount will ₹28000 grow to in 3 years at 20% per year compound interest (in ₹)?
  16. 16.Find the compound interest on ₹32200 at 8% per year for 1 year, compounded every year (in ₹).
  17. 17.A town has 30800 people. The population grows by 20% every year. What will the population be after 2 years?
  18. 18.What amount will ₹49200 grow to in 1 year at 15% per year compound interest (in ₹)?
  19. 19.Find the compound interest on ₹17500 at 8% per year for 1 year, compounded every year (in ₹).
  20. 20.A scooter is worth ₹49000. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
  21. 21.A town has 14400 people. The population grows by 5% every year. What will the population be after 2 years?
  22. 22.What is the difference between the compound interest and the simple interest on ₹57200 at 15% per year for 2 years (in ₹)?
  23. 23.A scooter is worth ₹51100. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
  24. 24.What amount will ₹55800 grow to in 1 year at 10% per year compound interest (in ₹)?
  25. 25.A town has 58000 people. The population grows by 10% every year. What will the population be after 3 years?
  26. 26.A town has 16000 people. The population grows by 5% every year. What will the population be after 3 years?
  27. 27.Find the compound interest on ₹39400 at 8% per year for 1 year, compounded every year (in ₹).
  28. 28.What amount will ₹16000 grow to in 3 years at 5% per year compound interest (in ₹)?
  29. 29.What is the difference between the compound interest and the simple interest on ₹6800 at 25% per year for 2 years (in ₹)?
  30. 30.What is the difference between the compound interest and the simple interest on ₹30000 at 4% per year for 2 years (in ₹)?
  31. 31.What is the difference between the compound interest and the simple interest on ₹24800 at 5% per year for 2 years (in ₹)?
  32. 32.What is the difference between the compound interest and the simple interest on ₹57500 at 8% per year for 2 years (in ₹)?
  33. 33.What amount will ₹35100 grow to in 1 year at 20% per year compound interest (in ₹)?
  34. 34.A town has 19200 people. The population grows by 25% every year. What will the population be after 2 years?
  35. 35.Find the compound interest on ₹41600 at 25% per year for 3 years, compounded every year (in ₹).
  36. 36.Find the compound interest on ₹56000 at 5% per year for 3 years, compounded every year (in ₹).
  37. 37.What is the difference between the compound interest and the simple interest on ₹37100 at 10% per year for 2 years (in ₹)?
  38. 38.What amount will ₹50000 grow to in 3 years at 10% per year compound interest (in ₹)?
  39. 39.Find the compound interest on ₹55000 at 10% per year for 3 years, compounded every year (in ₹).
  40. 40.What amount will ₹14000 grow to in 2 years at 10% per year compound interest (in ₹)?

Answer key

  1. 418
  2. 517
  3. 9768
  4. 161
  5. 9408
  6. 4335
  7. 484
  8. 34606
  9. 15625
  10. 55566
  11. 756
  12. 64827
  13. 360
  14. 56112
  15. 48384
  16. 2576
  17. 44352
  18. 56580
  19. 1400
  20. 41650
  21. 15876
  22. 1287
  23. 38325
  24. 61380
  25. 77198
  26. 18522
  27. 3152
  28. 18522
  29. 425
  30. 48
  31. 62
  32. 368
  33. 42120
  34. 30000
  35. 39650
  36. 8827
  37. 371
  38. 66550
  39. 18205
  40. 16940

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