Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
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- 1.What is the difference between the compound interest and the simple interest on ₹38400 at 5% per year for 2 years (in ₹)?
- 2.What is the difference between the compound interest and the simple interest on ₹12500 at 12% per year for 2 years (in ₹)?
- 3.What is the difference between the compound interest and the simple interest on ₹36400 at 5% per year for 2 years (in ₹)?
- 4.What is the difference between the compound interest and the simple interest on ₹12000 at 20% per year for 2 years (in ₹)?
- 5.What is the difference between the compound interest and the simple interest on ₹6800 at 15% per year for 2 years (in ₹)?
- 6.Find the compound interest on ₹10500 at 20% per year for 3 years, compounded every year (in ₹).
- 7.Find the compound interest on ₹43200 at 25% per year for 3 years, compounded every year (in ₹).
- 8.A town has 44700 people. The population grows by 8% every year. What will the population be after 1 year?
- 9.What is the difference between the compound interest and the simple interest on ₹57500 at 8% per year for 2 years (in ₹)?
- 10.What amount will ₹11200 grow to in 3 years at 25% per year compound interest (in ₹)?
- 11.Find the compound interest on ₹56000 at 15% per year for 3 years, compounded every year (in ₹).
- 12.A scooter is worth ₹2500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
- 13.What amount will ₹39200 grow to in 2 years at 5% per year compound interest (in ₹)?
- 14.Find the compound interest on ₹48600 at 5% per year for 1 year, compounded every year (in ₹).
- 15.What amount will ₹6800 grow to in 1 year at 15% per year compound interest (in ₹)?
- 16.A scooter is worth ₹12500. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
- 17.What is the difference between the compound interest and the simple interest on ₹34800 at 5% per year for 2 years (in ₹)?
- 18.What amount will ₹25000 grow to in 2 years at 4% per year compound interest (in ₹)?
- 19.Find the compound interest on ₹24000 at 5% per year for 3 years, compounded every year (in ₹).
- 20.What amount will ₹49500 grow to in 1 year at 10% per year compound interest (in ₹)?
- 21.Find the compound interest on ₹36000 at 10% per year for 3 years, compounded every year (in ₹).
- 22.What amount will ₹22600 grow to in 1 year at 25% per year compound interest (in ₹)?
- 23.What amount will ₹60000 grow to in 2 years at 8% per year compound interest (in ₹)?
- 24.What is the difference between the compound interest and the simple interest on ₹60000 at 8% per year for 2 years (in ₹)?
- 25.Find the compound interest on ₹50500 at 15% per year for 1 year, compounded every year (in ₹).
- 26.What is the difference between the compound interest and the simple interest on ₹28100 at 20% per year for 2 years (in ₹)?
- 27.What is the difference between the compound interest and the simple interest on ₹32000 at 5% per year for 2 years (in ₹)?
- 28.What is the difference between the compound interest and the simple interest on ₹24800 at 15% per year for 2 years (in ₹)?
- 29.A town has 12500 people. The population grows by 4% every year. What will the population be after 2 years?
- 30.A scooter is worth ₹49200. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
- 31.What is the difference between the compound interest and the simple interest on ₹35000 at 10% per year for 2 years (in ₹)?
- 32.A scooter is worth ₹22500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
- 33.A town has 49600 people. The population grows by 5% every year. What will the population be after 2 years?
- 34.A scooter is worth ₹52800. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
- 35.Find the compound interest on ₹40000 at 15% per year for 3 years, compounded every year (in ₹).
- 36.A scooter is worth ₹5000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
- 37.What amount will ₹35800 grow to in 1 year at 10% per year compound interest (in ₹)?
- 38.Find the compound interest on ₹60000 at 12% per year for 2 years, compounded every year (in ₹).
- 39.What is the difference between the compound interest and the simple interest on ₹54000 at 25% per year for 2 years (in ₹)?
- 40.What amount will ₹18800 grow to in 2 years at 20% per year compound interest (in ₹)?
Answer key
- 96
- 180
- 91
- 480
- 153
- 7644
- 41175
- 48276
- 368
- 21875
- 29169
- 1936
- 43218
- 2430
- 7820
- 10125
- 87
- 27040
- 3783
- 54450
- 11916
- 28250
- 69984
- 384
- 7575
- 1124
- 80
- 558
- 13520
- 35547
- 350
- 17424
- 54684
- 38148
- 20835
- 4232
- 39380
- 15264
- 3375
- 27072
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