Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.What is the difference between the compound interest and the simple interest on ₹10000 at 8% per year for 2 years (in ₹)?
- 2.A scooter is worth ₹18200. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
- 3.A scooter is worth ₹22500. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
- 4.What amount will ₹8000 grow to in 2 years at 5% per year compound interest (in ₹)?
- 5.What amount will ₹32000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 6.What amount will ₹31900 grow to in 1 year at 5% per year compound interest (in ₹)?
- 7.What amount will ₹5200 grow to in 2 years at 15% per year compound interest (in ₹)?
- 8.Find the compound interest on ₹55000 at 4% per year for 2 years, compounded every year (in ₹).
- 9.What amount will ₹11500 grow to in 3 years at 20% per year compound interest (in ₹)?
- 10.What is the difference between the compound interest and the simple interest on ₹42400 at 15% per year for 2 years (in ₹)?
- 11.What amount will ₹25000 grow to in 2 years at 12% per year compound interest (in ₹)?
- 12.What is the difference between the compound interest and the simple interest on ₹20800 at 15% per year for 2 years (in ₹)?
- 13.What amount will ₹57600 grow to in 2 years at 15% per year compound interest (in ₹)?
- 14.What is the difference between the compound interest and the simple interest on ₹47000 at 20% per year for 2 years (in ₹)?
- 15.What is the difference between the compound interest and the simple interest on ₹28000 at 15% per year for 2 years (in ₹)?
- 16.A town has 25300 people. The population grows by 10% every year. What will the population be after 2 years?
- 17.Find the compound interest on ₹14100 at 5% per year for 1 year, compounded every year (in ₹).
- 18.Find the compound interest on ₹8100 at 25% per year for 1 year, compounded every year (in ₹).
- 19.A town has 16000 people. The population grows by 25% every year. What will the population be after 3 years?
- 20.Find the compound interest on ₹16000 at 15% per year for 3 years, compounded every year (in ₹).
- 21.What amount will ₹2200 grow to in 1 year at 25% per year compound interest (in ₹)?
- 22.A town has 25000 people. The population grows by 10% every year. What will the population be after 3 years?
- 23.What amount will ₹36800 grow to in 3 years at 25% per year compound interest (in ₹)?
- 24.Find the compound interest on ₹17600 at 15% per year for 2 years, compounded every year (in ₹).
- 25.Find the compound interest on ₹11500 at 10% per year for 1 year, compounded every year (in ₹).
- 26.What is the difference between the compound interest and the simple interest on ₹60000 at 20% per year for 2 years (in ₹)?
- 27.What is the difference between the compound interest and the simple interest on ₹47800 at 20% per year for 2 years (in ₹)?
- 28.Find the compound interest on ₹15000 at 8% per year for 2 years, compounded every year (in ₹).
- 29.A scooter is worth ₹34500. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
- 30.Find the compound interest on ₹29900 at 8% per year for 1 year, compounded every year (in ₹).
- 31.Find the compound interest on ₹45200 at 15% per year for 2 years, compounded every year (in ₹).
- 32.What is the difference between the compound interest and the simple interest on ₹47500 at 4% per year for 2 years (in ₹)?
- 33.What is the difference between the compound interest and the simple interest on ₹45200 at 25% per year for 2 years (in ₹)?
- 34.A town has 33100 people. The population grows by 12% every year. What will the population be after 1 year?
- 35.Find the compound interest on ₹37000 at 20% per year for 3 years, compounded every year (in ₹).
- 36.Find the compound interest on ₹35000 at 4% per year for 2 years, compounded every year (in ₹).
- 37.What amount will ₹13600 grow to in 2 years at 15% per year compound interest (in ₹)?
- 38.What is the difference between the compound interest and the simple interest on ₹15000 at 12% per year for 2 years (in ₹)?
- 39.Find the compound interest on ₹19400 at 4% per year for 1 year, compounded every year (in ₹).
- 40.Find the compound interest on ₹34200 at 20% per year for 2 years, compounded every year (in ₹).
Answer key
- 64
- 16016
- 20736
- 8820
- 37044
- 33495
- 6877
- 4488
- 19872
- 954
- 31360
- 468
- 76176
- 1880
- 630
- 30613
- 705
- 2025
- 31250
- 8334
- 2750
- 33275
- 71875
- 5676
- 1150
- 2400
- 1912
- 2496
- 25875
- 2392
- 14577
- 76
- 2825
- 37072
- 26936
- 2856
- 17986
- 216
- 776
- 15048
Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets