Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 178 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹41400 at 20% per year for 2 years, compounded every year (in ₹).
2. 2.What is the difference between the compound interest and the simple interest on ₹56400 at 15% per year for 2 years (in ₹)?
3. 3.What amount will ₹6000 grow to in 1 year at 25% per year compound interest (in ₹)?
4. 4.Find the compound interest on ₹12500 at 12% per year for 2 years, compounded every year (in ₹).
5. 5.Find the compound interest on ₹8300 at 12% per year for 1 year, compounded every year (in ₹).
6. 6.Find the compound interest on ₹40900 at 12% per year for 1 year, compounded every year (in ₹).
7. 7.What amount will ₹50500 grow to in 1 year at 8% per year compound interest (in ₹)?
8. 8.Find the compound interest on ₹9500 at 4% per year for 1 year, compounded every year (in ₹).
9. 9.A town has 2400 people. The population grows by 25% every year. What will the population be after 1 year?
10. 10.A scooter is worth ₹21200. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
11. 11.Find the compound interest on ₹7500 at 12% per year for 2 years, compounded every year (in ₹).
12. 12.What amount will ₹13300 grow to in 1 year at 15% per year compound interest (in ₹)?
13. 13.What is the difference between the compound interest and the simple interest on ₹45000 at 12% per year for 2 years (in ₹)?
14. 14.A town has 8400 people. The population grows by 5% every year. What will the population be after 2 years?
15. 15.What is the difference between the compound interest and the simple interest on ₹46000 at 15% per year for 2 years (in ₹)?
16. 16.A scooter is worth ₹21300. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
17. 17.What amount will ₹8000 grow to in 3 years at 15% per year compound interest (in ₹)?
18. 18.Find the compound interest on ₹14100 at 5% per year for 1 year, compounded every year (in ₹).
19. 19.A town has 7500 people. The population grows by 4% every year. What will the population be after 2 years?
20. 20.Find the compound interest on ₹29000 at 10% per year for 1 year, compounded every year (in ₹).
21. 21.What is the difference between the compound interest and the simple interest on ₹3600 at 25% per year for 2 years (in ₹)?
22. 22.What is the difference between the compound interest and the simple interest on ₹18400 at 15% per year for 2 years (in ₹)?
23. 23.What is the difference between the compound interest and the simple interest on ₹55600 at 20% per year for 2 years (in ₹)?
24. 24.A town has 15200 people. The population grows by 10% every year. What will the population be after 2 years?
25. 25.A town has 55500 people. The population grows by 20% every year. What will the population be after 3 years?
26. 26.Find the compound interest on ₹27000 at 20% per year for 3 years, compounded every year (in ₹).
27. 27.Find the compound interest on ₹32000 at 10% per year for 3 years, compounded every year (in ₹).
28. 28.What is the difference between the compound interest and the simple interest on ₹47500 at 4% per year for 2 years (in ₹)?
29. 29.What amount will ₹32000 grow to in 3 years at 15% per year compound interest (in ₹)?
30. 30.What is the difference between the compound interest and the simple interest on ₹34800 at 25% per year for 2 years (in ₹)?
31. 31.What amount will ₹42300 grow to in 2 years at 20% per year compound interest (in ₹)?
32. 32.What is the difference between the compound interest and the simple interest on ₹31200 at 25% per year for 2 years (in ₹)?
33. 33.What amount will ₹12900 grow to in 1 year at 4% per year compound interest (in ₹)?
34. 34.What is the difference between the compound interest and the simple interest on ₹2500 at 12% per year for 2 years (in ₹)?
35. 35.What amount will ₹10900 grow to in 2 years at 10% per year compound interest (in ₹)?
36. 36.What amount will ₹20400 grow to in 2 years at 25% per year compound interest (in ₹)?
37. 37.What is the difference between the compound interest and the simple interest on ₹32500 at 4% per year for 2 years (in ₹)?
38. 38.A town has 32600 people. The population grows by 5% every year. What will the population be after 1 year?
39. 39.A scooter is worth ₹50000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
40. 40.A scooter is worth ₹30300. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?

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