Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.What amount will ₹32700 grow to in 1 year at 4% per year compound interest (in ₹)?
- 2.What amount will ₹10500 grow to in 1 year at 10% per year compound interest (in ₹)?
- 3.What is the difference between the compound interest and the simple interest on ₹8400 at 10% per year for 2 years (in ₹)?
- 4.Find the compound interest on ₹20400 at 5% per year for 2 years, compounded every year (in ₹).
- 5.Find the compound interest on ₹32000 at 5% per year for 3 years, compounded every year (in ₹).
- 6.What amount will ₹57500 grow to in 2 years at 20% per year compound interest (in ₹)?
- 7.What amount will ₹4500 grow to in 3 years at 20% per year compound interest (in ₹)?
- 8.What amount will ₹52500 grow to in 2 years at 8% per year compound interest (in ₹)?
- 9.A town has 17300 people. The population grows by 5% every year. What will the population be after 1 year?
- 10.Find the compound interest on ₹58800 at 15% per year for 1 year, compounded every year (in ₹).
- 11.What is the difference between the compound interest and the simple interest on ₹35000 at 12% per year for 2 years (in ₹)?
- 12.What is the difference between the compound interest and the simple interest on ₹37500 at 8% per year for 2 years (in ₹)?
- 13.What is the difference between the compound interest and the simple interest on ₹50000 at 12% per year for 2 years (in ₹)?
- 14.What is the difference between the compound interest and the simple interest on ₹8900 at 10% per year for 2 years (in ₹)?
- 15.What amount will ₹30400 grow to in 2 years at 25% per year compound interest (in ₹)?
- 16.A scooter is worth ₹19000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
- 17.What is the difference between the compound interest and the simple interest on ₹38400 at 25% per year for 2 years (in ₹)?
- 18.A town has 43700 people. The population grows by 12% every year. What will the population be after 1 year?
- 19.A town has 46000 people. The population grows by 20% every year. What will the population be after 1 year?
- 20.Find the compound interest on ₹43000 at 20% per year for 3 years, compounded every year (in ₹).
- 21.What amount will ₹46600 grow to in 1 year at 25% per year compound interest (in ₹)?
- 22.What is the difference between the compound interest and the simple interest on ₹20000 at 25% per year for 2 years (in ₹)?
- 23.Find the compound interest on ₹57500 at 4% per year for 2 years, compounded every year (in ₹).
- 24.Find the compound interest on ₹59000 at 20% per year for 3 years, compounded every year (in ₹).
- 25.Find the compound interest on ₹59300 at 5% per year for 1 year, compounded every year (in ₹).
- 26.Find the compound interest on ₹40000 at 12% per year for 2 years, compounded every year (in ₹).
- 27.What is the difference between the compound interest and the simple interest on ₹22600 at 10% per year for 2 years (in ₹)?
- 28.What is the difference between the compound interest and the simple interest on ₹19600 at 5% per year for 2 years (in ₹)?
- 29.What is the difference between the compound interest and the simple interest on ₹17800 at 20% per year for 2 years (in ₹)?
- 30.What is the difference between the compound interest and the simple interest on ₹27800 at 10% per year for 2 years (in ₹)?
- 31.What amount will ₹32400 grow to in 2 years at 5% per year compound interest (in ₹)?
- 32.A town has 7500 people. The population grows by 12% every year. What will the population be after 2 years?
- 33.Find the compound interest on ₹30200 at 10% per year for 1 year, compounded every year (in ₹).
- 34.A scooter is worth ₹15000. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
- 35.A town has 46700 people. The population grows by 10% every year. What will the population be after 1 year?
- 36.What amount will ₹2000 grow to in 2 years at 5% per year compound interest (in ₹)?
- 37.A town has 53800 people. The population grows by 4% every year. What will the population be after 1 year?
- 38.What amount will ₹21500 grow to in 1 year at 15% per year compound interest (in ₹)?
- 39.What amount will ₹27600 grow to in 2 years at 10% per year compound interest (in ₹)?
- 40.A town has 47500 people. The population grows by 8% every year. What will the population be after 2 years?
Answer key
- 34008
- 11550
- 84
- 2091
- 5044
- 82800
- 7776
- 61236
- 18165
- 8820
- 504
- 240
- 720
- 89
- 47500
- 13851
- 2400
- 48944
- 55200
- 31304
- 58250
- 1250
- 4692
- 42952
- 2965
- 10176
- 226
- 49
- 712
- 278
- 35721
- 9408
- 3020
- 13824
- 51370
- 2205
- 55952
- 24725
- 33396
- 55404
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