Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 184 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What amount will ₹24000 grow to in 3 years at 25% per year compound interest (in ₹)?
2. 2.What is the difference between the compound interest and the simple interest on ₹10400 at 5% per year for 2 years (in ₹)?
3. 3.What is the difference between the compound interest and the simple interest on ₹30000 at 12% per year for 2 years (in ₹)?
4. 4.Find the compound interest on ₹16000 at 25% per year for 3 years, compounded every year (in ₹).
5. 5.What is the difference between the compound interest and the simple interest on ₹41600 at 25% per year for 2 years (in ₹)?
6. 6.What amount will ₹7000 grow to in 3 years at 10% per year compound interest (in ₹)?
7. 7.What is the difference between the compound interest and the simple interest on ₹9700 at 10% per year for 2 years (in ₹)?
8. 8.What is the difference between the compound interest and the simple interest on ₹10000 at 8% per year for 2 years (in ₹)?
9. 9.Find the compound interest on ₹5400 at 15% per year for 1 year, compounded every year (in ₹).
10. 10.A town has 60000 people. The population grows by 8% every year. What will the population be after 2 years?
11. 11.What is the difference between the compound interest and the simple interest on ₹16000 at 15% per year for 2 years (in ₹)?
12. 12.A town has 35200 people. The population grows by 25% every year. What will the population be after 3 years?
13. 13.What is the difference between the compound interest and the simple interest on ₹42500 at 4% per year for 2 years (in ₹)?
14. 14.What amount will ₹13600 grow to in 2 years at 5% per year compound interest (in ₹)?
15. 15.Find the compound interest on ₹26800 at 25% per year for 2 years, compounded every year (in ₹).
16. 16.Find the compound interest on ₹50700 at 5% per year for 1 year, compounded every year (in ₹).
17. 17.What amount will ₹18100 grow to in 1 year at 5% per year compound interest (in ₹)?
18. 18.A scooter is worth ₹5000. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
19. 19.What is the difference between the compound interest and the simple interest on ₹53900 at 20% per year for 2 years (in ₹)?
20. 20.What is the difference between the compound interest and the simple interest on ₹7500 at 20% per year for 2 years (in ₹)?
21. 21.A scooter is worth ₹2500. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
22. 22.A town has 10300 people. The population grows by 8% every year. What will the population be after 1 year?
23. 23.A scooter is worth ₹23700. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
24. 24.A town has 34400 people. The population grows by 5% every year. What will the population be after 2 years?
25. 25.What amount will ₹57200 grow to in 2 years at 25% per year compound interest (in ₹)?
26. 26.A scooter is worth ₹57500. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
27. 27.What amount will ₹21400 grow to in 1 year at 15% per year compound interest (in ₹)?
28. 28.What amount will ₹8000 grow to in 3 years at 15% per year compound interest (in ₹)?
29. 29.Find the compound interest on ₹26800 at 5% per year for 2 years, compounded every year (in ₹).
30. 30.A scooter is worth ₹11900. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
31. 31.What is the difference between the compound interest and the simple interest on ₹41200 at 5% per year for 2 years (in ₹)?
32. 32.Find the compound interest on ₹35200 at 25% per year for 3 years, compounded every year (in ₹).
33. 33.A scooter is worth ₹15000. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
34. 34.Find the compound interest on ₹56000 at 5% per year for 3 years, compounded every year (in ₹).
35. 35.What amount will ₹21000 grow to in 2 years at 10% per year compound interest (in ₹)?
36. 36.What amount will ₹52900 grow to in 1 year at 8% per year compound interest (in ₹)?
37. 37.A town has 30900 people. The population grows by 20% every year. What will the population be after 2 years?
38. 38.What is the difference between the compound interest and the simple interest on ₹24700 at 10% per year for 2 years (in ₹)?
39. 39.What is the difference between the compound interest and the simple interest on ₹7200 at 25% per year for 2 years (in ₹)?
40. 40.Find the compound interest on ₹37200 at 25% per year for 2 years, compounded every year (in ₹).

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