Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.Find the compound interest on ₹16000 at 15% per year for 3 years, compounded every year (in ₹).
- 2.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).
- 3.Find the compound interest on ₹26900 at 10% per year for 1 year, compounded every year (in ₹).
- 4.What amount will ₹10000 grow to in 2 years at 4% per year compound interest (in ₹)?
- 5.What amount will ₹40000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 6.What amount will ₹26800 grow to in 2 years at 5% per year compound interest (in ₹)?
- 7.A scooter is worth ₹3200. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
- 8.What amount will ₹60000 grow to in 2 years at 8% per year compound interest (in ₹)?
- 9.What is the difference between the compound interest and the simple interest on ₹50000 at 4% per year for 2 years (in ₹)?
- 10.A scooter is worth ₹7500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
- 11.Find the compound interest on ₹58300 at 25% per year for 1 year, compounded every year (in ₹).
- 12.A scooter is worth ₹15000. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
- 13.What amount will ₹50300 grow to in 1 year at 8% per year compound interest (in ₹)?
- 14.Find the compound interest on ₹24200 at 25% per year for 1 year, compounded every year (in ₹).
- 15.What is the difference between the compound interest and the simple interest on ₹60000 at 8% per year for 2 years (in ₹)?
- 16.Find the compound interest on ₹48000 at 5% per year for 3 years, compounded every year (in ₹).
- 17.Find the compound interest on ₹50100 at 10% per year for 2 years, compounded every year (in ₹).
- 18.A scooter is worth ₹11500. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
- 19.What amount will ₹13000 grow to in 1 year at 4% per year compound interest (in ₹)?
- 20.What is the difference between the compound interest and the simple interest on ₹31500 at 10% per year for 2 years (in ₹)?
- 21.What is the difference between the compound interest and the simple interest on ₹23400 at 10% per year for 2 years (in ₹)?
- 22.A town has 55000 people. The population grows by 4% every year. What will the population be after 2 years?
- 23.What amount will ₹41800 grow to in 1 year at 12% per year compound interest (in ₹)?
- 24.Find the compound interest on ₹29400 at 25% per year for 1 year, compounded every year (in ₹).
- 25.Find the compound interest on ₹5000 at 12% per year for 2 years, compounded every year (in ₹).
- 26.What amount will ₹42800 grow to in 1 year at 12% per year compound interest (in ₹)?
- 27.Find the compound interest on ₹56000 at 25% per year for 3 years, compounded every year (in ₹).
- 28.Find the compound interest on ₹3000 at 10% per year for 2 years, compounded every year (in ₹).
- 29.Find the compound interest on ₹7700 at 8% per year for 1 year, compounded every year (in ₹).
- 30.Find the compound interest on ₹5000 at 10% per year for 2 years, compounded every year (in ₹).
- 31.Find the compound interest on ₹30700 at 4% per year for 1 year, compounded every year (in ₹).
- 32.A scooter is worth ₹17500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
- 33.Find the compound interest on ₹24000 at 15% per year for 3 years, compounded every year (in ₹).
- 34.What is the difference between the compound interest and the simple interest on ₹45000 at 8% per year for 2 years (in ₹)?
- 35.What amount will ₹7500 grow to in 2 years at 4% per year compound interest (in ₹)?
- 36.Find the compound interest on ₹37500 at 20% per year for 1 year, compounded every year (in ₹).
- 37.Find the compound interest on ₹17900 at 20% per year for 2 years, compounded every year (in ₹).
- 38.What is the difference between the compound interest and the simple interest on ₹32500 at 4% per year for 2 years (in ₹)?
- 39.A town has 54000 people. The population grows by 10% every year. What will the population be after 3 years?
- 40.What is the difference between the compound interest and the simple interest on ₹12800 at 5% per year for 2 years (in ₹)?
Answer key
- 8334
- 6305
- 2690
- 10816
- 46305
- 29547
- 3040
- 69984
- 80
- 6348
- 14575
- 13824
- 54324
- 6050
- 384
- 7566
- 10521
- 11040
- 13520
- 315
- 234
- 59488
- 46816
- 7350
- 1272
- 47936
- 53375
- 630
- 616
- 1050
- 1228
- 13552
- 12501
- 288
- 8112
- 7500
- 7876
- 52
- 71874
- 32
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