Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 19 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What amount will ₹29700 grow to in 2 years at 20% per year compound interest (in ₹)?
2. 2.Find the compound interest on ₹23200 at 8% per year for 1 year, compounded every year (in ₹).
3. 3.What amount will ₹29000 grow to in 3 years at 10% per year compound interest (in ₹)?
4. 4.What is the difference between the compound interest and the simple interest on ₹33300 at 20% per year for 2 years (in ₹)?
5. 5.What is the difference between the compound interest and the simple interest on ₹41600 at 20% per year for 2 years (in ₹)?
6. 6.A scooter is worth ₹55200. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
7. 7.What is the difference between the compound interest and the simple interest on ₹25000 at 12% per year for 2 years (in ₹)?
8. 8.What is the difference between the compound interest and the simple interest on ₹17500 at 12% per year for 2 years (in ₹)?
9. 9.What amount will ₹31900 grow to in 1 year at 12% per year compound interest (in ₹)?
10. 10.What is the difference between the compound interest and the simple interest on ₹29600 at 25% per year for 2 years (in ₹)?
11. 11.A town has 42400 people. The population grows by 5% every year. What will the population be after 2 years?
12. 12.A scooter is worth ₹24000. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
13. 13.A town has 41000 people. The population grows by 20% every year. What will the population be after 2 years?
14. 14.What is the difference between the compound interest and the simple interest on ₹31200 at 5% per year for 2 years (in ₹)?
15. 15.Find the compound interest on ₹5900 at 12% per year for 1 year, compounded every year (in ₹).
16. 16.What is the difference between the compound interest and the simple interest on ₹20000 at 10% per year for 2 years (in ₹)?
17. 17.What is the difference between the compound interest and the simple interest on ₹29100 at 10% per year for 2 years (in ₹)?
18. 18.What amount will ₹50100 grow to in 2 years at 20% per year compound interest (in ₹)?
19. 19.Find the compound interest on ₹16600 at 20% per year for 1 year, compounded every year (in ₹).
20. 20.What amount will ₹7700 grow to in 1 year at 5% per year compound interest (in ₹)?
21. 21.What is the difference between the compound interest and the simple interest on ₹15000 at 8% per year for 2 years (in ₹)?
22. 22.Find the compound interest on ₹2700 at 5% per year for 1 year, compounded every year (in ₹).
23. 23.Find the compound interest on ₹27300 at 25% per year for 1 year, compounded every year (in ₹).
24. 24.What is the difference between the compound interest and the simple interest on ₹15000 at 4% per year for 2 years (in ₹)?
25. 25.A scooter is worth ₹24000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
26. 26.Find the compound interest on ₹44500 at 20% per year for 3 years, compounded every year (in ₹).
27. 27.What amount will ₹21800 grow to in 2 years at 20% per year compound interest (in ₹)?
28. 28.What is the difference between the compound interest and the simple interest on ₹6700 at 20% per year for 2 years (in ₹)?
29. 29.A town has 14600 people. The population grows by 4% every year. What will the population be after 1 year?
30. 30.What is the difference between the compound interest and the simple interest on ₹20800 at 5% per year for 2 years (in ₹)?
31. 31.A scooter is worth ₹10900. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
32. 32.Find the compound interest on ₹43600 at 25% per year for 2 years, compounded every year (in ₹).
33. 33.What is the difference between the compound interest and the simple interest on ₹10700 at 20% per year for 2 years (in ₹)?
34. 34.A town has 4000 people. The population grows by 25% every year. What will the population be after 2 years?
35. 35.Find the compound interest on ₹13700 at 4% per year for 1 year, compounded every year (in ₹).
36. 36.Find the compound interest on ₹18000 at 20% per year for 3 years, compounded every year (in ₹).
37. 37.A scooter is worth ₹25000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
38. 38.Find the compound interest on ₹48000 at 15% per year for 3 years, compounded every year (in ₹).
39. 39.Find the compound interest on ₹24000 at 5% per year for 3 years, compounded every year (in ₹).
40. 40.Find the compound interest on ₹50800 at 10% per year for 2 years, compounded every year (in ₹).

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