Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 192 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What amount will ₹19000 grow to in 3 years at 20% per year compound interest (in ₹)?
2. 2.A town has 42500 people. The population grows by 12% every year. What will the population be after 2 years?
3. 3.A town has 46400 people. The population grows by 10% every year. What will the population be after 2 years?
4. 4.Find the compound interest on ₹10400 at 15% per year for 2 years, compounded every year (in ₹).
5. 5.A town has 3200 people. The population grows by 15% every year. What will the population be after 2 years?
6. 6.Find the compound interest on ₹53000 at 10% per year for 1 year, compounded every year (in ₹).
7. 7.What is the difference between the compound interest and the simple interest on ₹30000 at 4% per year for 2 years (in ₹)?
8. 8.What is the difference between the compound interest and the simple interest on ₹2500 at 8% per year for 2 years (in ₹)?
9. 9.What is the difference between the compound interest and the simple interest on ₹36800 at 15% per year for 2 years (in ₹)?
10. 10.What amount will ₹57500 grow to in 2 years at 12% per year compound interest (in ₹)?
11. 11.A town has 55000 people. The population grows by 5% every year. What will the population be after 1 year?
12. 12.What is the difference between the compound interest and the simple interest on ₹21200 at 25% per year for 2 years (in ₹)?
13. 13.Find the compound interest on ₹14800 at 25% per year for 2 years, compounded every year (in ₹).
14. 14.What amount will ₹42100 grow to in 1 year at 10% per year compound interest (in ₹)?
15. 15.What is the difference between the compound interest and the simple interest on ₹22800 at 5% per year for 2 years (in ₹)?
16. 16.What is the difference between the compound interest and the simple interest on ₹19300 at 10% per year for 2 years (in ₹)?
17. 17.Find the compound interest on ₹32000 at 5% per year for 3 years, compounded every year (in ₹).
18. 18.A town has 40000 people. The population grows by 8% every year. What will the population be after 2 years?
19. 19.What is the difference between the compound interest and the simple interest on ₹60000 at 8% per year for 2 years (in ₹)?
20. 20.A town has 31500 people. The population grows by 10% every year. What will the population be after 1 year?
21. 21.What amount will ₹10000 grow to in 2 years at 8% per year compound interest (in ₹)?
22. 22.Find the compound interest on ₹30400 at 25% per year for 3 years, compounded every year (in ₹).
23. 23.A town has 52800 people. The population grows by 25% every year. What will the population be after 2 years?
24. 24.A scooter is worth ₹8000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
25. 25.What is the difference between the compound interest and the simple interest on ₹7500 at 12% per year for 2 years (in ₹)?
26. 26.Find the compound interest on ₹25000 at 4% per year for 2 years, compounded every year (in ₹).
27. 27.What is the difference between the compound interest and the simple interest on ₹57500 at 4% per year for 2 years (in ₹)?
28. 28.What is the difference between the compound interest and the simple interest on ₹17400 at 20% per year for 2 years (in ₹)?
29. 29.A scooter is worth ₹26000. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
30. 30.What amount will ₹38300 grow to in 1 year at 10% per year compound interest (in ₹)?
31. 31.A scooter is worth ₹56800. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
32. 32.What amount will ₹2800 grow to in 1 year at 15% per year compound interest (in ₹)?
33. 33.What amount will ₹44800 grow to in 2 years at 5% per year compound interest (in ₹)?
34. 34.A town has 56100 people. The population grows by 12% every year. What will the population be after 1 year?
35. 35.Find the compound interest on ₹46500 at 10% per year for 2 years, compounded every year (in ₹).
36. 36.A town has 13100 people. The population grows by 10% every year. What will the population be after 1 year?
37. 37.What amount will ₹40000 grow to in 3 years at 15% per year compound interest (in ₹)?
38. 38.A scooter is worth ₹48000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
39. 39.Find the compound interest on ₹10100 at 4% per year for 1 year, compounded every year (in ₹).
40. 40.What amount will ₹37900 grow to in 2 years at 20% per year compound interest (in ₹)?

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