Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.What is the difference between the compound interest and the simple interest on ₹4000 at 15% per year for 2 years (in ₹)?
- 2.Find the compound interest on ₹10000 at 10% per year for 3 years, compounded every year (in ₹).
- 3.What amount will ₹16000 grow to in 3 years at 15% per year compound interest (in ₹)?
- 4.What is the difference between the compound interest and the simple interest on ₹37500 at 12% per year for 2 years (in ₹)?
- 5.A scooter is worth ₹19000. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
- 6.What is the difference between the compound interest and the simple interest on ₹19200 at 25% per year for 2 years (in ₹)?
- 7.A town has 54600 people. The population grows by 4% every year. What will the population be after 1 year?
- 8.A town has 26400 people. The population grows by 5% every year. What will the population be after 2 years?
- 9.Find the compound interest on ₹7600 at 12% per year for 1 year, compounded every year (in ₹).
- 10.A scooter is worth ₹12000. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
- 11.Find the compound interest on ₹10000 at 12% per year for 2 years, compounded every year (in ₹).
- 12.What amount will ₹10200 grow to in 1 year at 4% per year compound interest (in ₹)?
- 13.Find the compound interest on ₹48000 at 5% per year for 3 years, compounded every year (in ₹).
- 14.What is the difference between the compound interest and the simple interest on ₹44000 at 25% per year for 2 years (in ₹)?
- 15.A scooter is worth ₹2800. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
- 16.Find the compound interest on ₹30400 at 25% per year for 3 years, compounded every year (in ₹).
- 17.A town has 10800 people. The population grows by 8% every year. What will the population be after 1 year?
- 18.What is the difference between the compound interest and the simple interest on ₹55000 at 12% per year for 2 years (in ₹)?
- 19.Find the compound interest on ₹39500 at 20% per year for 2 years, compounded every year (in ₹).
- 20.Find the compound interest on ₹27500 at 20% per year for 1 year, compounded every year (in ₹).
- 21.A town has 9100 people. The population grows by 15% every year. What will the population be after 1 year?
- 22.A town has 36000 people. The population grows by 10% every year. What will the population be after 3 years?
- 23.What amount will ₹5000 grow to in 3 years at 20% per year compound interest (in ₹)?
- 24.What amount will ₹11000 grow to in 3 years at 10% per year compound interest (in ₹)?
- 25.Find the compound interest on ₹6900 at 10% per year for 2 years, compounded every year (in ₹).
- 26.Find the compound interest on ₹30700 at 25% per year for 1 year, compounded every year (in ₹).
- 27.What is the difference between the compound interest and the simple interest on ₹46100 at 10% per year for 2 years (in ₹)?
- 28.What is the difference between the compound interest and the simple interest on ₹38900 at 20% per year for 2 years (in ₹)?
- 29.A town has 35000 people. The population grows by 10% every year. What will the population be after 2 years?
- 30.Find the compound interest on ₹8800 at 15% per year for 1 year, compounded every year (in ₹).
- 31.What amount will ₹54800 grow to in 2 years at 25% per year compound interest (in ₹)?
- 32.What is the difference between the compound interest and the simple interest on ₹48200 at 20% per year for 2 years (in ₹)?
- 33.Find the compound interest on ₹5000 at 10% per year for 3 years, compounded every year (in ₹).
- 34.Find the compound interest on ₹32900 at 25% per year for 1 year, compounded every year (in ₹).
- 35.What is the difference between the compound interest and the simple interest on ₹26800 at 20% per year for 2 years (in ₹)?
- 36.What amount will ₹48000 grow to in 2 years at 5% per year compound interest (in ₹)?
- 37.A scooter is worth ₹25000. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
- 38.What amount will ₹31500 grow to in 2 years at 10% per year compound interest (in ₹)?
- 39.A scooter is worth ₹24900. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
- 40.What amount will ₹46000 grow to in 3 years at 20% per year compound interest (in ₹)?
Answer key
- 90
- 3310
- 24334
- 540
- 12160
- 1200
- 56784
- 29106
- 912
- 8670
- 2544
- 10608
- 7566
- 2750
- 1575
- 28975
- 11664
- 792
- 17380
- 5500
- 10465
- 47916
- 8640
- 14641
- 1449
- 7675
- 461
- 1556
- 42350
- 1320
- 85625
- 1928
- 1655
- 8225
- 1072
- 52920
- 23750
- 38115
- 23904
- 79488
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