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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 198 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What is the difference between the compound interest and the simple interest on ₹4000 at 15% per year for 2 years (in ₹)?
  2. 2.Find the compound interest on ₹10000 at 10% per year for 3 years, compounded every year (in ₹).
  3. 3.What amount will ₹16000 grow to in 3 years at 15% per year compound interest (in ₹)?
  4. 4.What is the difference between the compound interest and the simple interest on ₹37500 at 12% per year for 2 years (in ₹)?
  5. 5.A scooter is worth ₹19000. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
  6. 6.What is the difference between the compound interest and the simple interest on ₹19200 at 25% per year for 2 years (in ₹)?
  7. 7.A town has 54600 people. The population grows by 4% every year. What will the population be after 1 year?
  8. 8.A town has 26400 people. The population grows by 5% every year. What will the population be after 2 years?
  9. 9.Find the compound interest on ₹7600 at 12% per year for 1 year, compounded every year (in ₹).
  10. 10.A scooter is worth ₹12000. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
  11. 11.Find the compound interest on ₹10000 at 12% per year for 2 years, compounded every year (in ₹).
  12. 12.What amount will ₹10200 grow to in 1 year at 4% per year compound interest (in ₹)?
  13. 13.Find the compound interest on ₹48000 at 5% per year for 3 years, compounded every year (in ₹).
  14. 14.What is the difference between the compound interest and the simple interest on ₹44000 at 25% per year for 2 years (in ₹)?
  15. 15.A scooter is worth ₹2800. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
  16. 16.Find the compound interest on ₹30400 at 25% per year for 3 years, compounded every year (in ₹).
  17. 17.A town has 10800 people. The population grows by 8% every year. What will the population be after 1 year?
  18. 18.What is the difference between the compound interest and the simple interest on ₹55000 at 12% per year for 2 years (in ₹)?
  19. 19.Find the compound interest on ₹39500 at 20% per year for 2 years, compounded every year (in ₹).
  20. 20.Find the compound interest on ₹27500 at 20% per year for 1 year, compounded every year (in ₹).
  21. 21.A town has 9100 people. The population grows by 15% every year. What will the population be after 1 year?
  22. 22.A town has 36000 people. The population grows by 10% every year. What will the population be after 3 years?
  23. 23.What amount will ₹5000 grow to in 3 years at 20% per year compound interest (in ₹)?
  24. 24.What amount will ₹11000 grow to in 3 years at 10% per year compound interest (in ₹)?
  25. 25.Find the compound interest on ₹6900 at 10% per year for 2 years, compounded every year (in ₹).
  26. 26.Find the compound interest on ₹30700 at 25% per year for 1 year, compounded every year (in ₹).
  27. 27.What is the difference between the compound interest and the simple interest on ₹46100 at 10% per year for 2 years (in ₹)?
  28. 28.What is the difference between the compound interest and the simple interest on ₹38900 at 20% per year for 2 years (in ₹)?
  29. 29.A town has 35000 people. The population grows by 10% every year. What will the population be after 2 years?
  30. 30.Find the compound interest on ₹8800 at 15% per year for 1 year, compounded every year (in ₹).
  31. 31.What amount will ₹54800 grow to in 2 years at 25% per year compound interest (in ₹)?
  32. 32.What is the difference between the compound interest and the simple interest on ₹48200 at 20% per year for 2 years (in ₹)?
  33. 33.Find the compound interest on ₹5000 at 10% per year for 3 years, compounded every year (in ₹).
  34. 34.Find the compound interest on ₹32900 at 25% per year for 1 year, compounded every year (in ₹).
  35. 35.What is the difference between the compound interest and the simple interest on ₹26800 at 20% per year for 2 years (in ₹)?
  36. 36.What amount will ₹48000 grow to in 2 years at 5% per year compound interest (in ₹)?
  37. 37.A scooter is worth ₹25000. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
  38. 38.What amount will ₹31500 grow to in 2 years at 10% per year compound interest (in ₹)?
  39. 39.A scooter is worth ₹24900. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
  40. 40.What amount will ₹46000 grow to in 3 years at 20% per year compound interest (in ₹)?

Answer key

  1. 90
  2. 3310
  3. 24334
  4. 540
  5. 12160
  6. 1200
  7. 56784
  8. 29106
  9. 912
  10. 8670
  11. 2544
  12. 10608
  13. 7566
  14. 2750
  15. 1575
  16. 28975
  17. 11664
  18. 792
  19. 17380
  20. 5500
  21. 10465
  22. 47916
  23. 8640
  24. 14641
  25. 1449
  26. 7675
  27. 461
  28. 1556
  29. 42350
  30. 1320
  31. 85625
  32. 1928
  33. 1655
  34. 8225
  35. 1072
  36. 52920
  37. 23750
  38. 38115
  39. 23904
  40. 79488

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