Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 206 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A town has 49000 people. The population grows by 10% every year. What will the population be after 3 years?
2. 2.What amount will ₹58900 grow to in 1 year at 15% per year compound interest (in ₹)?
3. 3.Find the compound interest on ₹42700 at 12% per year for 1 year, compounded every year (in ₹).
4. 4.A scooter is worth ₹3500. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
5. 5.What is the difference between the compound interest and the simple interest on ₹41600 at 5% per year for 2 years (in ₹)?
6. 6.What amount will ₹44100 grow to in 1 year at 20% per year compound interest (in ₹)?
7. 7.What is the difference between the compound interest and the simple interest on ₹52000 at 5% per year for 2 years (in ₹)?
8. 8.What amount will ₹5100 grow to in 1 year at 5% per year compound interest (in ₹)?
9. 9.A town has 40500 people. The population grows by 20% every year. What will the population be after 3 years?
10. 10.What is the difference between the compound interest and the simple interest on ₹30700 at 20% per year for 2 years (in ₹)?
11. 11.What is the difference between the compound interest and the simple interest on ₹28400 at 20% per year for 2 years (in ₹)?
12. 12.What amount will ₹25000 grow to in 2 years at 8% per year compound interest (in ₹)?
13. 13.What is the difference between the compound interest and the simple interest on ₹20000 at 12% per year for 2 years (in ₹)?
14. 14.What is the difference between the compound interest and the simple interest on ₹14100 at 10% per year for 2 years (in ₹)?
15. 15.What is the difference between the compound interest and the simple interest on ₹47500 at 8% per year for 2 years (in ₹)?
16. 16.What amount will ₹12200 grow to in 1 year at 25% per year compound interest (in ₹)?
17. 17.What is the difference between the compound interest and the simple interest on ₹45000 at 8% per year for 2 years (in ₹)?
18. 18.Find the compound interest on ₹3900 at 10% per year for 2 years, compounded every year (in ₹).
19. 19.What is the difference between the compound interest and the simple interest on ₹12900 at 10% per year for 2 years (in ₹)?
20. 20.Find the compound interest on ₹16600 at 15% per year for 1 year, compounded every year (in ₹).
21. 21.Find the compound interest on ₹2000 at 10% per year for 3 years, compounded every year (in ₹).
22. 22.Find the compound interest on ₹21400 at 12% per year for 1 year, compounded every year (in ₹).
23. 23.What amount will ₹30000 grow to in 2 years at 12% per year compound interest (in ₹)?
24. 24.What amount will ₹30300 grow to in 2 years at 20% per year compound interest (in ₹)?
25. 25.Find the compound interest on ₹8000 at 15% per year for 3 years, compounded every year (in ₹).
26. 26.A scooter is worth ₹59100. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
27. 27.What is the difference between the compound interest and the simple interest on ₹57500 at 12% per year for 2 years (in ₹)?
28. 28.Find the compound interest on ₹57500 at 8% per year for 2 years, compounded every year (in ₹).
29. 29.A town has 38400 people. The population grows by 10% every year. What will the population be after 2 years?
30. 30.What is the difference between the compound interest and the simple interest on ₹4600 at 20% per year for 2 years (in ₹)?
31. 31.Find the compound interest on ₹2500 at 4% per year for 2 years, compounded every year (in ₹).
32. 32.Find the compound interest on ₹9700 at 10% per year for 2 years, compounded every year (in ₹).
33. 33.A town has 46900 people. The population grows by 20% every year. What will the population be after 1 year?
34. 34.A town has 29500 people. The population grows by 20% every year. What will the population be after 3 years?
35. 35.Find the compound interest on ₹16000 at 15% per year for 3 years, compounded every year (in ₹).
36. 36.What amount will ₹33200 grow to in 1 year at 4% per year compound interest (in ₹)?
37. 37.Find the compound interest on ₹29200 at 15% per year for 2 years, compounded every year (in ₹).
38. 38.What is the difference between the compound interest and the simple interest on ₹2500 at 4% per year for 2 years (in ₹)?
39. 39.What is the difference between the compound interest and the simple interest on ₹39200 at 5% per year for 2 years (in ₹)?
40. 40.Find the compound interest on ₹21000 at 10% per year for 3 years, compounded every year (in ₹).

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets