Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 208 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A scooter is worth ₹29100. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
2. 2.A town has 57500 people. The population grows by 8% every year. What will the population be after 2 years?
3. 3.What amount will ₹13500 grow to in 3 years at 20% per year compound interest (in ₹)?
4. 4.Find the compound interest on ₹46200 at 20% per year for 2 years, compounded every year (in ₹).
5. 5.What is the difference between the compound interest and the simple interest on ₹5000 at 12% per year for 2 years (in ₹)?
6. 6.What is the difference between the compound interest and the simple interest on ₹11600 at 25% per year for 2 years (in ₹)?
7. 7.What is the difference between the compound interest and the simple interest on ₹10000 at 12% per year for 2 years (in ₹)?
8. 8.What amount will ₹25600 grow to in 2 years at 15% per year compound interest (in ₹)?
9. 9.What is the difference between the compound interest and the simple interest on ₹25600 at 25% per year for 2 years (in ₹)?
10. 10.What is the difference between the compound interest and the simple interest on ₹29700 at 20% per year for 2 years (in ₹)?
11. 11.What is the difference between the compound interest and the simple interest on ₹5600 at 25% per year for 2 years (in ₹)?
12. 12.What is the difference between the compound interest and the simple interest on ₹10800 at 10% per year for 2 years (in ₹)?
13. 13.Find the compound interest on ₹47600 at 25% per year for 2 years, compounded every year (in ₹).
14. 14.A scooter is worth ₹41900. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
15. 15.What is the difference between the compound interest and the simple interest on ₹45000 at 4% per year for 2 years (in ₹)?
16. 16.What amount will ₹56400 grow to in 1 year at 12% per year compound interest (in ₹)?
17. 17.Find the compound interest on ₹37200 at 15% per year for 1 year, compounded every year (in ₹).
18. 18.Find the compound interest on ₹13500 at 10% per year for 1 year, compounded every year (in ₹).
19. 19.A town has 12500 people. The population grows by 12% every year. What will the population be after 2 years?
20. 20.Find the compound interest on ₹60000 at 4% per year for 2 years, compounded every year (in ₹).
21. 21.What is the difference between the compound interest and the simple interest on ₹36800 at 25% per year for 2 years (in ₹)?
22. 22.A town has 9300 people. The population grows by 10% every year. What will the population be after 1 year?
23. 23.What is the difference between the compound interest and the simple interest on ₹52500 at 8% per year for 2 years (in ₹)?
24. 24.What is the difference between the compound interest and the simple interest on ₹18500 at 10% per year for 2 years (in ₹)?
25. 25.A scooter is worth ₹56000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
26. 26.A scooter is worth ₹45000. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
27. 27.What is the difference between the compound interest and the simple interest on ₹4800 at 15% per year for 2 years (in ₹)?
28. 28.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).
29. 29.Find the compound interest on ₹22800 at 10% per year for 1 year, compounded every year (in ₹).
30. 30.What amount will ₹2900 grow to in 2 years at 10% per year compound interest (in ₹)?
31. 31.What amount will ₹3900 grow to in 1 year at 5% per year compound interest (in ₹)?
32. 32.Find the compound interest on ₹56900 at 8% per year for 1 year, compounded every year (in ₹).
33. 33.A town has 52500 people. The population grows by 12% every year. What will the population be after 2 years?
34. 34.What amount will ₹17500 grow to in 1 year at 12% per year compound interest (in ₹)?
35. 35.Find the compound interest on ₹5000 at 4% per year for 2 years, compounded every year (in ₹).
36. 36.A town has 18000 people. The population grows by 10% every year. What will the population be after 3 years?
37. 37.What is the difference between the compound interest and the simple interest on ₹23200 at 5% per year for 2 years (in ₹)?
38. 38.A town has 32000 people. The population grows by 5% every year. What will the population be after 3 years?
39. 39.A scooter is worth ₹31100. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
40. 40.Find the compound interest on ₹15000 at 12% per year for 2 years, compounded every year (in ₹).

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets