Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.Find the compound interest on ₹9300 at 20% per year for 1 year, compounded every year (in ₹).
- 2.What is the difference between the compound interest and the simple interest on ₹7500 at 8% per year for 2 years (in ₹)?
- 3.What is the difference between the compound interest and the simple interest on ₹8800 at 15% per year for 2 years (in ₹)?
- 4.A scooter is worth ₹45000. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
- 5.What is the difference between the compound interest and the simple interest on ₹42000 at 5% per year for 2 years (in ₹)?
- 6.Find the compound interest on ₹49900 at 4% per year for 1 year, compounded every year (in ₹).
- 7.Find the compound interest on ₹14400 at 12% per year for 1 year, compounded every year (in ₹).
- 8.What is the difference between the compound interest and the simple interest on ₹2500 at 12% per year for 2 years (in ₹)?
- 9.Find the compound interest on ₹35500 at 8% per year for 1 year, compounded every year (in ₹).
- 10.A scooter is worth ₹21000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
- 11.What is the difference between the compound interest and the simple interest on ₹42500 at 4% per year for 2 years (in ₹)?
- 12.What amount will ₹32000 grow to in 3 years at 15% per year compound interest (in ₹)?
- 13.What is the difference between the compound interest and the simple interest on ₹17500 at 8% per year for 2 years (in ₹)?
- 14.What amount will ₹6000 grow to in 2 years at 15% per year compound interest (in ₹)?
- 15.Find the compound interest on ₹40700 at 4% per year for 1 year, compounded every year (in ₹).
- 16.A town has 5000 people. The population grows by 4% every year. What will the population be after 2 years?
- 17.Find the compound interest on ₹56400 at 25% per year for 2 years, compounded every year (in ₹).
- 18.What is the difference between the compound interest and the simple interest on ₹42500 at 12% per year for 2 years (in ₹)?
- 19.What is the difference between the compound interest and the simple interest on ₹30400 at 5% per year for 2 years (in ₹)?
- 20.What amount will ₹58300 grow to in 1 year at 20% per year compound interest (in ₹)?
- 21.What is the difference between the compound interest and the simple interest on ₹10400 at 5% per year for 2 years (in ₹)?
- 22.A scooter is worth ₹27500. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
- 23.What amount will ₹8000 grow to in 3 years at 15% per year compound interest (in ₹)?
- 24.What is the difference between the compound interest and the simple interest on ₹57500 at 8% per year for 2 years (in ₹)?
- 25.A town has 52500 people. The population grows by 12% every year. What will the population be after 2 years?
- 26.Find the compound interest on ₹3000 at 10% per year for 3 years, compounded every year (in ₹).
- 27.What amount will ₹40900 grow to in 1 year at 10% per year compound interest (in ₹)?
- 28.Find the compound interest on ₹35200 at 15% per year for 2 years, compounded every year (in ₹).
- 29.What amount will ₹20600 grow to in 1 year at 4% per year compound interest (in ₹)?
- 30.A town has 35000 people. The population grows by 12% every year. What will the population be after 2 years?
- 31.What is the difference between the compound interest and the simple interest on ₹42300 at 10% per year for 2 years (in ₹)?
- 32.A scooter is worth ₹53000. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
- 33.What is the difference between the compound interest and the simple interest on ₹26400 at 25% per year for 2 years (in ₹)?
- 34.A scooter is worth ₹22500. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
- 35.What amount will ₹12900 grow to in 1 year at 4% per year compound interest (in ₹)?
- 36.A town has 17100 people. The population grows by 25% every year. What will the population be after 1 year?
- 37.What amount will ₹45000 grow to in 2 years at 12% per year compound interest (in ₹)?
- 38.A town has 8800 people. The population grows by 25% every year. What will the population be after 2 years?
- 39.What is the difference between the compound interest and the simple interest on ₹47400 at 10% per year for 2 years (in ₹)?
- 40.What amount will ₹59500 grow to in 2 years at 10% per year compound interest (in ₹)?
Answer key
- 1860
- 48
- 198
- 34848
- 105
- 1996
- 1728
- 36
- 2840
- 15309
- 68
- 48668
- 112
- 7935
- 1628
- 5408
- 31725
- 612
- 76
- 69960
- 26
- 17600
- 12167
- 368
- 65856
- 993
- 44990
- 11352
- 21424
- 43904
- 423
- 33920
- 1650
- 18225
- 13416
- 21375
- 56448
- 13750
- 474
- 71995
Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets