Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 212 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A town has 31200 people. The population grows by 5% every year. What will the population be after 2 years?
2. 2.Find the compound interest on ₹11200 at 25% per year for 3 years, compounded every year (in ₹).
3. 3.What is the difference between the compound interest and the simple interest on ₹15600 at 5% per year for 2 years (in ₹)?
4. 4.A scooter is worth ₹24000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
5. 5.A scooter is worth ₹39600. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
6. 6.Find the compound interest on ₹12200 at 20% per year for 1 year, compounded every year (in ₹).
7. 7.Find the compound interest on ₹49800 at 4% per year for 1 year, compounded every year (in ₹).
8. 8.What amount will ₹11600 grow to in 2 years at 5% per year compound interest (in ₹)?
9. 9.What is the difference between the compound interest and the simple interest on ₹48400 at 5% per year for 2 years (in ₹)?
10. 10.A town has 16000 people. The population grows by 5% every year. What will the population be after 3 years?
11. 11.A town has 56000 people. The population grows by 5% every year. What will the population be after 3 years?
12. 12.What amount will ₹10800 grow to in 2 years at 5% per year compound interest (in ₹)?
13. 13.A town has 20000 people. The population grows by 12% every year. What will the population be after 2 years?
14. 14.Find the compound interest on ₹31600 at 12% per year for 1 year, compounded every year (in ₹).
15. 15.What is the difference between the compound interest and the simple interest on ₹47500 at 8% per year for 2 years (in ₹)?
16. 16.What amount will ₹52200 grow to in 1 year at 25% per year compound interest (in ₹)?
17. 17.Find the compound interest on ₹27500 at 8% per year for 2 years, compounded every year (in ₹).
18. 18.Find the compound interest on ₹41200 at 15% per year for 2 years, compounded every year (in ₹).
19. 19.What is the difference between the compound interest and the simple interest on ₹9600 at 5% per year for 2 years (in ₹)?
20. 20.What is the difference between the compound interest and the simple interest on ₹15000 at 8% per year for 2 years (in ₹)?
21. 21.Find the compound interest on ₹3400 at 10% per year for 1 year, compounded every year (in ₹).
22. 22.Find the compound interest on ₹39200 at 5% per year for 2 years, compounded every year (in ₹).
23. 23.What is the difference between the compound interest and the simple interest on ₹9900 at 10% per year for 2 years (in ₹)?
24. 24.What is the difference between the compound interest and the simple interest on ₹38800 at 5% per year for 2 years (in ₹)?
25. 25.What is the difference between the compound interest and the simple interest on ₹6700 at 10% per year for 2 years (in ₹)?
26. 26.What amount will ₹16400 grow to in 2 years at 20% per year compound interest (in ₹)?
27. 27.A town has 50400 people. The population grows by 25% every year. What will the population be after 2 years?
28. 28.A scooter is worth ₹32400. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
29. 29.A town has 10000 people. The population grows by 10% every year. What will the population be after 3 years?
30. 30.Find the compound interest on ₹16000 at 15% per year for 2 years, compounded every year (in ₹).
31. 31.What amount will ₹35000 grow to in 3 years at 10% per year compound interest (in ₹)?
32. 32.Find the compound interest on ₹38400 at 25% per year for 3 years, compounded every year (in ₹).
33. 33.A town has 28800 people. The population grows by 15% every year. What will the population be after 2 years?
34. 34.What is the difference between the compound interest and the simple interest on ₹41900 at 10% per year for 2 years (in ₹)?
35. 35.What amount will ₹47500 grow to in 2 years at 20% per year compound interest (in ₹)?
36. 36.What amount will ₹13000 grow to in 3 years at 10% per year compound interest (in ₹)?
37. 37.Find the compound interest on ₹29100 at 20% per year for 1 year, compounded every year (in ₹).
38. 38.What amount will ₹10400 grow to in 1 year at 12% per year compound interest (in ₹)?
39. 39.Find the compound interest on ₹35300 at 4% per year for 1 year, compounded every year (in ₹).
40. 40.A town has 58600 people. The population grows by 20% every year. What will the population be after 2 years?

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