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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 214 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What is the difference between the compound interest and the simple interest on ₹29200 at 15% per year for 2 years (in ₹)?
  2. 2.What is the difference between the compound interest and the simple interest on ₹35200 at 15% per year for 2 years (in ₹)?
  3. 3.A town has 40700 people. The population grows by 10% every year. What will the population be after 1 year?
  4. 4.What amount will ₹24400 grow to in 1 year at 20% per year compound interest (in ₹)?
  5. 5.What is the difference between the compound interest and the simple interest on ₹18400 at 5% per year for 2 years (in ₹)?
  6. 6.Find the compound interest on ₹59400 at 10% per year for 1 year, compounded every year (in ₹).
  7. 7.Find the compound interest on ₹47500 at 8% per year for 2 years, compounded every year (in ₹).
  8. 8.A scooter is worth ₹26800. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
  9. 9.A scooter is worth ₹36800. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
  10. 10.What amount will ₹12000 grow to in 3 years at 10% per year compound interest (in ₹)?
  11. 11.Find the compound interest on ₹16000 at 20% per year for 1 year, compounded every year (in ₹).
  12. 12.What is the difference between the compound interest and the simple interest on ₹35000 at 12% per year for 2 years (in ₹)?
  13. 13.Find the compound interest on ₹30800 at 5% per year for 2 years, compounded every year (in ₹).
  14. 14.A town has 49600 people. The population grows by 10% every year. What will the population be after 1 year?
  15. 15.Find the compound interest on ₹49000 at 10% per year for 3 years, compounded every year (in ₹).
  16. 16.Find the compound interest on ₹10000 at 4% per year for 2 years, compounded every year (in ₹).
  17. 17.What amount will ₹34300 grow to in 1 year at 15% per year compound interest (in ₹)?
  18. 18.What is the difference between the compound interest and the simple interest on ₹37500 at 8% per year for 2 years (in ₹)?
  19. 19.What is the difference between the compound interest and the simple interest on ₹57600 at 20% per year for 2 years (in ₹)?
  20. 20.Find the compound interest on ₹28600 at 5% per year for 1 year, compounded every year (in ₹).
  21. 21.What amount will ₹40000 grow to in 1 year at 10% per year compound interest (in ₹)?
  22. 22.What amount will ₹55000 grow to in 1 year at 15% per year compound interest (in ₹)?
  23. 23.Find the compound interest on ₹32000 at 5% per year for 3 years, compounded every year (in ₹).
  24. 24.Find the compound interest on ₹4400 at 20% per year for 2 years, compounded every year (in ₹).
  25. 25.Find the compound interest on ₹8000 at 5% per year for 3 years, compounded every year (in ₹).
  26. 26.Find the compound interest on ₹51700 at 10% per year for 1 year, compounded every year (in ₹).
  27. 27.What amount will ₹16000 grow to in 3 years at 15% per year compound interest (in ₹)?
  28. 28.A scooter is worth ₹40700. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
  29. 29.A town has 12300 people. The population grows by 4% every year. What will the population be after 1 year?
  30. 30.What is the difference between the compound interest and the simple interest on ₹26800 at 5% per year for 2 years (in ₹)?
  31. 31.A town has 25000 people. The population grows by 8% every year. What will the population be after 2 years?
  32. 32.What is the difference between the compound interest and the simple interest on ₹34400 at 25% per year for 2 years (in ₹)?
  33. 33.What amount will ₹9300 grow to in 1 year at 10% per year compound interest (in ₹)?
  34. 34.A scooter is worth ₹43100. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
  35. 35.What amount will ₹39600 grow to in 2 years at 5% per year compound interest (in ₹)?
  36. 36.Find the compound interest on ₹54400 at 25% per year for 3 years, compounded every year (in ₹).
  37. 37.What is the difference between the compound interest and the simple interest on ₹6400 at 25% per year for 2 years (in ₹)?
  38. 38.A scooter is worth ₹5000. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
  39. 39.Find the compound interest on ₹24900 at 5% per year for 1 year, compounded every year (in ₹).
  40. 40.A town has 56000 people. The population grows by 15% every year. What will the population be after 3 years?

Answer key

  1. 657
  2. 792
  3. 44770
  4. 29280
  5. 46
  6. 5940
  7. 7904
  8. 23584
  9. 15525
  10. 15972
  11. 3200
  12. 504
  13. 3157
  14. 54560
  15. 16219
  16. 816
  17. 39445
  18. 240
  19. 2304
  20. 1430
  21. 44000
  22. 63250
  23. 5044
  24. 1936
  25. 1261
  26. 5170
  27. 24334
  28. 36630
  29. 12792
  30. 67
  31. 29160
  32. 2150
  33. 10230
  34. 36635
  35. 43659
  36. 51850
  37. 400
  38. 4608
  39. 1245
  40. 85169

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