Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.What is the difference between the compound interest and the simple interest on ₹29200 at 15% per year for 2 years (in ₹)?
- 2.What is the difference between the compound interest and the simple interest on ₹35200 at 15% per year for 2 years (in ₹)?
- 3.A town has 40700 people. The population grows by 10% every year. What will the population be after 1 year?
- 4.What amount will ₹24400 grow to in 1 year at 20% per year compound interest (in ₹)?
- 5.What is the difference between the compound interest and the simple interest on ₹18400 at 5% per year for 2 years (in ₹)?
- 6.Find the compound interest on ₹59400 at 10% per year for 1 year, compounded every year (in ₹).
- 7.Find the compound interest on ₹47500 at 8% per year for 2 years, compounded every year (in ₹).
- 8.A scooter is worth ₹26800. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
- 9.A scooter is worth ₹36800. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
- 10.What amount will ₹12000 grow to in 3 years at 10% per year compound interest (in ₹)?
- 11.Find the compound interest on ₹16000 at 20% per year for 1 year, compounded every year (in ₹).
- 12.What is the difference between the compound interest and the simple interest on ₹35000 at 12% per year for 2 years (in ₹)?
- 13.Find the compound interest on ₹30800 at 5% per year for 2 years, compounded every year (in ₹).
- 14.A town has 49600 people. The population grows by 10% every year. What will the population be after 1 year?
- 15.Find the compound interest on ₹49000 at 10% per year for 3 years, compounded every year (in ₹).
- 16.Find the compound interest on ₹10000 at 4% per year for 2 years, compounded every year (in ₹).
- 17.What amount will ₹34300 grow to in 1 year at 15% per year compound interest (in ₹)?
- 18.What is the difference between the compound interest and the simple interest on ₹37500 at 8% per year for 2 years (in ₹)?
- 19.What is the difference between the compound interest and the simple interest on ₹57600 at 20% per year for 2 years (in ₹)?
- 20.Find the compound interest on ₹28600 at 5% per year for 1 year, compounded every year (in ₹).
- 21.What amount will ₹40000 grow to in 1 year at 10% per year compound interest (in ₹)?
- 22.What amount will ₹55000 grow to in 1 year at 15% per year compound interest (in ₹)?
- 23.Find the compound interest on ₹32000 at 5% per year for 3 years, compounded every year (in ₹).
- 24.Find the compound interest on ₹4400 at 20% per year for 2 years, compounded every year (in ₹).
- 25.Find the compound interest on ₹8000 at 5% per year for 3 years, compounded every year (in ₹).
- 26.Find the compound interest on ₹51700 at 10% per year for 1 year, compounded every year (in ₹).
- 27.What amount will ₹16000 grow to in 3 years at 15% per year compound interest (in ₹)?
- 28.A scooter is worth ₹40700. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
- 29.A town has 12300 people. The population grows by 4% every year. What will the population be after 1 year?
- 30.What is the difference between the compound interest and the simple interest on ₹26800 at 5% per year for 2 years (in ₹)?
- 31.A town has 25000 people. The population grows by 8% every year. What will the population be after 2 years?
- 32.What is the difference between the compound interest and the simple interest on ₹34400 at 25% per year for 2 years (in ₹)?
- 33.What amount will ₹9300 grow to in 1 year at 10% per year compound interest (in ₹)?
- 34.A scooter is worth ₹43100. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
- 35.What amount will ₹39600 grow to in 2 years at 5% per year compound interest (in ₹)?
- 36.Find the compound interest on ₹54400 at 25% per year for 3 years, compounded every year (in ₹).
- 37.What is the difference between the compound interest and the simple interest on ₹6400 at 25% per year for 2 years (in ₹)?
- 38.A scooter is worth ₹5000. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
- 39.Find the compound interest on ₹24900 at 5% per year for 1 year, compounded every year (in ₹).
- 40.A town has 56000 people. The population grows by 15% every year. What will the population be after 3 years?
Answer key
- 657
- 792
- 44770
- 29280
- 46
- 5940
- 7904
- 23584
- 15525
- 15972
- 3200
- 504
- 3157
- 54560
- 16219
- 816
- 39445
- 240
- 2304
- 1430
- 44000
- 63250
- 5044
- 1936
- 1261
- 5170
- 24334
- 36630
- 12792
- 67
- 29160
- 2150
- 10230
- 36635
- 43659
- 51850
- 400
- 4608
- 1245
- 85169
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