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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 219 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What amount will ₹35000 grow to in 2 years at 8% per year compound interest (in ₹)?
  2. 2.What is the difference between the compound interest and the simple interest on ₹37600 at 25% per year for 2 years (in ₹)?
  3. 3.What amount will ₹54000 grow to in 2 years at 15% per year compound interest (in ₹)?
  4. 4.A scooter is worth ₹32000. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
  5. 5.A town has 52100 people. The population grows by 20% every year. What will the population be after 1 year?
  6. 6.What is the difference between the compound interest and the simple interest on ₹36300 at 10% per year for 2 years (in ₹)?
  7. 7.What amount will ₹48000 grow to in 3 years at 5% per year compound interest (in ₹)?
  8. 8.A scooter is worth ₹3600. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
  9. 9.Find the compound interest on ₹27000 at 10% per year for 3 years, compounded every year (in ₹).
  10. 10.What amount will ₹56000 grow to in 3 years at 5% per year compound interest (in ₹)?
  11. 11.Find the compound interest on ₹7700 at 20% per year for 1 year, compounded every year (in ₹).
  12. 12.A scooter is worth ₹36800. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
  13. 13.What amount will ₹10800 grow to in 2 years at 15% per year compound interest (in ₹)?
  14. 14.What amount will ₹40000 grow to in 3 years at 15% per year compound interest (in ₹)?
  15. 15.Find the compound interest on ₹7000 at 10% per year for 3 years, compounded every year (in ₹).
  16. 16.Find the compound interest on ₹26000 at 20% per year for 3 years, compounded every year (in ₹).
  17. 17.Find the compound interest on ₹41500 at 20% per year for 3 years, compounded every year (in ₹).
  18. 18.Find the compound interest on ₹6000 at 10% per year for 3 years, compounded every year (in ₹).
  19. 19.What amount will ₹12400 grow to in 2 years at 5% per year compound interest (in ₹)?
  20. 20.A town has 52300 people. The population grows by 20% every year. What will the population be after 2 years?
  21. 21.What amount will ₹15700 grow to in 1 year at 4% per year compound interest (in ₹)?
  22. 22.What amount will ₹60000 grow to in 2 years at 4% per year compound interest (in ₹)?
  23. 23.Find the compound interest on ₹48500 at 20% per year for 3 years, compounded every year (in ₹).
  24. 24.Find the compound interest on ₹17600 at 4% per year for 1 year, compounded every year (in ₹).
  25. 25.What is the difference between the compound interest and the simple interest on ₹18000 at 10% per year for 2 years (in ₹)?
  26. 26.Find the compound interest on ₹4100 at 5% per year for 1 year, compounded every year (in ₹).
  27. 27.What is the difference between the compound interest and the simple interest on ₹17200 at 25% per year for 2 years (in ₹)?
  28. 28.A scooter is worth ₹36000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
  29. 29.A town has 2200 people. The population grows by 20% every year. What will the population be after 1 year?
  30. 30.What amount will ₹33500 grow to in 2 years at 20% per year compound interest (in ₹)?
  31. 31.Find the compound interest on ₹54000 at 10% per year for 3 years, compounded every year (in ₹).
  32. 32.Find the compound interest on ₹48000 at 15% per year for 3 years, compounded every year (in ₹).
  33. 33.A town has 8800 people. The population grows by 5% every year. What will the population be after 2 years?
  34. 34.What amount will ₹33800 grow to in 1 year at 25% per year compound interest (in ₹)?
  35. 35.Find the compound interest on ₹29300 at 25% per year for 1 year, compounded every year (in ₹).
  36. 36.What is the difference between the compound interest and the simple interest on ₹15200 at 5% per year for 2 years (in ₹)?
  37. 37.Find the compound interest on ₹19700 at 4% per year for 1 year, compounded every year (in ₹).
  38. 38.A scooter is worth ₹56200. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
  39. 39.A scooter is worth ₹57200. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
  40. 40.What is the difference between the compound interest and the simple interest on ₹2500 at 8% per year for 2 years (in ₹)?

Answer key

  1. 40824
  2. 2350
  3. 71415
  4. 27200
  5. 62520
  6. 363
  7. 55566
  8. 2025
  9. 8937
  10. 64827
  11. 1540
  12. 26588
  13. 14283
  14. 60835
  15. 2317
  16. 18928
  17. 30212
  18. 1986
  19. 13671
  20. 75312
  21. 16328
  22. 64896
  23. 35308
  24. 704
  25. 180
  26. 205
  27. 1075
  28. 26244
  29. 2640
  30. 48240
  31. 17874
  32. 25002
  33. 9702
  34. 42250
  35. 7325
  36. 38
  37. 788
  38. 45522
  39. 46332
  40. 16

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