Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.What amount will ₹35000 grow to in 2 years at 8% per year compound interest (in ₹)?
- 2.What is the difference between the compound interest and the simple interest on ₹37600 at 25% per year for 2 years (in ₹)?
- 3.What amount will ₹54000 grow to in 2 years at 15% per year compound interest (in ₹)?
- 4.A scooter is worth ₹32000. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
- 5.A town has 52100 people. The population grows by 20% every year. What will the population be after 1 year?
- 6.What is the difference between the compound interest and the simple interest on ₹36300 at 10% per year for 2 years (in ₹)?
- 7.What amount will ₹48000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 8.A scooter is worth ₹3600. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
- 9.Find the compound interest on ₹27000 at 10% per year for 3 years, compounded every year (in ₹).
- 10.What amount will ₹56000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 11.Find the compound interest on ₹7700 at 20% per year for 1 year, compounded every year (in ₹).
- 12.A scooter is worth ₹36800. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
- 13.What amount will ₹10800 grow to in 2 years at 15% per year compound interest (in ₹)?
- 14.What amount will ₹40000 grow to in 3 years at 15% per year compound interest (in ₹)?
- 15.Find the compound interest on ₹7000 at 10% per year for 3 years, compounded every year (in ₹).
- 16.Find the compound interest on ₹26000 at 20% per year for 3 years, compounded every year (in ₹).
- 17.Find the compound interest on ₹41500 at 20% per year for 3 years, compounded every year (in ₹).
- 18.Find the compound interest on ₹6000 at 10% per year for 3 years, compounded every year (in ₹).
- 19.What amount will ₹12400 grow to in 2 years at 5% per year compound interest (in ₹)?
- 20.A town has 52300 people. The population grows by 20% every year. What will the population be after 2 years?
- 21.What amount will ₹15700 grow to in 1 year at 4% per year compound interest (in ₹)?
- 22.What amount will ₹60000 grow to in 2 years at 4% per year compound interest (in ₹)?
- 23.Find the compound interest on ₹48500 at 20% per year for 3 years, compounded every year (in ₹).
- 24.Find the compound interest on ₹17600 at 4% per year for 1 year, compounded every year (in ₹).
- 25.What is the difference between the compound interest and the simple interest on ₹18000 at 10% per year for 2 years (in ₹)?
- 26.Find the compound interest on ₹4100 at 5% per year for 1 year, compounded every year (in ₹).
- 27.What is the difference between the compound interest and the simple interest on ₹17200 at 25% per year for 2 years (in ₹)?
- 28.A scooter is worth ₹36000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
- 29.A town has 2200 people. The population grows by 20% every year. What will the population be after 1 year?
- 30.What amount will ₹33500 grow to in 2 years at 20% per year compound interest (in ₹)?
- 31.Find the compound interest on ₹54000 at 10% per year for 3 years, compounded every year (in ₹).
- 32.Find the compound interest on ₹48000 at 15% per year for 3 years, compounded every year (in ₹).
- 33.A town has 8800 people. The population grows by 5% every year. What will the population be after 2 years?
- 34.What amount will ₹33800 grow to in 1 year at 25% per year compound interest (in ₹)?
- 35.Find the compound interest on ₹29300 at 25% per year for 1 year, compounded every year (in ₹).
- 36.What is the difference between the compound interest and the simple interest on ₹15200 at 5% per year for 2 years (in ₹)?
- 37.Find the compound interest on ₹19700 at 4% per year for 1 year, compounded every year (in ₹).
- 38.A scooter is worth ₹56200. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
- 39.A scooter is worth ₹57200. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
- 40.What is the difference between the compound interest and the simple interest on ₹2500 at 8% per year for 2 years (in ₹)?
Answer key
- 40824
- 2350
- 71415
- 27200
- 62520
- 363
- 55566
- 2025
- 8937
- 64827
- 1540
- 26588
- 14283
- 60835
- 2317
- 18928
- 30212
- 1986
- 13671
- 75312
- 16328
- 64896
- 35308
- 704
- 180
- 205
- 1075
- 26244
- 2640
- 48240
- 17874
- 25002
- 9702
- 42250
- 7325
- 38
- 788
- 45522
- 46332
- 16
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