Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 22 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What is the difference between the compound interest and the simple interest on ₹49200 at 5% per year for 2 years (in ₹)?
2. 2.Find the compound interest on ₹35500 at 20% per year for 3 years, compounded every year (in ₹).
3. 3.Find the compound interest on ₹2500 at 8% per year for 2 years, compounded every year (in ₹).
4. 4.Find the compound interest on ₹46200 at 4% per year for 1 year, compounded every year (in ₹).
5. 5.Find the compound interest on ₹42500 at 4% per year for 2 years, compounded every year (in ₹).
6. 6.A scooter is worth ₹10600. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
7. 7.Find the compound interest on ₹39400 at 10% per year for 2 years, compounded every year (in ₹).
8. 8.What amount will ₹11900 grow to in 1 year at 15% per year compound interest (in ₹)?
9. 9.Find the compound interest on ₹4000 at 10% per year for 3 years, compounded every year (in ₹).
10. 10.A town has 60000 people. The population grows by 8% every year. What will the population be after 2 years?
11. 11.What is the difference between the compound interest and the simple interest on ₹60000 at 12% per year for 2 years (in ₹)?
12. 12.A scooter is worth ₹18000. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
13. 13.What amount will ₹6300 grow to in 1 year at 25% per year compound interest (in ₹)?
14. 14.What amount will ₹54500 grow to in 1 year at 5% per year compound interest (in ₹)?
15. 15.Find the compound interest on ₹14400 at 25% per year for 3 years, compounded every year (in ₹).
16. 16.Find the compound interest on ₹37500 at 8% per year for 2 years, compounded every year (in ₹).
17. 17.Find the compound interest on ₹53000 at 10% per year for 3 years, compounded every year (in ₹).
18. 18.What is the difference between the compound interest and the simple interest on ₹30000 at 8% per year for 2 years (in ₹)?
19. 19.A town has 60000 people. The population grows by 4% every year. What will the population be after 2 years?
20. 20.Find the compound interest on ₹16000 at 15% per year for 3 years, compounded every year (in ₹).
21. 21.Find the compound interest on ₹38300 at 12% per year for 1 year, compounded every year (in ₹).
22. 22.A town has 48100 people. The population grows by 25% every year. What will the population be after 1 year?
23. 23.Find the compound interest on ₹50100 at 4% per year for 1 year, compounded every year (in ₹).
24. 24.Find the compound interest on ₹16000 at 5% per year for 3 years, compounded every year (in ₹).
25. 25.Find the compound interest on ₹24800 at 20% per year for 2 years, compounded every year (in ₹).
26. 26.What is the difference between the compound interest and the simple interest on ₹18800 at 5% per year for 2 years (in ₹)?
27. 27.What amount will ₹19100 grow to in 1 year at 10% per year compound interest (in ₹)?
28. 28.A scooter is worth ₹6000. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
29. 29.A town has 5600 people. The population grows by 5% every year. What will the population be after 2 years?
30. 30.What amount will ₹22300 grow to in 1 year at 12% per year compound interest (in ₹)?
31. 31.A scooter is worth ₹36000. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
32. 32.Find the compound interest on ₹24500 at 20% per year for 3 years, compounded every year (in ₹).
33. 33.What amount will ₹35000 grow to in 2 years at 12% per year compound interest (in ₹)?
34. 34.A scooter is worth ₹38700. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
35. 35.A scooter is worth ₹16500. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
36. 36.Find the compound interest on ₹30000 at 10% per year for 3 years, compounded every year (in ₹).
37. 37.What amount will ₹34000 grow to in 2 years at 5% per year compound interest (in ₹)?
38. 38.What amount will ₹41900 grow to in 1 year at 15% per year compound interest (in ₹)?
39. 39.A town has 40000 people. The population grows by 15% every year. What will the population be after 3 years?
40. 40.Find the compound interest on ₹24400 at 25% per year for 2 years, compounded every year (in ₹).

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