Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 223 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹22300 at 15% per year for 1 year, compounded every year (in ₹).
2. 2.What is the difference between the compound interest and the simple interest on ₹14900 at 10% per year for 2 years (in ₹)?
3. 3.Find the compound interest on ₹16000 at 5% per year for 3 years, compounded every year (in ₹).
4. 4.What is the difference between the compound interest and the simple interest on ₹35000 at 12% per year for 2 years (in ₹)?
5. 5.Find the compound interest on ₹14900 at 20% per year for 1 year, compounded every year (in ₹).
6. 6.Find the compound interest on ₹51200 at 20% per year for 1 year, compounded every year (in ₹).
7. 7.What amount will ₹58500 grow to in 3 years at 20% per year compound interest (in ₹)?
8. 8.What amount will ₹5000 grow to in 3 years at 20% per year compound interest (in ₹)?
9. 9.What amount will ₹26300 grow to in 2 years at 20% per year compound interest (in ₹)?
10. 10.A scooter is worth ₹30400. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
11. 11.What is the difference between the compound interest and the simple interest on ₹15000 at 12% per year for 2 years (in ₹)?
12. 12.A scooter is worth ₹30800. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
13. 13.Find the compound interest on ₹43800 at 4% per year for 1 year, compounded every year (in ₹).
14. 14.A scooter is worth ₹52900. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
15. 15.What is the difference between the compound interest and the simple interest on ₹18200 at 20% per year for 2 years (in ₹)?
16. 16.What is the difference between the compound interest and the simple interest on ₹28000 at 25% per year for 2 years (in ₹)?
17. 17.Find the compound interest on ₹21400 at 5% per year for 1 year, compounded every year (in ₹).
18. 18.Find the compound interest on ₹9200 at 15% per year for 2 years, compounded every year (in ₹).
19. 19.A town has 32000 people. The population grows by 10% every year. What will the population be after 3 years?
20. 20.What amount will ₹20600 grow to in 1 year at 8% per year compound interest (in ₹)?
21. 21.What is the difference between the compound interest and the simple interest on ₹17600 at 25% per year for 2 years (in ₹)?
22. 22.What amount will ₹57500 grow to in 2 years at 12% per year compound interest (in ₹)?
23. 23.A scooter is worth ₹9600. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
24. 24.What is the difference between the compound interest and the simple interest on ₹25000 at 12% per year for 2 years (in ₹)?
25. 25.Find the compound interest on ₹56400 at 5% per year for 1 year, compounded every year (in ₹).
26. 26.What is the difference between the compound interest and the simple interest on ₹42500 at 12% per year for 2 years (in ₹)?
27. 27.Find the compound interest on ₹17200 at 10% per year for 1 year, compounded every year (in ₹).
28. 28.What is the difference between the compound interest and the simple interest on ₹40000 at 5% per year for 2 years (in ₹)?
29. 29.A town has 20000 people. The population grows by 8% every year. What will the population be after 2 years?
30. 30.What amount will ₹52500 grow to in 2 years at 8% per year compound interest (in ₹)?
31. 31.What amount will ₹4800 grow to in 3 years at 25% per year compound interest (in ₹)?
32. 32.What is the difference between the compound interest and the simple interest on ₹47600 at 15% per year for 2 years (in ₹)?
33. 33.What is the difference between the compound interest and the simple interest on ₹57200 at 5% per year for 2 years (in ₹)?
34. 34.A town has 56500 people. The population grows by 20% every year. What will the population be after 3 years?
35. 35.What amount will ₹4400 grow to in 2 years at 25% per year compound interest (in ₹)?
36. 36.Find the compound interest on ₹52500 at 4% per year for 2 years, compounded every year (in ₹).
37. 37.What is the difference between the compound interest and the simple interest on ₹43800 at 10% per year for 2 years (in ₹)?
38. 38.What amount will ₹56000 grow to in 3 years at 5% per year compound interest (in ₹)?
39. 39.What amount will ₹16700 grow to in 1 year at 10% per year compound interest (in ₹)?
40. 40.A town has 50400 people. The population grows by 5% every year. What will the population be after 2 years?

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets