Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 226 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹50100 at 20% per year for 1 year, compounded every year (in ₹).
2. 2.A town has 17800 people. The population grows by 10% every year. What will the population be after 1 year?
3. 3.What amount will ₹7700 grow to in 1 year at 5% per year compound interest (in ₹)?
4. 4.What amount will ₹12500 grow to in 2 years at 8% per year compound interest (in ₹)?
5. 5.A town has 34500 people. The population grows by 20% every year. What will the population be after 3 years?
6. 6.A town has 14500 people. The population grows by 25% every year. What will the population be after 1 year?
7. 7.Find the compound interest on ₹8000 at 25% per year for 3 years, compounded every year (in ₹).
8. 8.Find the compound interest on ₹8000 at 5% per year for 3 years, compounded every year (in ₹).
9. 9.Find the compound interest on ₹23000 at 10% per year for 3 years, compounded every year (in ₹).
10. 10.Find the compound interest on ₹25300 at 15% per year for 1 year, compounded every year (in ₹).
11. 11.What is the difference between the compound interest and the simple interest on ₹58000 at 25% per year for 2 years (in ₹)?
12. 12.Find the compound interest on ₹53700 at 5% per year for 1 year, compounded every year (in ₹).
13. 13.What is the difference between the compound interest and the simple interest on ₹6600 at 20% per year for 2 years (in ₹)?
14. 14.Find the compound interest on ₹32000 at 5% per year for 3 years, compounded every year (in ₹).
15. 15.Find the compound interest on ₹11200 at 10% per year for 1 year, compounded every year (in ₹).
16. 16.What amount will ₹53500 grow to in 3 years at 20% per year compound interest (in ₹)?
17. 17.Find the compound interest on ₹37500 at 12% per year for 2 years, compounded every year (in ₹).
18. 18.A scooter is worth ₹34800. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
19. 19.What amount will ₹34700 grow to in 1 year at 5% per year compound interest (in ₹)?
20. 20.A town has 46400 people. The population grows by 5% every year. What will the population be after 1 year?
21. 21.A town has 20800 people. The population grows by 25% every year. What will the population be after 3 years?
22. 22.What is the difference between the compound interest and the simple interest on ₹46000 at 5% per year for 2 years (in ₹)?
23. 23.What is the difference between the compound interest and the simple interest on ₹36700 at 20% per year for 2 years (in ₹)?
24. 24.A town has 3400 people. The population grows by 5% every year. What will the population be after 1 year?
25. 25.A scooter is worth ₹57500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
26. 26.What amount will ₹17000 grow to in 3 years at 20% per year compound interest (in ₹)?
27. 27.Find the compound interest on ₹15500 at 20% per year for 3 years, compounded every year (in ₹).
28. 28.Find the compound interest on ₹7500 at 4% per year for 2 years, compounded every year (in ₹).
29. 29.Find the compound interest on ₹10000 at 10% per year for 3 years, compounded every year (in ₹).
30. 30.What is the difference between the compound interest and the simple interest on ₹51100 at 10% per year for 2 years (in ₹)?
31. 31.Find the compound interest on ₹43200 at 5% per year for 2 years, compounded every year (in ₹).
32. 32.Find the compound interest on ₹30000 at 8% per year for 2 years, compounded every year (in ₹).
33. 33.What amount will ₹5700 grow to in 1 year at 12% per year compound interest (in ₹)?
34. 34.What amount will ₹56000 grow to in 3 years at 15% per year compound interest (in ₹)?
35. 35.Find the compound interest on ₹9500 at 5% per year for 1 year, compounded every year (in ₹).
36. 36.A scooter is worth ₹10700. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
37. 37.A town has 2600 people. The population grows by 25% every year. What will the population be after 1 year?
38. 38.Find the compound interest on ₹38400 at 25% per year for 2 years, compounded every year (in ₹).
39. 39.What is the difference between the compound interest and the simple interest on ₹57400 at 10% per year for 2 years (in ₹)?
40. 40.What is the difference between the compound interest and the simple interest on ₹7500 at 4% per year for 2 years (in ₹)?

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