Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 230 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What is the difference between the compound interest and the simple interest on ₹11600 at 10% per year for 2 years (in ₹)?
2. 2.What amount will ₹32000 grow to in 3 years at 5% per year compound interest (in ₹)?
3. 3.A town has 46000 people. The population grows by 8% every year. What will the population be after 1 year?
4. 4.Find the compound interest on ₹13200 at 5% per year for 2 years, compounded every year (in ₹).
5. 5.A town has 32000 people. The population grows by 25% every year. What will the population be after 1 year?
6. 6.A town has 9000 people. The population grows by 10% every year. What will the population be after 3 years?
7. 7.What is the difference between the compound interest and the simple interest on ₹4400 at 25% per year for 2 years (in ₹)?
8. 8.A scooter is worth ₹5000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
9. 9.Find the compound interest on ₹3700 at 12% per year for 1 year, compounded every year (in ₹).
10. 10.A scooter is worth ₹24000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
11. 11.Find the compound interest on ₹29900 at 20% per year for 2 years, compounded every year (in ₹).
12. 12.What is the difference between the compound interest and the simple interest on ₹4800 at 5% per year for 2 years (in ₹)?
13. 13.What is the difference between the compound interest and the simple interest on ₹17800 at 10% per year for 2 years (in ₹)?
14. 14.A scooter is worth ₹44800. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
15. 15.A town has 9700 people. The population grows by 8% every year. What will the population be after 1 year?
16. 16.A scooter is worth ₹51100. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
17. 17.A scooter is worth ₹40000. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
18. 18.A scooter is worth ₹20400. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
19. 19.What is the difference between the compound interest and the simple interest on ₹7500 at 8% per year for 2 years (in ₹)?
20. 20.What amount will ₹51900 grow to in 1 year at 10% per year compound interest (in ₹)?
21. 21.Find the compound interest on ₹13800 at 4% per year for 1 year, compounded every year (in ₹).
22. 22.A town has 46400 people. The population grows by 15% every year. What will the population be after 2 years?
23. 23.What is the difference between the compound interest and the simple interest on ₹40000 at 4% per year for 2 years (in ₹)?
24. 24.What amount will ₹14100 grow to in 1 year at 4% per year compound interest (in ₹)?
25. 25.A town has 53800 people. The population grows by 25% every year. What will the population be after 1 year?
26. 26.What is the difference between the compound interest and the simple interest on ₹10000 at 8% per year for 2 years (in ₹)?
27. 27.What amount will ₹16000 grow to in 3 years at 15% per year compound interest (in ₹)?
28. 28.Find the compound interest on ₹5000 at 12% per year for 2 years, compounded every year (in ₹).
29. 29.Find the compound interest on ₹52400 at 15% per year for 2 years, compounded every year (in ₹).
30. 30.What is the difference between the compound interest and the simple interest on ₹38600 at 20% per year for 2 years (in ₹)?
31. 31.A scooter is worth ₹57500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
32. 32.Find the compound interest on ₹18000 at 12% per year for 1 year, compounded every year (in ₹).
33. 33.What is the difference between the compound interest and the simple interest on ₹22500 at 8% per year for 2 years (in ₹)?
34. 34.What is the difference between the compound interest and the simple interest on ₹42000 at 15% per year for 2 years (in ₹)?
35. 35.Find the compound interest on ₹53400 at 8% per year for 1 year, compounded every year (in ₹).
36. 36.What amount will ₹12500 grow to in 2 years at 12% per year compound interest (in ₹)?
37. 37.What is the difference between the compound interest and the simple interest on ₹4000 at 15% per year for 2 years (in ₹)?
38. 38.A scooter is worth ₹60000. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
39. 39.A scooter is worth ₹16400. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
40. 40.Find the compound interest on ₹22100 at 10% per year for 1 year, compounded every year (in ₹).

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets