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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 232 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

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  1. 1.A town has 9300 people. The population grows by 10% every year. What will the population be after 1 year?
  2. 2.What is the difference between the compound interest and the simple interest on ₹40000 at 4% per year for 2 years (in ₹)?
  3. 3.Find the compound interest on ₹17500 at 8% per year for 2 years, compounded every year (in ₹).
  4. 4.What is the difference between the compound interest and the simple interest on ₹47600 at 5% per year for 2 years (in ₹)?
  5. 5.What is the difference between the compound interest and the simple interest on ₹43200 at 25% per year for 2 years (in ₹)?
  6. 6.What is the difference between the compound interest and the simple interest on ₹35000 at 8% per year for 2 years (in ₹)?
  7. 7.Find the compound interest on ₹49800 at 20% per year for 2 years, compounded every year (in ₹).
  8. 8.What is the difference between the compound interest and the simple interest on ₹48300 at 10% per year for 2 years (in ₹)?
  9. 9.What is the difference between the compound interest and the simple interest on ₹27500 at 12% per year for 2 years (in ₹)?
  10. 10.What amount will ₹59800 grow to in 1 year at 4% per year compound interest (in ₹)?
  11. 11.What is the difference between the compound interest and the simple interest on ₹38400 at 25% per year for 2 years (in ₹)?
  12. 12.Find the compound interest on ₹54100 at 25% per year for 1 year, compounded every year (in ₹).
  13. 13.What amount will ₹54100 grow to in 1 year at 15% per year compound interest (in ₹)?
  14. 14.What amount will ₹32000 grow to in 3 years at 5% per year compound interest (in ₹)?
  15. 15.What amount will ₹17500 grow to in 1 year at 5% per year compound interest (in ₹)?
  16. 16.Find the compound interest on ₹57500 at 8% per year for 2 years, compounded every year (in ₹).
  17. 17.What is the difference between the compound interest and the simple interest on ₹57500 at 8% per year for 2 years (in ₹)?
  18. 18.What amount will ₹36300 grow to in 1 year at 5% per year compound interest (in ₹)?
  19. 19.Find the compound interest on ₹49000 at 8% per year for 1 year, compounded every year (in ₹).
  20. 20.Find the compound interest on ₹19700 at 10% per year for 1 year, compounded every year (in ₹).
  21. 21.What is the difference between the compound interest and the simple interest on ₹2500 at 4% per year for 2 years (in ₹)?
  22. 22.What amount will ₹30400 grow to in 3 years at 25% per year compound interest (in ₹)?
  23. 23.Find the compound interest on ₹3200 at 20% per year for 2 years, compounded every year (in ₹).
  24. 24.Find the compound interest on ₹20700 at 20% per year for 1 year, compounded every year (in ₹).
  25. 25.What is the difference between the compound interest and the simple interest on ₹30400 at 10% per year for 2 years (in ₹)?
  26. 26.What is the difference between the compound interest and the simple interest on ₹37100 at 20% per year for 2 years (in ₹)?
  27. 27.What amount will ₹48900 grow to in 1 year at 4% per year compound interest (in ₹)?
  28. 28.Find the compound interest on ₹29700 at 20% per year for 2 years, compounded every year (in ₹).
  29. 29.What is the difference between the compound interest and the simple interest on ₹10000 at 10% per year for 2 years (in ₹)?
  30. 30.Find the compound interest on ₹39900 at 4% per year for 1 year, compounded every year (in ₹).
  31. 31.Find the compound interest on ₹53300 at 15% per year for 1 year, compounded every year (in ₹).
  32. 32.What is the difference between the compound interest and the simple interest on ₹30000 at 4% per year for 2 years (in ₹)?
  33. 33.A town has 25000 people. The population grows by 8% every year. What will the population be after 2 years?
  34. 34.What amount will ₹8100 grow to in 1 year at 5% per year compound interest (in ₹)?
  35. 35.A town has 56000 people. The population grows by 12% every year. What will the population be after 1 year?
  36. 36.Find the compound interest on ₹3600 at 25% per year for 2 years, compounded every year (in ₹).
  37. 37.What amount will ₹33600 grow to in 2 years at 15% per year compound interest (in ₹)?
  38. 38.What amount will ₹39000 grow to in 3 years at 10% per year compound interest (in ₹)?
  39. 39.A town has 14400 people. The population grows by 25% every year. What will the population be after 2 years?
  40. 40.A town has 12100 people. The population grows by 10% every year. What will the population be after 1 year?

Answer key

  1. 10230
  2. 64
  3. 2912
  4. 119
  5. 2700
  6. 224
  7. 21912
  8. 483
  9. 396
  10. 62192
  11. 2400
  12. 13525
  13. 62215
  14. 37044
  15. 18375
  16. 9568
  17. 368
  18. 38115
  19. 3920
  20. 1970
  21. 4
  22. 59375
  23. 1408
  24. 4140
  25. 304
  26. 1484
  27. 50856
  28. 13068
  29. 100
  30. 1596
  31. 7995
  32. 48
  33. 29160
  34. 8505
  35. 62720
  36. 2025
  37. 44436
  38. 51909
  39. 22500
  40. 13310

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