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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 238 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

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  1. 1.Find the compound interest on ₹5800 at 8% per year for 1 year, compounded every year (in ₹).
  2. 2.Find the compound interest on ₹17500 at 4% per year for 2 years, compounded every year (in ₹).
  3. 3.Find the compound interest on ₹12900 at 25% per year for 1 year, compounded every year (in ₹).
  4. 4.Find the compound interest on ₹2500 at 4% per year for 2 years, compounded every year (in ₹).
  5. 5.What amount will ₹30000 grow to in 2 years at 8% per year compound interest (in ₹)?
  6. 6.Find the compound interest on ₹49600 at 25% per year for 3 years, compounded every year (in ₹).
  7. 7.What is the difference between the compound interest and the simple interest on ₹38300 at 20% per year for 2 years (in ₹)?
  8. 8.Find the compound interest on ₹9800 at 10% per year for 2 years, compounded every year (in ₹).
  9. 9.Find the compound interest on ₹24000 at 15% per year for 3 years, compounded every year (in ₹).
  10. 10.Find the compound interest on ₹5400 at 25% per year for 1 year, compounded every year (in ₹).
  11. 11.A town has 34800 people. The population grows by 15% every year. What will the population be after 1 year?
  12. 12.What is the difference between the compound interest and the simple interest on ₹56000 at 15% per year for 2 years (in ₹)?
  13. 13.A town has 5000 people. The population grows by 4% every year. What will the population be after 2 years?
  14. 14.A town has 7500 people. The population grows by 8% every year. What will the population be after 2 years?
  15. 15.A scooter is worth ₹48000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
  16. 16.What is the difference between the compound interest and the simple interest on ₹7600 at 25% per year for 2 years (in ₹)?
  17. 17.A scooter is worth ₹22300. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
  18. 18.Find the compound interest on ₹46400 at 25% per year for 3 years, compounded every year (in ₹).
  19. 19.A town has 9800 people. The population grows by 25% every year. What will the population be after 1 year?
  20. 20.A town has 43200 people. The population grows by 15% every year. What will the population be after 2 years?
  21. 21.A town has 15200 people. The population grows by 5% every year. What will the population be after 2 years?
  22. 22.What is the difference between the compound interest and the simple interest on ₹52700 at 10% per year for 2 years (in ₹)?
  23. 23.What amount will ₹51000 grow to in 3 years at 20% per year compound interest (in ₹)?
  24. 24.A town has 50000 people. The population grows by 10% every year. What will the population be after 3 years?
  25. 25.What amount will ₹10300 grow to in 1 year at 4% per year compound interest (in ₹)?
  26. 26.What amount will ₹23300 grow to in 1 year at 10% per year compound interest (in ₹)?
  27. 27.Find the compound interest on ₹42500 at 8% per year for 2 years, compounded every year (in ₹).
  28. 28.What is the difference between the compound interest and the simple interest on ₹24100 at 20% per year for 2 years (in ₹)?
  29. 29.What amount will ₹7500 grow to in 2 years at 8% per year compound interest (in ₹)?
  30. 30.A scooter is worth ₹14100. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
  31. 31.Find the compound interest on ₹46700 at 10% per year for 1 year, compounded every year (in ₹).
  32. 32.A town has 17600 people. The population grows by 15% every year. What will the population be after 2 years?
  33. 33.What amount will ₹36800 grow to in 2 years at 25% per year compound interest (in ₹)?
  34. 34.Find the compound interest on ₹36800 at 25% per year for 2 years, compounded every year (in ₹).
  35. 35.What is the difference between the compound interest and the simple interest on ₹9200 at 25% per year for 2 years (in ₹)?
  36. 36.A town has 42000 people. The population grows by 10% every year. What will the population be after 3 years?
  37. 37.What is the difference between the compound interest and the simple interest on ₹30000 at 5% per year for 2 years (in ₹)?
  38. 38.Find the compound interest on ₹15100 at 10% per year for 2 years, compounded every year (in ₹).
  39. 39.What is the difference between the compound interest and the simple interest on ₹38400 at 15% per year for 2 years (in ₹)?
  40. 40.A town has 36800 people. The population grows by 5% every year. What will the population be after 2 years?

Answer key

  1. 464
  2. 1428
  3. 3225
  4. 204
  5. 34992
  6. 47275
  7. 1532
  8. 2058
  9. 12501
  10. 1350
  11. 40020
  12. 1260
  13. 5408
  14. 8748
  15. 29478
  16. 475
  17. 21185
  18. 44225
  19. 12250
  20. 57132
  21. 16758
  22. 527
  23. 88128
  24. 66550
  25. 10712
  26. 25630
  27. 7072
  28. 964
  29. 8748
  30. 11280
  31. 4670
  32. 23276
  33. 57500
  34. 20700
  35. 575
  36. 55902
  37. 75
  38. 3171
  39. 864
  40. 40572

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