← Compound interest lesson New set →

Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 240 · 40 sums
TalentJR

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.Find the compound interest on ₹54100 at 10% per year for 1 year, compounded every year (in ₹).
  2. 2.What amount will ₹2500 grow to in 2 years at 4% per year compound interest (in ₹)?
  3. 3.What is the difference between the compound interest and the simple interest on ₹35000 at 12% per year for 2 years (in ₹)?
  4. 4.A town has 39500 people. The population grows by 15% every year. What will the population be after 1 year?
  5. 5.What is the difference between the compound interest and the simple interest on ₹54000 at 15% per year for 2 years (in ₹)?
  6. 6.Find the compound interest on ₹48300 at 4% per year for 1 year, compounded every year (in ₹).
  7. 7.What is the difference between the compound interest and the simple interest on ₹56200 at 10% per year for 2 years (in ₹)?
  8. 8.A scooter is worth ₹23100. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
  9. 9.What is the difference between the compound interest and the simple interest on ₹41600 at 10% per year for 2 years (in ₹)?
  10. 10.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).
  11. 11.Find the compound interest on ₹31200 at 5% per year for 2 years, compounded every year (in ₹).
  12. 12.Find the compound interest on ₹59200 at 25% per year for 3 years, compounded every year (in ₹).
  13. 13.What amount will ₹40000 grow to in 3 years at 15% per year compound interest (in ₹)?
  14. 14.A scooter is worth ₹16000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
  15. 15.What amount will ₹16000 grow to in 3 years at 5% per year compound interest (in ₹)?
  16. 16.What amount will ₹17500 grow to in 1 year at 5% per year compound interest (in ₹)?
  17. 17.Find the compound interest on ₹5000 at 12% per year for 2 years, compounded every year (in ₹).
  18. 18.What amount will ₹60000 grow to in 2 years at 12% per year compound interest (in ₹)?
  19. 19.A town has 22500 people. The population grows by 4% every year. What will the population be after 2 years?
  20. 20.What amount will ₹50000 grow to in 2 years at 8% per year compound interest (in ₹)?
  21. 21.What amount will ₹18400 grow to in 2 years at 5% per year compound interest (in ₹)?
  22. 22.Find the compound interest on ₹17400 at 12% per year for 1 year, compounded every year (in ₹).
  23. 23.Find the compound interest on ₹33600 at 25% per year for 3 years, compounded every year (in ₹).
  24. 24.Find the compound interest on ₹4800 at 12% per year for 1 year, compounded every year (in ₹).
  25. 25.A town has 37500 people. The population grows by 10% every year. What will the population be after 1 year?
  26. 26.What amount will ₹31400 grow to in 1 year at 10% per year compound interest (in ₹)?
  27. 27.What is the difference between the compound interest and the simple interest on ₹53000 at 10% per year for 2 years (in ₹)?
  28. 28.What amount will ₹14900 grow to in 1 year at 4% per year compound interest (in ₹)?
  29. 29.A scooter is worth ₹36000. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
  30. 30.A scooter is worth ₹14800. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
  31. 31.Find the compound interest on ₹12500 at 20% per year for 2 years, compounded every year (in ₹).
  32. 32.What amount will ₹35200 grow to in 1 year at 25% per year compound interest (in ₹)?
  33. 33.Find the compound interest on ₹36400 at 5% per year for 2 years, compounded every year (in ₹).
  34. 34.Find the compound interest on ₹33900 at 5% per year for 1 year, compounded every year (in ₹).
  35. 35.What amount will ₹58800 grow to in 2 years at 25% per year compound interest (in ₹)?
  36. 36.A town has 36600 people. The population grows by 10% every year. What will the population be after 1 year?
  37. 37.What is the difference between the compound interest and the simple interest on ₹15000 at 8% per year for 2 years (in ₹)?
  38. 38.A town has 33000 people. The population grows by 10% every year. What will the population be after 3 years?
  39. 39.A scooter is worth ₹3800. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
  40. 40.Find the compound interest on ₹9100 at 12% per year for 1 year, compounded every year (in ₹).

Answer key

  1. 5410
  2. 2704
  3. 504
  4. 45425
  5. 1215
  6. 1932
  7. 562
  8. 20790
  9. 416
  10. 6305
  11. 3198
  12. 56425
  13. 60835
  14. 13718
  15. 18522
  16. 18375
  17. 1272
  18. 75264
  19. 24336
  20. 58320
  21. 20286
  22. 2088
  23. 32025
  24. 576
  25. 41250
  26. 34540
  27. 530
  28. 15496
  29. 29160
  30. 8325
  31. 5500
  32. 44000
  33. 3731
  34. 1695
  35. 91875
  36. 40260
  37. 96
  38. 43923
  39. 3344
  40. 1092

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets