Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 242 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹59000 at 10% per year for 3 years, compounded every year (in ₹).
2. 2.Find the compound interest on ₹19000 at 20% per year for 1 year, compounded every year (in ₹).
3. 3.What amount will ₹26100 grow to in 1 year at 15% per year compound interest (in ₹)?
4. 4.What amount will ₹56000 grow to in 2 years at 5% per year compound interest (in ₹)?
5. 5.What is the difference between the compound interest and the simple interest on ₹10000 at 12% per year for 2 years (in ₹)?
6. 6.What amount will ₹15400 grow to in 1 year at 25% per year compound interest (in ₹)?
7. 7.A town has 12000 people. The population grows by 10% every year. What will the population be after 3 years?
8. 8.What is the difference between the compound interest and the simple interest on ₹20000 at 12% per year for 2 years (in ₹)?
9. 9.What amount will ₹10000 grow to in 2 years at 8% per year compound interest (in ₹)?
10. 10.What is the difference between the compound interest and the simple interest on ₹45700 at 20% per year for 2 years (in ₹)?
11. 11.What is the difference between the compound interest and the simple interest on ₹2800 at 5% per year for 2 years (in ₹)?
12. 12.What amount will ₹11600 grow to in 1 year at 15% per year compound interest (in ₹)?
13. 13.What is the difference between the compound interest and the simple interest on ₹59100 at 10% per year for 2 years (in ₹)?
14. 14.What is the difference between the compound interest and the simple interest on ₹5000 at 12% per year for 2 years (in ₹)?
15. 15.Find the compound interest on ₹31000 at 10% per year for 1 year, compounded every year (in ₹).
16. 16.What amount will ₹14000 grow to in 3 years at 10% per year compound interest (in ₹)?
17. 17.What amount will ₹23200 grow to in 2 years at 25% per year compound interest (in ₹)?
18. 18.What amount will ₹32500 grow to in 2 years at 8% per year compound interest (in ₹)?
19. 19.Find the compound interest on ₹45600 at 5% per year for 1 year, compounded every year (in ₹).
20. 20.Find the compound interest on ₹42300 at 12% per year for 1 year, compounded every year (in ₹).
21. 21.What amount will ₹41200 grow to in 2 years at 25% per year compound interest (in ₹)?
22. 22.Find the compound interest on ₹25400 at 25% per year for 1 year, compounded every year (in ₹).
23. 23.Find the compound interest on ₹8000 at 5% per year for 3 years, compounded every year (in ₹).
24. 24.Find the compound interest on ₹8000 at 8% per year for 1 year, compounded every year (in ₹).
25. 25.What amount will ₹40000 grow to in 3 years at 5% per year compound interest (in ₹)?
26. 26.What is the difference between the compound interest and the simple interest on ₹40800 at 15% per year for 2 years (in ₹)?
27. 27.Find the compound interest on ₹56000 at 25% per year for 3 years, compounded every year (in ₹).
28. 28.What amount will ₹19200 grow to in 3 years at 25% per year compound interest (in ₹)?
29. 29.A town has 16400 people. The population grows by 25% every year. What will the population be after 1 year?
30. 30.A town has 3200 people. The population grows by 25% every year. What will the population be after 3 years?
31. 31.What amount will ₹25000 grow to in 2 years at 8% per year compound interest (in ₹)?
32. 32.Find the compound interest on ₹24000 at 12% per year for 1 year, compounded every year (in ₹).
33. 33.What amount will ₹17800 grow to in 1 year at 10% per year compound interest (in ₹)?
34. 34.What is the difference between the compound interest and the simple interest on ₹33600 at 25% per year for 2 years (in ₹)?
35. 35.What is the difference between the compound interest and the simple interest on ₹38100 at 10% per year for 2 years (in ₹)?
36. 36.A town has 59000 people. The population grows by 20% every year. What will the population be after 3 years?
37. 37.What amount will ₹22500 grow to in 2 years at 8% per year compound interest (in ₹)?
38. 38.A scooter is worth ₹46400. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
39. 39.What is the difference between the compound interest and the simple interest on ₹42000 at 25% per year for 2 years (in ₹)?
40. 40.What is the difference between the compound interest and the simple interest on ₹54300 at 20% per year for 2 years (in ₹)?

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