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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 250 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.Find the compound interest on ₹40000 at 8% per year for 2 years, compounded every year (in ₹).
  2. 2.A town has 57100 people. The population grows by 5% every year. What will the population be after 1 year?
  3. 3.What amount will ₹50200 grow to in 1 year at 20% per year compound interest (in ₹)?
  4. 4.Find the compound interest on ₹42500 at 10% per year for 2 years, compounded every year (in ₹).
  5. 5.Find the compound interest on ₹13400 at 20% per year for 1 year, compounded every year (in ₹).
  6. 6.Find the compound interest on ₹17500 at 4% per year for 2 years, compounded every year (in ₹).
  7. 7.Find the compound interest on ₹22800 at 20% per year for 1 year, compounded every year (in ₹).
  8. 8.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).
  9. 9.Find the compound interest on ₹24800 at 5% per year for 2 years, compounded every year (in ₹).
  10. 10.Find the compound interest on ₹10000 at 4% per year for 2 years, compounded every year (in ₹).
  11. 11.Find the compound interest on ₹28900 at 10% per year for 1 year, compounded every year (in ₹).
  12. 12.What is the difference between the compound interest and the simple interest on ₹27200 at 5% per year for 2 years (in ₹)?
  13. 13.A town has 47500 people. The population grows by 4% every year. What will the population be after 2 years?
  14. 14.What amount will ₹60000 grow to in 2 years at 12% per year compound interest (in ₹)?
  15. 15.A town has 25000 people. The population grows by 12% every year. What will the population be after 2 years?
  16. 16.What is the difference between the compound interest and the simple interest on ₹51300 at 10% per year for 2 years (in ₹)?
  17. 17.What is the difference between the compound interest and the simple interest on ₹3200 at 20% per year for 2 years (in ₹)?
  18. 18.Find the compound interest on ₹14000 at 15% per year for 1 year, compounded every year (in ₹).
  19. 19.What is the difference between the compound interest and the simple interest on ₹2500 at 4% per year for 2 years (in ₹)?
  20. 20.A town has 34600 people. The population grows by 4% every year. What will the population be after 1 year?
  21. 21.What amount will ₹45600 grow to in 2 years at 25% per year compound interest (in ₹)?
  22. 22.What is the difference between the compound interest and the simple interest on ₹17000 at 10% per year for 2 years (in ₹)?
  23. 23.A scooter is worth ₹48800. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
  24. 24.Find the compound interest on ₹43200 at 15% per year for 2 years, compounded every year (in ₹).
  25. 25.What amount will ₹24000 grow to in 3 years at 5% per year compound interest (in ₹)?
  26. 26.What amount will ₹32000 grow to in 3 years at 15% per year compound interest (in ₹)?
  27. 27.Find the compound interest on ₹16000 at 5% per year for 2 years, compounded every year (in ₹).
  28. 28.What is the difference between the compound interest and the simple interest on ₹25700 at 10% per year for 2 years (in ₹)?
  29. 29.What is the difference between the compound interest and the simple interest on ₹35900 at 10% per year for 2 years (in ₹)?
  30. 30.What is the difference between the compound interest and the simple interest on ₹10000 at 12% per year for 2 years (in ₹)?
  31. 31.What is the difference between the compound interest and the simple interest on ₹21100 at 20% per year for 2 years (in ₹)?
  32. 32.A scooter is worth ₹4600. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
  33. 33.A town has 12500 people. The population grows by 12% every year. What will the population be after 2 years?
  34. 34.What is the difference between the compound interest and the simple interest on ₹60000 at 4% per year for 2 years (in ₹)?
  35. 35.What amount will ₹5000 grow to in 2 years at 12% per year compound interest (in ₹)?
  36. 36.Find the compound interest on ₹24000 at 5% per year for 3 years, compounded every year (in ₹).
  37. 37.A town has 16000 people. The population grows by 5% every year. What will the population be after 3 years?
  38. 38.What is the difference between the compound interest and the simple interest on ₹44800 at 5% per year for 2 years (in ₹)?
  39. 39.A scooter is worth ₹40000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
  40. 40.A scooter is worth ₹39600. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?

Answer key

  1. 6656
  2. 59955
  3. 60240
  4. 8925
  5. 2680
  6. 1428
  7. 4560
  8. 6305
  9. 2542
  10. 816
  11. 2890
  12. 68
  13. 51376
  14. 75264
  15. 31360
  16. 513
  17. 128
  18. 2100
  19. 4
  20. 35984
  21. 71250
  22. 170
  23. 27450
  24. 13932
  25. 27783
  26. 48668
  27. 1640
  28. 257
  29. 359
  30. 144
  31. 844
  32. 4232
  33. 15680
  34. 96
  35. 6272
  36. 3783
  37. 18522
  38. 112
  39. 24565
  40. 35739

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