Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.Find the compound interest on ₹40000 at 8% per year for 2 years, compounded every year (in ₹).
- 2.A town has 57100 people. The population grows by 5% every year. What will the population be after 1 year?
- 3.What amount will ₹50200 grow to in 1 year at 20% per year compound interest (in ₹)?
- 4.Find the compound interest on ₹42500 at 10% per year for 2 years, compounded every year (in ₹).
- 5.Find the compound interest on ₹13400 at 20% per year for 1 year, compounded every year (in ₹).
- 6.Find the compound interest on ₹17500 at 4% per year for 2 years, compounded every year (in ₹).
- 7.Find the compound interest on ₹22800 at 20% per year for 1 year, compounded every year (in ₹).
- 8.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).
- 9.Find the compound interest on ₹24800 at 5% per year for 2 years, compounded every year (in ₹).
- 10.Find the compound interest on ₹10000 at 4% per year for 2 years, compounded every year (in ₹).
- 11.Find the compound interest on ₹28900 at 10% per year for 1 year, compounded every year (in ₹).
- 12.What is the difference between the compound interest and the simple interest on ₹27200 at 5% per year for 2 years (in ₹)?
- 13.A town has 47500 people. The population grows by 4% every year. What will the population be after 2 years?
- 14.What amount will ₹60000 grow to in 2 years at 12% per year compound interest (in ₹)?
- 15.A town has 25000 people. The population grows by 12% every year. What will the population be after 2 years?
- 16.What is the difference between the compound interest and the simple interest on ₹51300 at 10% per year for 2 years (in ₹)?
- 17.What is the difference between the compound interest and the simple interest on ₹3200 at 20% per year for 2 years (in ₹)?
- 18.Find the compound interest on ₹14000 at 15% per year for 1 year, compounded every year (in ₹).
- 19.What is the difference between the compound interest and the simple interest on ₹2500 at 4% per year for 2 years (in ₹)?
- 20.A town has 34600 people. The population grows by 4% every year. What will the population be after 1 year?
- 21.What amount will ₹45600 grow to in 2 years at 25% per year compound interest (in ₹)?
- 22.What is the difference between the compound interest and the simple interest on ₹17000 at 10% per year for 2 years (in ₹)?
- 23.A scooter is worth ₹48800. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
- 24.Find the compound interest on ₹43200 at 15% per year for 2 years, compounded every year (in ₹).
- 25.What amount will ₹24000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 26.What amount will ₹32000 grow to in 3 years at 15% per year compound interest (in ₹)?
- 27.Find the compound interest on ₹16000 at 5% per year for 2 years, compounded every year (in ₹).
- 28.What is the difference between the compound interest and the simple interest on ₹25700 at 10% per year for 2 years (in ₹)?
- 29.What is the difference between the compound interest and the simple interest on ₹35900 at 10% per year for 2 years (in ₹)?
- 30.What is the difference between the compound interest and the simple interest on ₹10000 at 12% per year for 2 years (in ₹)?
- 31.What is the difference between the compound interest and the simple interest on ₹21100 at 20% per year for 2 years (in ₹)?
- 32.A scooter is worth ₹4600. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
- 33.A town has 12500 people. The population grows by 12% every year. What will the population be after 2 years?
- 34.What is the difference between the compound interest and the simple interest on ₹60000 at 4% per year for 2 years (in ₹)?
- 35.What amount will ₹5000 grow to in 2 years at 12% per year compound interest (in ₹)?
- 36.Find the compound interest on ₹24000 at 5% per year for 3 years, compounded every year (in ₹).
- 37.A town has 16000 people. The population grows by 5% every year. What will the population be after 3 years?
- 38.What is the difference between the compound interest and the simple interest on ₹44800 at 5% per year for 2 years (in ₹)?
- 39.A scooter is worth ₹40000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
- 40.A scooter is worth ₹39600. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
Answer key
- 6656
- 59955
- 60240
- 8925
- 2680
- 1428
- 4560
- 6305
- 2542
- 816
- 2890
- 68
- 51376
- 75264
- 31360
- 513
- 128
- 2100
- 4
- 35984
- 71250
- 170
- 27450
- 13932
- 27783
- 48668
- 1640
- 257
- 359
- 144
- 844
- 4232
- 15680
- 96
- 6272
- 3783
- 18522
- 112
- 24565
- 35739
Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets