Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.Find the compound interest on ₹5000 at 12% per year for 2 years, compounded every year (in ₹).
- 2.A town has 34100 people. The population grows by 10% every year. What will the population be after 2 years?
- 3.Find the compound interest on ₹8200 at 10% per year for 1 year, compounded every year (in ₹).
- 4.Find the compound interest on ₹21800 at 12% per year for 1 year, compounded every year (in ₹).
- 5.Find the compound interest on ₹52500 at 12% per year for 2 years, compounded every year (in ₹).
- 6.A scooter is worth ₹24800. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
- 7.What is the difference between the compound interest and the simple interest on ₹10200 at 10% per year for 2 years (in ₹)?
- 8.Find the compound interest on ₹32500 at 12% per year for 2 years, compounded every year (in ₹).
- 9.A scooter is worth ₹6300. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
- 10.What is the difference between the compound interest and the simple interest on ₹30900 at 20% per year for 2 years (in ₹)?
- 11.A town has 27700 people. The population grows by 10% every year. What will the population be after 2 years?
- 12.Find the compound interest on ₹6200 at 15% per year for 1 year, compounded every year (in ₹).
- 13.A town has 33200 people. The population grows by 8% every year. What will the population be after 1 year?
- 14.What is the difference between the compound interest and the simple interest on ₹17600 at 5% per year for 2 years (in ₹)?
- 15.Find the compound interest on ₹29800 at 20% per year for 2 years, compounded every year (in ₹).
- 16.A town has 8800 people. The population grows by 25% every year. What will the population be after 2 years?
- 17.A scooter is worth ₹43900. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
- 18.A scooter is worth ₹40000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
- 19.Find the compound interest on ₹32000 at 5% per year for 3 years, compounded every year (in ₹).
- 20.What amount will ₹48000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 21.What amount will ₹40000 grow to in 1 year at 5% per year compound interest (in ₹)?
- 22.What amount will ₹30000 grow to in 2 years at 8% per year compound interest (in ₹)?
- 23.A scooter is worth ₹28200. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
- 24.Find the compound interest on ₹16000 at 5% per year for 3 years, compounded every year (in ₹).
- 25.What is the difference between the compound interest and the simple interest on ₹50000 at 10% per year for 2 years (in ₹)?
- 26.What amount will ₹7100 grow to in 1 year at 10% per year compound interest (in ₹)?
- 27.What amount will ₹35500 grow to in 1 year at 10% per year compound interest (in ₹)?
- 28.What amount will ₹11800 grow to in 1 year at 8% per year compound interest (in ₹)?
- 29.What is the difference between the compound interest and the simple interest on ₹27400 at 20% per year for 2 years (in ₹)?
- 30.What is the difference between the compound interest and the simple interest on ₹37600 at 25% per year for 2 years (in ₹)?
- 31.Find the compound interest on ₹15000 at 12% per year for 2 years, compounded every year (in ₹).
- 32.A town has 32000 people. The population grows by 5% every year. What will the population be after 3 years?
- 33.A town has 47000 people. The population grows by 10% every year. What will the population be after 3 years?
- 34.What amount will ₹17500 grow to in 2 years at 8% per year compound interest (in ₹)?
- 35.What amount will ₹40200 grow to in 1 year at 8% per year compound interest (in ₹)?
- 36.A scooter is worth ₹38800. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
- 37.What is the difference between the compound interest and the simple interest on ₹40400 at 5% per year for 2 years (in ₹)?
- 38.What amount will ₹56800 grow to in 2 years at 5% per year compound interest (in ₹)?
- 39.A town has 8000 people. The population grows by 5% every year. What will the population be after 3 years?
- 40.What amount will ₹53200 grow to in 2 years at 5% per year compound interest (in ₹)?
Answer key
- 1272
- 41261
- 820
- 2616
- 13356
- 22382
- 102
- 8268
- 5985
- 1236
- 33517
- 930
- 35856
- 44
- 13112
- 13750
- 35120
- 34295
- 5044
- 55566
- 42000
- 34992
- 27072
- 2522
- 500
- 7810
- 39050
- 12744
- 1096
- 2350
- 3816
- 37044
- 62557
- 20412
- 43416
- 28033
- 101
- 62622
- 9261
- 58653
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