← Compound interest lesson New set →

Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 252 · 40 sums
TalentJR

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.Find the compound interest on ₹5000 at 12% per year for 2 years, compounded every year (in ₹).
  2. 2.A town has 34100 people. The population grows by 10% every year. What will the population be after 2 years?
  3. 3.Find the compound interest on ₹8200 at 10% per year for 1 year, compounded every year (in ₹).
  4. 4.Find the compound interest on ₹21800 at 12% per year for 1 year, compounded every year (in ₹).
  5. 5.Find the compound interest on ₹52500 at 12% per year for 2 years, compounded every year (in ₹).
  6. 6.A scooter is worth ₹24800. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
  7. 7.What is the difference between the compound interest and the simple interest on ₹10200 at 10% per year for 2 years (in ₹)?
  8. 8.Find the compound interest on ₹32500 at 12% per year for 2 years, compounded every year (in ₹).
  9. 9.A scooter is worth ₹6300. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
  10. 10.What is the difference between the compound interest and the simple interest on ₹30900 at 20% per year for 2 years (in ₹)?
  11. 11.A town has 27700 people. The population grows by 10% every year. What will the population be after 2 years?
  12. 12.Find the compound interest on ₹6200 at 15% per year for 1 year, compounded every year (in ₹).
  13. 13.A town has 33200 people. The population grows by 8% every year. What will the population be after 1 year?
  14. 14.What is the difference between the compound interest and the simple interest on ₹17600 at 5% per year for 2 years (in ₹)?
  15. 15.Find the compound interest on ₹29800 at 20% per year for 2 years, compounded every year (in ₹).
  16. 16.A town has 8800 people. The population grows by 25% every year. What will the population be after 2 years?
  17. 17.A scooter is worth ₹43900. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
  18. 18.A scooter is worth ₹40000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
  19. 19.Find the compound interest on ₹32000 at 5% per year for 3 years, compounded every year (in ₹).
  20. 20.What amount will ₹48000 grow to in 3 years at 5% per year compound interest (in ₹)?
  21. 21.What amount will ₹40000 grow to in 1 year at 5% per year compound interest (in ₹)?
  22. 22.What amount will ₹30000 grow to in 2 years at 8% per year compound interest (in ₹)?
  23. 23.A scooter is worth ₹28200. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
  24. 24.Find the compound interest on ₹16000 at 5% per year for 3 years, compounded every year (in ₹).
  25. 25.What is the difference between the compound interest and the simple interest on ₹50000 at 10% per year for 2 years (in ₹)?
  26. 26.What amount will ₹7100 grow to in 1 year at 10% per year compound interest (in ₹)?
  27. 27.What amount will ₹35500 grow to in 1 year at 10% per year compound interest (in ₹)?
  28. 28.What amount will ₹11800 grow to in 1 year at 8% per year compound interest (in ₹)?
  29. 29.What is the difference between the compound interest and the simple interest on ₹27400 at 20% per year for 2 years (in ₹)?
  30. 30.What is the difference between the compound interest and the simple interest on ₹37600 at 25% per year for 2 years (in ₹)?
  31. 31.Find the compound interest on ₹15000 at 12% per year for 2 years, compounded every year (in ₹).
  32. 32.A town has 32000 people. The population grows by 5% every year. What will the population be after 3 years?
  33. 33.A town has 47000 people. The population grows by 10% every year. What will the population be after 3 years?
  34. 34.What amount will ₹17500 grow to in 2 years at 8% per year compound interest (in ₹)?
  35. 35.What amount will ₹40200 grow to in 1 year at 8% per year compound interest (in ₹)?
  36. 36.A scooter is worth ₹38800. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
  37. 37.What is the difference between the compound interest and the simple interest on ₹40400 at 5% per year for 2 years (in ₹)?
  38. 38.What amount will ₹56800 grow to in 2 years at 5% per year compound interest (in ₹)?
  39. 39.A town has 8000 people. The population grows by 5% every year. What will the population be after 3 years?
  40. 40.What amount will ₹53200 grow to in 2 years at 5% per year compound interest (in ₹)?

Answer key

  1. 1272
  2. 41261
  3. 820
  4. 2616
  5. 13356
  6. 22382
  7. 102
  8. 8268
  9. 5985
  10. 1236
  11. 33517
  12. 930
  13. 35856
  14. 44
  15. 13112
  16. 13750
  17. 35120
  18. 34295
  19. 5044
  20. 55566
  21. 42000
  22. 34992
  23. 27072
  24. 2522
  25. 500
  26. 7810
  27. 39050
  28. 12744
  29. 1096
  30. 2350
  31. 3816
  32. 37044
  33. 62557
  34. 20412
  35. 43416
  36. 28033
  37. 101
  38. 62622
  39. 9261
  40. 58653

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets