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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 254 · 40 sums
TalentJR

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.Find the compound interest on ₹14500 at 4% per year for 1 year, compounded every year (in ₹).
  2. 2.What is the difference between the compound interest and the simple interest on ₹9100 at 10% per year for 2 years (in ₹)?
  3. 3.What is the difference between the compound interest and the simple interest on ₹2500 at 12% per year for 2 years (in ₹)?
  4. 4.What is the difference between the compound interest and the simple interest on ₹15000 at 4% per year for 2 years (in ₹)?
  5. 5.What is the difference between the compound interest and the simple interest on ₹36400 at 10% per year for 2 years (in ₹)?
  6. 6.What is the difference between the compound interest and the simple interest on ₹17400 at 20% per year for 2 years (in ₹)?
  7. 7.What is the difference between the compound interest and the simple interest on ₹44400 at 5% per year for 2 years (in ₹)?
  8. 8.A town has 48000 people. The population grows by 5% every year. What will the population be after 3 years?
  9. 9.Find the compound interest on ₹5700 at 10% per year for 2 years, compounded every year (in ₹).
  10. 10.Find the compound interest on ₹31000 at 10% per year for 3 years, compounded every year (in ₹).
  11. 11.What is the difference between the compound interest and the simple interest on ₹16700 at 20% per year for 2 years (in ₹)?
  12. 12.Find the compound interest on ₹49100 at 10% per year for 2 years, compounded every year (in ₹).
  13. 13.What is the difference between the compound interest and the simple interest on ₹32800 at 5% per year for 2 years (in ₹)?
  14. 14.Find the compound interest on ₹39500 at 20% per year for 3 years, compounded every year (in ₹).
  15. 15.A town has 16000 people. The population grows by 10% every year. What will the population be after 3 years?
  16. 16.What amount will ₹27600 grow to in 1 year at 5% per year compound interest (in ₹)?
  17. 17.What is the difference between the compound interest and the simple interest on ₹41200 at 15% per year for 2 years (in ₹)?
  18. 18.What amount will ₹52500 grow to in 2 years at 4% per year compound interest (in ₹)?
  19. 19.A town has 45900 people. The population grows by 10% every year. What will the population be after 1 year?
  20. 20.A scooter is worth ₹25000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
  21. 21.Find the compound interest on ₹16300 at 15% per year for 1 year, compounded every year (in ₹).
  22. 22.What is the difference between the compound interest and the simple interest on ₹36800 at 15% per year for 2 years (in ₹)?
  23. 23.What amount will ₹32000 grow to in 2 years at 5% per year compound interest (in ₹)?
  24. 24.Find the compound interest on ₹40400 at 10% per year for 1 year, compounded every year (in ₹).
  25. 25.Find the compound interest on ₹52500 at 12% per year for 2 years, compounded every year (in ₹).
  26. 26.What is the difference between the compound interest and the simple interest on ₹42000 at 15% per year for 2 years (in ₹)?
  27. 27.What is the difference between the compound interest and the simple interest on ₹25000 at 4% per year for 2 years (in ₹)?
  28. 28.Find the compound interest on ₹17600 at 5% per year for 2 years, compounded every year (in ₹).
  29. 29.Find the compound interest on ₹42100 at 4% per year for 1 year, compounded every year (in ₹).
  30. 30.What is the difference between the compound interest and the simple interest on ₹20000 at 12% per year for 2 years (in ₹)?
  31. 31.A scooter is worth ₹47400. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
  32. 32.A town has 2700 people. The population grows by 15% every year. What will the population be after 1 year?
  33. 33.What amount will ₹4200 grow to in 2 years at 20% per year compound interest (in ₹)?
  34. 34.What is the difference between the compound interest and the simple interest on ₹11000 at 10% per year for 2 years (in ₹)?
  35. 35.What is the difference between the compound interest and the simple interest on ₹29200 at 15% per year for 2 years (in ₹)?
  36. 36.What amount will ₹51800 grow to in 1 year at 5% per year compound interest (in ₹)?
  37. 37.Find the compound interest on ₹28700 at 20% per year for 2 years, compounded every year (in ₹).
  38. 38.What is the difference between the compound interest and the simple interest on ₹22500 at 8% per year for 2 years (in ₹)?
  39. 39.Find the compound interest on ₹16000 at 10% per year for 3 years, compounded every year (in ₹).
  40. 40.What is the difference between the compound interest and the simple interest on ₹50800 at 10% per year for 2 years (in ₹)?

Answer key

  1. 580
  2. 91
  3. 36
  4. 24
  5. 364
  6. 696
  7. 111
  8. 55566
  9. 1197
  10. 10261
  11. 668
  12. 10311
  13. 82
  14. 28756
  15. 21296
  16. 28980
  17. 927
  18. 56784
  19. 50490
  20. 21160
  21. 2445
  22. 828
  23. 35280
  24. 4040
  25. 13356
  26. 945
  27. 40
  28. 1804
  29. 1684
  30. 288
  31. 42660
  32. 3105
  33. 6048
  34. 110
  35. 657
  36. 54390
  37. 12628
  38. 144
  39. 5296
  40. 508

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