Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.A town has 40000 people. The population grows by 5% every year. What will the population be after 3 years?
- 2.What amount will ₹5500 grow to in 2 years at 20% per year compound interest (in ₹)?
- 3.A scooter is worth ₹2500. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
- 4.A town has 24800 people. The population grows by 20% every year. What will the population be after 2 years?
- 5.What is the difference between the compound interest and the simple interest on ₹58000 at 5% per year for 2 years (in ₹)?
- 6.Find the compound interest on ₹32000 at 15% per year for 3 years, compounded every year (in ₹).
- 7.What is the difference between the compound interest and the simple interest on ₹31600 at 15% per year for 2 years (in ₹)?
- 8.What amount will ₹9600 grow to in 3 years at 25% per year compound interest (in ₹)?
- 9.Find the compound interest on ₹26000 at 10% per year for 3 years, compounded every year (in ₹).
- 10.Find the compound interest on ₹60000 at 4% per year for 2 years, compounded every year (in ₹).
- 11.Find the compound interest on ₹55300 at 25% per year for 1 year, compounded every year (in ₹).
- 12.A town has 50500 people. The population grows by 5% every year. What will the population be after 1 year?
- 13.What amount will ₹51200 grow to in 3 years at 25% per year compound interest (in ₹)?
- 14.Find the compound interest on ₹34000 at 10% per year for 3 years, compounded every year (in ₹).
- 15.Find the compound interest on ₹6000 at 20% per year for 1 year, compounded every year (in ₹).
- 16.A scooter is worth ₹48400. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
- 17.A scooter is worth ₹35000. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
- 18.A scooter is worth ₹22500. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
- 19.A scooter is worth ₹14700. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
- 20.What amount will ₹35200 grow to in 3 years at 25% per year compound interest (in ₹)?
- 21.What is the difference between the compound interest and the simple interest on ₹47500 at 12% per year for 2 years (in ₹)?
- 22.What amount will ₹27900 grow to in 1 year at 25% per year compound interest (in ₹)?
- 23.What amount will ₹56000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 24.Find the compound interest on ₹32000 at 25% per year for 3 years, compounded every year (in ₹).
- 25.Find the compound interest on ₹37000 at 10% per year for 3 years, compounded every year (in ₹).
- 26.A town has 7500 people. The population grows by 12% every year. What will the population be after 2 years?
- 27.What is the difference between the compound interest and the simple interest on ₹25000 at 12% per year for 2 years (in ₹)?
- 28.A scooter is worth ₹29000. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
- 29.What is the difference between the compound interest and the simple interest on ₹54000 at 20% per year for 2 years (in ₹)?
- 30.What amount will ₹4700 grow to in 1 year at 10% per year compound interest (in ₹)?
- 31.What amount will ₹52100 grow to in 1 year at 25% per year compound interest (in ₹)?
- 32.What is the difference between the compound interest and the simple interest on ₹42600 at 20% per year for 2 years (in ₹)?
- 33.A town has 26800 people. The population grows by 15% every year. What will the population be after 2 years?
- 34.Find the compound interest on ₹46000 at 15% per year for 2 years, compounded every year (in ₹).
- 35.What amount will ₹39300 grow to in 1 year at 8% per year compound interest (in ₹)?
- 36.Find the compound interest on ₹48000 at 5% per year for 3 years, compounded every year (in ₹).
- 37.What is the difference between the compound interest and the simple interest on ₹24000 at 25% per year for 2 years (in ₹)?
- 38.Find the compound interest on ₹12500 at 20% per year for 3 years, compounded every year (in ₹).
- 39.What amount will ₹32000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 40.What amount will ₹35600 grow to in 2 years at 20% per year compound interest (in ₹)?
Answer key
- 46305
- 7920
- 2304
- 35712
- 145
- 16668
- 711
- 18750
- 8606
- 4896
- 13825
- 53025
- 100000
- 11254
- 1200
- 43681
- 27104
- 20736
- 12495
- 68750
- 684
- 34875
- 64827
- 30500
- 12247
- 9408
- 360
- 14848
- 2160
- 5170
- 65125
- 1704
- 35443
- 14835
- 42444
- 7566
- 1500
- 9100
- 37044
- 51264
Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets