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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 264 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.Find the compound interest on ₹20800 at 25% per year for 3 years, compounded every year (in ₹).
  2. 2.Find the compound interest on ₹53600 at 20% per year for 1 year, compounded every year (in ₹).
  3. 3.What amount will ₹10000 grow to in 2 years at 4% per year compound interest (in ₹)?
  4. 4.What amount will ₹16000 grow to in 3 years at 5% per year compound interest (in ₹)?
  5. 5.A scooter is worth ₹28000. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
  6. 6.What is the difference between the compound interest and the simple interest on ₹2500 at 12% per year for 2 years (in ₹)?
  7. 7.What is the difference between the compound interest and the simple interest on ₹50900 at 10% per year for 2 years (in ₹)?
  8. 8.Find the compound interest on ₹49100 at 5% per year for 1 year, compounded every year (in ₹).
  9. 9.What is the difference between the compound interest and the simple interest on ₹59600 at 15% per year for 2 years (in ₹)?
  10. 10.A town has 42500 people. The population grows by 4% every year. What will the population be after 2 years?
  11. 11.Find the compound interest on ₹22800 at 15% per year for 2 years, compounded every year (in ₹).
  12. 12.What is the difference between the compound interest and the simple interest on ₹37500 at 8% per year for 2 years (in ₹)?
  13. 13.A town has 20000 people. The population grows by 10% every year. What will the population be after 1 year?
  14. 14.A town has 34000 people. The population grows by 5% every year. What will the population be after 2 years?
  15. 15.A town has 12500 people. The population grows by 8% every year. What will the population be after 2 years?
  16. 16.A scooter is worth ₹30500. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
  17. 17.Find the compound interest on ₹50400 at 10% per year for 2 years, compounded every year (in ₹).
  18. 18.What amount will ₹6700 grow to in 2 years at 20% per year compound interest (in ₹)?
  19. 19.What amount will ₹5000 grow to in 2 years at 12% per year compound interest (in ₹)?
  20. 20.A scooter is worth ₹49600. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
  21. 21.Find the compound interest on ₹3600 at 15% per year for 2 years, compounded every year (in ₹).
  22. 22.A town has 14000 people. The population grows by 15% every year. What will the population be after 2 years?
  23. 23.What is the difference between the compound interest and the simple interest on ₹12400 at 25% per year for 2 years (in ₹)?
  24. 24.What amount will ₹56000 grow to in 1 year at 12% per year compound interest (in ₹)?
  25. 25.What amount will ₹54800 grow to in 2 years at 15% per year compound interest (in ₹)?
  26. 26.Find the compound interest on ₹40000 at 4% per year for 2 years, compounded every year (in ₹).
  27. 27.What is the difference between the compound interest and the simple interest on ₹2500 at 8% per year for 2 years (in ₹)?
  28. 28.Find the compound interest on ₹17000 at 10% per year for 3 years, compounded every year (in ₹).
  29. 29.A town has 56600 people. The population grows by 20% every year. What will the population be after 1 year?
  30. 30.What amount will ₹20300 grow to in 1 year at 12% per year compound interest (in ₹)?
  31. 31.Find the compound interest on ₹28000 at 5% per year for 2 years, compounded every year (in ₹).
  32. 32.What is the difference between the compound interest and the simple interest on ₹45000 at 8% per year for 2 years (in ₹)?
  33. 33.Find the compound interest on ₹52600 at 8% per year for 1 year, compounded every year (in ₹).
  34. 34.What is the difference between the compound interest and the simple interest on ₹18000 at 15% per year for 2 years (in ₹)?
  35. 35.A scooter is worth ₹54300. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
  36. 36.A scooter is worth ₹50200. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
  37. 37.Find the compound interest on ₹45000 at 12% per year for 2 years, compounded every year (in ₹).
  38. 38.Find the compound interest on ₹51000 at 4% per year for 1 year, compounded every year (in ₹).
  39. 39.What amount will ₹53500 grow to in 1 year at 25% per year compound interest (in ₹)?
  40. 40.Find the compound interest on ₹14200 at 25% per year for 1 year, compounded every year (in ₹).

Answer key

  1. 19825
  2. 10720
  3. 10816
  4. 18522
  5. 25270
  6. 36
  7. 509
  8. 2455
  9. 1341
  10. 45968
  11. 7353
  12. 240
  13. 22000
  14. 37485
  15. 14580
  16. 27450
  17. 10584
  18. 9648
  19. 6272
  20. 37200
  21. 1161
  22. 18515
  23. 775
  24. 62720
  25. 72473
  26. 3264
  27. 16
  28. 5627
  29. 67920
  30. 22736
  31. 2870
  32. 288
  33. 4208
  34. 405
  35. 46155
  36. 47690
  37. 11448
  38. 2040
  39. 66875
  40. 3550

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