Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 271 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹27400 at 25% per year for 1 year, compounded every year (in ₹).
2. 2.Find the compound interest on ₹53000 at 20% per year for 3 years, compounded every year (in ₹).
3. 3.Find the compound interest on ₹24000 at 25% per year for 2 years, compounded every year (in ₹).
4. 4.A town has 7500 people. The population grows by 12% every year. What will the population be after 2 years?
5. 5.A town has 7200 people. The population grows by 25% every year. What will the population be after 2 years?
6. 6.Find the compound interest on ₹57100 at 15% per year for 1 year, compounded every year (in ₹).
7. 7.Find the compound interest on ₹16000 at 10% per year for 3 years, compounded every year (in ₹).
8. 8.What is the difference between the compound interest and the simple interest on ₹56700 at 20% per year for 2 years (in ₹)?
9. 9.What is the difference between the compound interest and the simple interest on ₹42800 at 15% per year for 2 years (in ₹)?
10. 10.Find the compound interest on ₹16600 at 15% per year for 1 year, compounded every year (in ₹).
11. 11.A scooter is worth ₹45000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
12. 12.Find the compound interest on ₹40500 at 25% per year for 1 year, compounded every year (in ₹).
13. 13.Find the compound interest on ₹56000 at 10% per year for 3 years, compounded every year (in ₹).
14. 14.A town has 32500 people. The population grows by 4% every year. What will the population be after 2 years?
15. 15.What is the difference between the compound interest and the simple interest on ₹47500 at 4% per year for 2 years (in ₹)?
16. 16.A town has 47000 people. The population grows by 10% every year. What will the population be after 3 years?
17. 17.A town has 32800 people. The population grows by 4% every year. What will the population be after 1 year?
18. 18.A scooter is worth ₹45000. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
19. 19.What amount will ₹12600 grow to in 1 year at 8% per year compound interest (in ₹)?
20. 20.What is the difference between the compound interest and the simple interest on ₹10000 at 25% per year for 2 years (in ₹)?
21. 21.What amount will ₹9600 grow to in 3 years at 25% per year compound interest (in ₹)?
22. 22.What is the difference between the compound interest and the simple interest on ₹50000 at 8% per year for 2 years (in ₹)?
23. 23.What is the difference between the compound interest and the simple interest on ₹2500 at 4% per year for 2 years (in ₹)?
24. 24.What is the difference between the compound interest and the simple interest on ₹22000 at 25% per year for 2 years (in ₹)?
25. 25.A scooter is worth ₹5600. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
26. 26.A town has 56000 people. The population grows by 15% every year. What will the population be after 3 years?
27. 27.Find the compound interest on ₹54200 at 20% per year for 1 year, compounded every year (in ₹).
28. 28.What is the difference between the compound interest and the simple interest on ₹19600 at 25% per year for 2 years (in ₹)?
29. 29.What amount will ₹40000 grow to in 3 years at 15% per year compound interest (in ₹)?
30. 30.Find the compound interest on ₹36800 at 25% per year for 3 years, compounded every year (in ₹).
31. 31.A town has 41600 people. The population grows by 15% every year. What will the population be after 2 years?
32. 32.What is the difference between the compound interest and the simple interest on ₹27500 at 8% per year for 2 years (in ₹)?
33. 33.Find the compound interest on ₹26600 at 10% per year for 2 years, compounded every year (in ₹).
34. 34.What is the difference between the compound interest and the simple interest on ₹4800 at 25% per year for 2 years (in ₹)?
35. 35.Find the compound interest on ₹54700 at 10% per year for 2 years, compounded every year (in ₹).
36. 36.What amount will ₹2500 grow to in 2 years at 8% per year compound interest (in ₹)?
37. 37.What is the difference between the compound interest and the simple interest on ₹22500 at 4% per year for 2 years (in ₹)?
38. 38.What amount will ₹10000 grow to in 2 years at 4% per year compound interest (in ₹)?
39. 39.What is the difference between the compound interest and the simple interest on ₹7500 at 8% per year for 2 years (in ₹)?
40. 40.A town has 22400 people. The population grows by 25% every year. What will the population be after 1 year?

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